12 multiple-choice questions, progressively harder.
Which description defines a circular segment?
Solution
Correct answer: B
A chord closes the selected arc. Two radii instead give a sector, and concentric circles give an annulus.
A sector has radius 666 cm and central angle 40∘40^\circ40∘. What is its exact area?
Correct answer: D
Take the angle’s fraction of the full disk area.
A sector has radius 333 cm and central angle 2/32/32/3 radian. What is its area?
Correct answer: A
The angle is in radians, so use half the radius squared times the angle.
A sector has radius 555 cm and central angle 108∘108^\circ108∘. What is its complete perimeter?
Correct answer: C
First find the selected arc, then include both radii.
A minor circular segment is cut off by a 90∘90^\circ90∘ central angle in a circle of radius 222 cm. What is its area?
The quarter-disk area is reduced by the triangle between the radii. Those radii are perpendicular legs.
An annulus has outer radius 6 cm and inner radius 2 cm. What is its exact area?
Subtract the inner disk from the outer disk.
An annulus has outer radius 9 cm and inner radius 2 cm. What is the total length of its two boundary circles?
Both circular edges touch the ring. Add their lengths.
The selected major sector has radius 666 cm and angle 210∘210^\circ210∘. What is its area?
Use the stated major angle rather than its complementary smaller angle.
A sector has radius 444 cm and angle π/4\pi/4π/4 radians. What is its area?
Substitute the radian measure into the radian area formula.
Which pieces make up the complete boundary of a proper sector?
Following the sector from one endpoint goes along a radius to the center, along the other radius to the second endpoint, and back along the selected arc. A chord belongs to a circular segment instead.
A minor sector is partitioned into a triangle of area 17 cm217\text{ cm}^217 cm2 and a circular segment of area 11 cm211\text{ cm}^211 cm2. What is the sector area?
The two regions have disjoint interiors and together fill the sector, so add their areas.
An annulus has outer radius RRR and inner radius rrr, with 0<r<R0<r<R0<r<R. Which expression gives its area using the ring's width as a factor?
The area subtracts the disk areas. Factor the difference of their squared radii.
Reset this practice set?
This clears every answer you have given and starts the set again from question 1.