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Additional practice set 2 · Challenge ← Back to lesson

Transformations of Graphs: Additional Practice (Set 2)

12 multiple-choice questions, progressively harder.

Additional practice set 2 · Challenge 0 / 12 answered
Question 1 of 12
  1. 1

    The rule y=f(2x6)y = f(2x - 6) transforms y=f(x)y = f(x). Factoring the input, which describes it?

    Answer choices for question 1
  2. 2

    The rule y=f(3x+12)y = f(3x + 12) transforms y=f(x)y = f(x). Factoring the input, which describes it?

    Answer choices for question 2
  3. 3

    The graphs y=2f(x)+3y = 2f(x) + 3 and y=2(f(x)+3)y = 2(f(x) + 3) differ. By what constant vertical amount is the second above the first?

    Answer choices for question 3
  4. 4

    For f(x)=x2+4f(x) = x^2 + 4, does the compression y=f(3x)y = f(3x) equal a vertical stretch cf(x)c\,f(x)?

    Answer choices for question 4
  5. 5

    'Stretch vertically by 22, then shift up 33' gives which rule from y=f(x)y = f(x)?

    Answer choices for question 5
  6. 6

    A function gg is odd on a domain symmetric about 00, and (4,7)(4, 7) is on its graph. Which point must also be on the graph?

    Answer choices for question 6
  7. 7

    The point (u,v)(u, v) lies on y=f(x)y = f(x). Under y=af(b(xh))+ky = a f(b(x - h)) + k with b0b \ne 0, where does it land?

    Answer choices for question 7
  8. 8

    The point (p,q)(p, q) is on y=f(x)y = f(x). Under y=af(b(xh))+ky = a f(b(x - h)) + k, where does it land?

    Answer choices for question 8
  9. 9

    Is f(x)=x3f(x) = x^3 even, odd, or neither, and what invariance does that give its graph?

    Answer choices for question 9
  10. 10

    Reflect y=f(x)y = f(x) across the xx-axis, then shift up 22. The point (5,4)(5, 4) on ff lands where?

    Answer choices for question 10
  11. 11

    With f(x)=x2f(x) = x^2, which statement about transforming y=f(x)y = f(x) into y=4x2y = 4x^2 is TRUE?

    Answer choices for question 11
  12. 12

    The point (2,5)(-2, 5) is on y=f(x)y = f(x). Which point must lie on y=f(x)y = f(-x)?

    Answer choices for question 12