12 multiple-choice questions, progressively harder.
A proof gives
△KLM≅△RST.\triangle KLM\cong\triangle RST.△KLM≅△RST.
If
find xxx.
Solution
Correct answer: C
CPCTC gives equality of KLKLKL and RSRSRS:
Subtract 7 and divide by 2, obtaining
The ordered congruence is:
△ABC≅△EFD\triangle ABC\cong\triangle EFD△ABC≅△EFD
The given angle measure is:
m∠F=68∘m\angle F=68^\circm∠F=68∘
Find m∠Bm\angle Bm∠B.
Correct answer: A
The second vertices correspond, so BBB matches FFF.
By CPCTC, their angle measures are equal:
A four-sided figure JKLMJKLMJKLM, with every corner pointing outward, has
Which auxiliary segment creates a pair of triangles that can be matched immediately by SSS?
Correct answer: B
Drawing JLJLJL creates △JKL\triangle JKL△JKL and △JML\triangle JML△JML.
The givens supply two side pairs; the third is
SSS establishes their congruence.
After proving
which equality is a valid CPCTC conclusion?
Correct answer: D
The correspondence fixes JJJ and LLL and sends KKK to MMM.
Thus the angle mapping is
The other choices do not pair corresponding parts.
Points A,B,DA,B,DA,B,D lie on one ray in that order, and A,C,EA,C,EA,C,E lie on a second ray in that order. The two rays form an opening strictly between 0∘0^\circ0∘ and 180∘180^\circ180∘. Given
which ordered triangle pair is matched by SAS using the shared opening at AAA?
Use the short pair
and long pair
Their included opening is the same at AAA.
The correct order is
The collinear triples ABDABDABD and ACEACEACE are not triangles.
In the angle-copy construction,
Which pair of triangles is matched in the order needed to compare the angles at OOO and PPP?
The two equal radii meet at OOO in the source and PPP in the target.
The chord ABABAB corresponds to DEDEDE, giving
This matches all three side pairs.
Triangles ABCABCABC and DBCDBCDBC share side BCBCBC and have matching angles at BBB and CCC. If
what is ABABAB in the exact model?
ASA gives
By CPCTC the matching side lengths satisfy
A proof establishes
The corresponding lengths are
Find ttt.
The corresponding side equality gives
Rearranging gives
hence
Both lengths are then 15.
Two triangle drawings overlap. What must a separated redraw preserve for use in the proof?
A redraw may move copies for clarity, but it must retain the same mathematical data.
A known side pair such as
remains the same pair; redrawing does not create new givens.
Lines ACACAC and BDBDBD cross at OOO, with
Which fact supplies the included angle pair for SAS in △AOB\triangle AOB△AOB and △COD\triangle COD△COD?
The rays OAOAOA and OCOCOC are opposite, as are OBOBOB and ODODOD.
Thus
by the vertical-angle theorem.
These are the included angles between the given side pairs.
A two-stage congruence argument has established one pair of triangles and then, by CPCTC, a side pair needed for a second comparison. What must happen before CPCTC can be used on the second pair?
The first match supplies only its own corresponding parts.
The second pair needs a criterion establishing its own statement, such as
Only then can CPCTC compare that pair’s remaining parts.
In an angle copy, which equality would be an invalid reason for SAS if it is the very result being proved?
The desired angle equality is the conclusion, not an initial datum.
Use the three transferred side pairs for SSS first. CPCTC then gives the corresponding angle equality:
Reset this practice set?
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