12 multiple-choice questions, progressively harder.
For AAA at (−6,1)(-6,1)(−6,1) and BBB at (2,7)(2,7)(2,7), find the distance from AAA to the midpoint of ABABAB.
Solution
Correct answer: C
First find the whole length.
The midpoint of ABABAB is (−3/2,2)(-3/2,2)(−3/2,2), and B=(4,−3)B=(4,-3)B=(4,−3). Find AAA.
Correct answer: A
The coordinate sums are twice the midpoint coordinates.
For AAA at (−5,2)(-5,2)(−5,2) and BBB at (1,−2)(1,-2)(1,−2), what is the exact length ABABAB in simplest radical form?
Correct answer: D
The signed changes are 6 and −4-4−4.
A is at (−2,1)(-2,1)(−2,1). Point B is at (t,4)(t,4)(t,4), and ABABAB is 5 units. Which list gives all possible values of ttt?
Correct answer: B
The vertical gap is 3.
The horizontal change is either −4-4−4 or 4. Subtracting 2 gives −6-6−6 or 2.
The midpoint of ABABAB is (2,3)(2,3)(2,3). Both endpoints have x-coordinate 2, and AAA has y-coordinate −4-4−4. What is ABABAB?
A and M are on the same vertical line.
Segments ABABAB and CDCDCD have endpoints AAA at (−4,−2)(-4,-2)(−4,−2), BBB at (2,4)(2,4)(2,4), CCC at (−2,4)(-2,4)(−2,4), and DDD at (4,−2)(4,-2)(4,−2). How are their midpoints positioned?
Average each pair of endpoints.
The heights agree, and the x-coordinate increases from −1-1−1 to 1. Thus the second midpoint is 2 units right of the first.
For AAA at (−1,0)(-1,0)(−1,0), BBB at (3,2)(3,2)(3,2), and PPP at (1,1)(1,1)(1,1), which statement confirms that P is the midpoint of AB?
The average of the x-coordinates is 1, and the average of the y-coordinates is 1.
Halving both changes places P on AB at half its length.
Triangle ABC has squared side lengths 20 for AB, 45 for AC, and 29 for BC. Under the order ABC to DEF, which data establish congruence?
DE2=20DE^2=20DE2=20
DF2=29DF^2=29DF2=29
EF2=45EF^2=45EF2=45
DF2=45DF^2=45DF2=45
EF2=29EF^2=29EF2=29
DE2=45DE^2=45DE2=45
DF2=20DF^2=20DF2=20
EF2=30EF^2=30EF2=30
The order pairs A with D, B with E, and C with F. Thus AB pairs with DE, AC with DF, and BC with EF.
All three must match these particular pairs.
A straight cable joins map points (−2,−1)(-2,-1)(−2,−1) and (4,4)(4,4)(4,4). Each coordinate unit represents 3 meters. What exact cable length is needed?
The coordinate gaps are 6 and 5, so the length in map units is
Multiply a length by the scale of 3 meters per unit, giving 3613\sqrt{61}361 meters.
A segment has endpoints (−5,3)(-5,3)(−5,3) and (1,−1)(1,-1)(1,−1). The second endpoint moves to (5,−3)(5,-3)(5,−3) while the first stays fixed. What is the new midpoint?
Average the fixed endpoint and the new endpoint, not the old endpoint.
For AAA at (−3,2)(-3,2)(−3,2), BBB at (4,6)(4,6)(4,6), and CCC at (5,−1)(5,-1)(5,−1), which segment is longer, AB or AC?
Compare the squared lengths, since both lengths are nonnegative.
The larger square belongs to AC.
With AAA at (1,−3)(1,-3)(1,−3) and BBB at (t,2)(t,2)(t,2), for which prescribed length is there exactly one possible endpoint B?
The vertical gap is fixed at 5.
At length 5, the horizontal square is zero, so t=1t=1t=1 only. A shorter length is impossible, and a longer length gives two horizontal positions.
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