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Using Congruence in Proofs: Practice

12 multiple-choice questions, progressively harder.

Level 2 · Intermediate 0 / 12 answered
Question 1 of 12
  1. 1

    A proof gives

    △KLM≅△RST.\triangle KLM\cong\triangle RST.

    If

    KL=2x+7RS=25\begin{aligned}KL&=2x+7 \\ RS&=25\end{aligned}

    find xx.

    Answer choices for question 1
  2. 2

    The ordered congruence is:

    △ABC≅△EFD\triangle ABC\cong\triangle EFD

    The given angle measure is:

    m∠F=68∘m\angle F=68^\circ

    Find m∠Bm\angle B.

    Answer choices for question 2
  3. 3

    A four-sided figure JKLMJKLM, with every corner pointing outward, has

    JK=JMKL=ML.\begin{aligned}JK&=JM \\ KL&=ML\end{aligned}.

    Which auxiliary segment creates a pair of triangles that can be matched immediately by SSS?

    Read the given side pairsFour-sided figure JKLM has every corner pointing outward. The two given adjacent side pairs have matching tick marks. No segment between opposite corners is drawn.JKLM
    Answer choices for question 3
  4. 4

    After proving

    △JKL≅△JML\begin{aligned}\triangle JKL&\cong\triangle JML\end{aligned}

    which equality is a valid CPCTC conclusion?

    Answer choices for question 4
  5. 5

    Points A,B,DA,B,D lie on one ray in that order, and A,C,EA,C,E lie on a second ray in that order. The two rays form an opening strictly between 0∘0^\circ and 180∘180^\circ. Given

    AB=ACAD=AE\begin{aligned}AB&=AC \\ AD&=AE\end{aligned}

    which ordered triangle pair is matched by SAS using the shared opening at AA?

    Read the given point orderThe named points lie on the two rays in their stated orders. The segments whose lengths appear in the problem are drawn without equality markings.ABDCE
    Answer choices for question 5
  6. 6

    In the angle-copy construction,

    OA=OBOB=PDPD=PEPE=11 cmAB=DEDE=13 cm.\begin{aligned}OA&=OB \\ OB&=PD \\ PD&=PE \\ PE&=11\text{ cm} \\ AB&=DE \\ DE&=13\text{ cm}\end{aligned}.

    Which pair of triangles is matched in the order needed to compare the angles at OO and PP?

    Locate the source and transferred marksThe source and target triangles have the given common-radius markings and matching transferred-chord markings. No angle equality is marked.OABPDE
    Answer choices for question 6
  7. 7

    Triangles ABCABC and DBCDBC share side BCBC and have matching angles at BB and CC. If

    BD=37 m\begin{aligned}BD&=37\text{ m}\end{aligned}

    what is ABAB in the exact model?

    Read the common baseline and given anglesTriangles ABC and DBC are on opposite sides of their common baseline. Matching arcs mark only the given endpoint-angle pairs.ABCD37 m
    Answer choices for question 7
  8. 8

    A proof establishes

    △PQR≅△XYZ.\begin{aligned}\triangle PQR&\cong\triangle XYZ\end{aligned}.

    The corresponding lengths are

    PR=2t+1XZ=5t−20.\begin{aligned}PR&=2t+1 \\ XZ&=5t-20\end{aligned}.

    Find tt.

    Answer choices for question 8
  9. 9

    Two triangle drawings overlap. What must a separated redraw preserve for use in the proof?

    Answer choices for question 9
  10. 10

    Lines ACAC and BDBD cross at OO, with

    OA=OCOB=OD.\begin{aligned}OA&=OC \\ OB&=OD\end{aligned}.

    Which fact supplies the included angle pair for SAS in △AOB\triangle AOB and △COD\triangle COD?

    Read the crossing and the given lengthsO is between A and C on one line and between B and D on the other. The equal length pairs are marked, while the crossing angles are not assumed right.ABCDO
    Answer choices for question 10
  11. 11

    A two-stage congruence argument has established one pair of triangles and then, by CPCTC, a side pair needed for a second comparison. What must happen before CPCTC can be used on the second pair?

    Answer choices for question 11
  12. 12

    In an angle copy, which equality would be an invalid reason for SAS if it is the very result being proved?

    Locate the source and transferred marksThe source and target triangles have the given common-radius markings and matching transferred-chord markings. No angle equality is marked.OABPDE
    Answer choices for question 12