12 multiple-choice questions, progressively harder.
Diameter VDVDVD is outside ∠AVB\angle AVB∠AVB, with ray VAVAVA between VDVDVD and VBVBVB. Angle DVBDVBDVB measures 71∘71^\circ71∘, and DVADVADVA measures 26∘26^\circ26∘. Find arc ABABAB excluding VVV.
Solution
Correct answer: D
Subtract to obtain the inscribed angle of 45 degrees, then double to obtain its arc.
The arc measures 90 degrees.
Diameter VDVDVD lies inside ∠AVB\angle AVB∠AVB. Angles AVDAVDAVD and DVBDVBDVB measure (x+7)∘(x+7)^\circ(x+7)∘ and (2x−4)∘(2x-4)^\circ(2x−4)∘. The intercepted arc ADBADBADB measures 174∘174^\circ174∘. Find xxx.
Correct answer: B
The whole angle is half the arc, or 87 degrees. Add its parts.
VAVAVA is a diameter with center OOO. In triangle VOBVOBVOB, the angle at OOO measures (4x+12)∘(4x+12)^\circ(4x+12)∘, and the angle at BBB measures (x+6)∘(x+6)^\circ(x+6)∘. Find arc BABABA excluding VVV.
Correct answer: C
The radii make the two base angles equal.
The central angle VOB is 116 degrees. Subtract from the straight angle along the diameter.
The requested arc measures 64 degrees.
Point QQQ lies on major arc ABABAB, and RRR lies on minor arc ABABAB. Given m∠AQB=82∘m\angle AQB=82^\circm∠AQB=82∘ and arc ARARAR of 76∘76^\circ76∘, find arc RBRBRB along minor arc ABABAB.
Correct answer: A
The angle at Q excludes the minor arc AB, so that full arc measures 164 degrees. Since R lies on it, subtract arc AR.
Arc RB measures 88 degrees.
An inscribed angle measures (4x+30)∘(4x+30)^\circ(4x+30)∘. Its intercepted major arc measures (7x+80)∘(7x+80)^\circ(7x+80)∘. Find xxx.
The intercepted arc is twice the angle, including when it is major.
This gives an angle of 110 degrees and a major arc of 220 degrees, both valid.
Triangle ABCABCABC is inscribed in a circle and has a right angle at CCC. Its angles at A,BA,BA,B measure (4x+8)∘(4x+8)^\circ(4x+8)∘ and (6x+2)∘(6x+2)^\circ(6x+2)∘. Find arc ACACAC excluding BBB.
The other two angles total 90 degrees.
The angle at B is 50 degrees, so double it for its intercepted arc.
The arc measures 100 degrees.
Opposite tangent rays TR,TSTR,TSTR,TS form angles with chord TATATA of (3x+11)∘(3x+11)^\circ(3x+11)∘ and (5x+9)∘(5x+9)^\circ(5x+9)∘, respectively. Ray TRTRTR lies on the same side of line OTOTOT as AAA. Find minor arc TATATA.
The two tangent rays form a straight angle.
Ray TR selects the minor arc. Its angle is 71 degrees.
The minor arc measures 142 degrees.
Ray TSTSTS is tangent at TTT on the opposite side of line OTOTOT from AAA. Given m∠STA=94∘m\angle STA=94^\circm∠STA=94∘, point BBB on major arc TATATA, and m∠TAB=31∘m\angle TAB=31^\circm∠TAB=31∘, find m∠ATBm\angle ATBm∠ATB.
The tangent ray selects the major arc of 188 degrees, leaving a minor arc of 172 degrees. Vertex B selects that minor arc, so its inscribed angle is 86 degrees. Now use the triangle sum.
The angle at T measures 63 degrees.
PPP lies on major arc ABABAB, and QQQ on minor arc ABABAB. Given m∠APB=62∘m\angle APB=62^\circm∠APB=62∘, what is the measure of arc APBAPBAPB containing PPP?
The angle at P intercepts the other arc, of 124 degrees. Subtract it from a full circle.
The arc containing P measures 236 degrees.
Diameter VDVDVD is inside ∠AVB\angle AVB∠AVB. Angle AVBAVBAVB measures 81∘81^\circ81∘, and arc ADADAD measures 68∘68^\circ68∘. Find arc DBDBDB on intercepted arc ADBADBADB.
Double the whole angle to get the full intercepted arc, then subtract AD.
Arc DB measures 94 degrees.
Diameter VDVDVD lies outside ∠AVB\angle AVB∠AVB. The arc order away from VVV is D,A,BD,A,BD,A,B. Given m∠AVB=34∘m\angle AVB=34^\circm∠AVB=34∘ and arc DBDBDB of 158∘158^\circ158∘, find arc DADADA.
Angle AVB intercepts arc AB of 68 degrees. Remove that arc from DB.
Arc DA measures 90 degrees.
At AAA, tangent ray ASASAS lies on the opposite side of line OAOAOA from BBB, and m∠SAB=114∘m\angle SAB=114^\circm∠SAB=114∘. Point PPP lies on major arc ABABAB and QQQ on minor arc ABABAB. Which pair is correct?
m∠APB=66∘m\angle APB=66^\circm∠APB=66∘
m∠AQB=66∘m\angle AQB=66^\circm∠AQB=66∘
m∠AQB=114∘m\angle AQB=114^\circm∠AQB=114∘
m∠APB=114∘m\angle APB=114^\circm∠APB=114∘
The tangent ray selects the major arc of 228 degrees; the minor arc measures 132 degrees. P excludes the minor arc; Q excludes the major arc.
Reset this practice set?
This clears every answer you have given and starts the set again from question 1.