12 multiple-choice questions, progressively harder.
Diameter VDVDVD lies inside ∠AVB\angle AVB∠AVB. On the intercepted arc, ADADAD measures 42∘42^\circ42∘ and DBDBDB measures 118∘118^\circ118∘. Find m∠AVBm\angle AVBm∠AVB.
Solution
Correct answer: C
Add the intercepted arc pieces, then halve.
The angle is 80 degrees.
Diameter VDVDVD is outside ∠AVB\angle AVB∠AVB. Along the arc away from VVV, the order is D,A,BD,A,BD,A,B. Arc DBDBDB measures 162∘162^\circ162∘ and DADADA measures 48∘48^\circ48∘. Find m∠AVBm\angle AVBm∠AVB.
Correct answer: A
Subtract the smaller arc from the larger, then halve the remaining arc AB.
The angle is 57 degrees.
VAVAVA is a diameter through center OOO, and m∠VOB=108∘m\angle VOB=108^\circm∠VOB=108∘. Find m∠AVBm\angle AVBm∠AVB.
Correct answer: D
The equal-radius triangle has two equal base angles.
The angle is 36 degrees.
P,QP,QP,Q lie on the same open arc between A,BA,BA,B. The angles APBAPBAPB and AQBAQBAQB measure (2x+13)∘(2x+13)^\circ(2x+13)∘ and (4x−17)∘(4x-17)^\circ(4x−17)∘. Find xxx.
Correct answer: B
The angles intercept the same arc, so their measures are equal.
P,RP,RP,R lie on opposite open arcs between A,BA,BA,B. Their inscribed angles measure (3x+4)∘(3x+4)^\circ(3x+4)∘ and (5x+8)∘(5x+8)^\circ(5x+8)∘. Find xxx.
The angles intercept the two arcs between the same endpoints, so they are supplementary.
Triangle ACBACBACB is inscribed in a circle with diameter ABABAB. Given m∠CAB=29∘m\angle CAB=29^\circm∠CAB=29∘, find m∠ABCm\angle ABCm∠ABC.
The diameter gives a right angle at C. Use the triangle sum.
The angle is 61 degrees.
Triangle ABCABCABC is inscribed in a circle. Its angle at AAA is 24∘24^\circ24∘, and its angle at BBB is 66∘66^\circ66∘. Which segment must be a diameter?
The two given angles total 90 degrees, making the angle at C right.
This is 90 degrees, so the converse makes AB a diameter.
Minor arc TATATA measures 154∘154^\circ154∘. Ray TSTSTS is tangent at TTT on the opposite side of line OTOTOT from AAA. Find m∠STAm\angle STAm∠STA.
The opposite ray selects the major arc of 206 degrees.
The angle is 103 degrees.
Ray TRTRTR is tangent at TTT on the same side of line OTOTOT as AAA. Given m∠RTA=46∘m\angle RTA=46^\circm∠RTA=46∘, find the measure of minor arc TATATA.
The ray selects the minor arc, so double the tangent-chord angle.
The minor arc measures 92 degrees.
A tangent-chord angle measures 127∘127^\circ127∘. What are the measure and type of its intercepted arc?
Double the tangent-chord angle.
This exceeds 180 degrees, so it is major. The other arc measures 106 degrees.
Diameter VDVDVD lies inside ∠AVB\angle AVB∠AVB, with DDD on its intercepted arc. Let aaa be the measure of arc ADBADBADB, bbb the measure of arc ADADAD, and ccc the measure of arc DBDBDB. Which equation correctly assembles the arc?
Arc AD and arc DB have disjoint interiors and join at D to make arc ADB. Their measures add.
Points A,P,B,QA,P,B,QA,P,B,Q occur in order around a circle. Arc APBAPBAPB measures (3x+24)∘(3x+24)^\circ(3x+24)∘, and arc AQBAQBAQB measures (5x+16)∘(5x+16)^\circ(5x+16)∘. Find m∠APBm\angle APBm∠APB.
The two arcs make a full circle.
The angle at P excludes P, so use arc AQB, of 216 degrees.
The angle is 108 degrees.
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