12 multiple-choice questions, progressively harder.
On a coordinate grid, the given circle is centered at O=(1,7)O=(1,7)O=(1,7). The external point is P=(9,13)P=(9,13)P=(9,13). Where is the center of the auxiliary circle?
Solution
Correct answer: D
The auxiliary center is the midpoint of OP. Average the horizontal coordinates and then the vertical coordinates.
The near point AAA of the given solid circle is inside the dashed circle. The opposite point BBB is outside. Which argument shows there are at least two crossings?
Correct answer: A
The points A and B are on opposite sides of the dashed circle's boundary, whose radius is MO.
Each arc of the solid circle from A to B must cross the dashed circle on its way from inside to outside. The two arcs have no points in common between A and B.
A tangent from PPP to the given circle touches at TTT. The original radius is 202020 cm and PTPTPT is 212121 cm. What compass opening draws the auxiliary circle?
Correct answer: B
The right angle is at T, so OP is the hypotenuse.
The compass opening is half of OP, or 14.514.514.5 cm.
The given circle has positive radius. Point PPP is 444 mm closer to OOO than a point on the circle is. What happens to any line through PPP?
Correct answer: C
The distances from O to all points on the circle are equal to the radius rrr. Measuring in millimeters,
P is inside the circle. From P the line crosses the boundary once in each direction, so it is a secant.
The midpoint MMM is correctly marked, but the compass is opened to less than MOMOMO. Which property of the intended auxiliary circle fails?
The midpoint still makes the two distances equal.
With the smaller opening, both endpoints are outside the auxiliary circle.
Point XXX is on the auxiliary circle with diameter OPOPOP and differs from both endpoints. Its distance from OOO is less than the given circle's radius. What can you conclude about line PXPXPX at XXX?
Since X is on the auxiliary circle with diameter OP, the semicircle theorem gives
The shorter distance from O puts X inside the given circle, so it cannot be a contact point.
The original circle has radius 242424 mm. The outside point PPP gives an auxiliary radius of 161616 mm. The ray from OOO through PPP crosses the original circle at AAA. What is the distance APAPAP?
The auxiliary radius is half the length of OP. Since A is between O and P, subtract the original radius from that diameter.
Point XXX lies on a circle of radius 999 cm centered at OOO. The lengths of PXPXPX and OPOPOP are 131313 cm and 161616 cm. Is line PXPXPX tangent at XXX?
If line PX were tangent at X, triangle OXP would be right at X.
The numbers differ, so OX and PX are not perpendicular.
The diagram shows a tangent from PPP to the given circle at T1T_1T1. The second tangent has yet to be drawn. What stays fixed when you reflect the drawing in OPOPOP to find it?
Let ddd be the distance to the mirror line OP. The endpoints both lie on that line.
They stay fixed. The point T₁ lies off the mirror line and moves to the other side.
The arc intersections UUU and VVV are visible, but the midpoint mark has been erased. Which construction recovers it directly?
U and V are each equally far from O and P. Draw the perpendicular bisector UV, then mark its crossing M with OP. The bisector gives
Suppose two distinct circles share three different points. Why would this contradict the uniqueness used in the tangent construction?
Three distinct points on a circle are not collinear. If the circle centers were O and M, both would have to lie at the unique intersection of the triangle's perpendicular bisectors.
The distance from that common center to a shared point would also fix the same radius, contradicting distinct circles.
The distance OPOPOP is 313131 cm. Point T1T_1T1 has already been constructed as a contact point. Why does moving PPP to another point that is also 313131 cm from OOO leave the auxiliary radius unchanged?
The auxiliary radius depends on the length of OP. For the original point and the new one, it is
Changing the direction of OP does not change its length.
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