12 multiple-choice questions, progressively harder.
Two triangles have matching side lengths 9,10,149, 10, 149,10,14 and 13.5,15,2113.5, 15, 2113.5,15,21. Which conclusion follows?
Solution
Correct answer: D
Compare all three side pairs in the same direction.
Triangle ABCABCABC has
Triangle DEFDEFDEF has
Which ordered similarity is justified by SSS?
Correct answer: B
Pair equal lengths: AB with FD, BC with DE, and CA with EF. Their shared endpoints give A to F, B to D, and C to E. The common factor is one.
Sides
meet at a 53∘53^\circ53∘ angle. Sides
meet at the same angle. If BC=tBC=tBC=t, what is EFEFEF?
Correct answer: C
The two side ratios agree, and their included angles are equal, so SAS establishes the stated matching.
The ratios DE/ABDE/ABDE/AB and EF/BCEF/BCEF/BC agree. Which added angle equality would establish SAS similarity for the order ABCABCABC to DEFDEFDEF?
Correct answer: A
AB and BC meet at B, while DE and EF meet at E. The needed included angles are therefore ABC and DEF.
For the correspondence ABCABCABC to DEFDEFDEF, the side lengths are
What value of xxx makes SSS similarity hold?
The first two matched side pairs fix the factor at 1.5. Apply that factor to the third side.
x=1.5⋅11,=16.5.\begin{aligned}x&=1.5\cdot 11,\\&=16.5.\end{aligned}x=1.5⋅11,=16.5.
SAS establishes similarity with factor 85\frac 8558 from triangle KLMKLMKLM to triangle PQRPQRPQR. What is the factor from PQRPQRPQR back to KLMKLMKLM?
Reverse the direction of every corresponding length ratio.
Both within-triangle ratios AB/BCAB/BCAB/BC and DE/EFDE/EFDE/EF equal 3/43/43/4, and ∠ABC≅∠DEF\angle ABC\cong\angle DEF∠ABC≅∠DEF. Which conclusion is correct?
Equality of the within-triangle side ratios can be rearranged into equality of the corresponding between-triangle ratios.
The included angles at B and E match, so SAS applies. The value 3/4 compares two sides within each triangle, not an image length with its preimage.
Triangles satisfy ∠A≅∠D\angle A\cong\angle D∠A≅∠D, with
What value of xxx allows SAS similarity in the stated order?
The included angles match. The ratio from AC to DF is 1.5, so AB must scale by 1.5 too.
A SAS similarity has side factor 0.80.80.8 and an included angle measuring 44∘44^\circ44∘ in the original triangle. What is the corresponding image angle?
A dilation scales lengths and preserves angles. The corresponding image angle still measures 44 degrees; the factor 0.8 is not applied to its measure.
A side-ratio test fails for one proposed vertex matching. What can safely be concluded before other matchings have been considered?
A failure for one naming order rejects that order. To reject similarity altogether, one must rule out all possible correspondences, often by comparing sorted side lengths.
In triangle ABCABCABC, DDD lies between AAA and BBB and EEE lies between AAA and CCC. If
, which criterion establishes △ADE∼△ABC\triangle ADE\sim\triangle ABC△ADE∼△ABC without a parallelism assumption?
The two pairs of sides around the shared angle have the same small-to-large ratio.
The rays forming the angle at A are the same in both triangles. Therefore the shared angle is included for those two side pairs, and SAS applies.
Points A,O,CA,O,CA,O,C and B,O,DB,O,DB,O,D are collinear in those orders. If
, why is △AOB∼△COD\triangle AOB\sim\triangle COD△AOB∼△COD justified without assuming AB∥CDAB\parallel CDAB∥CD?
The corresponding sides adjacent to O have the same factor, and the included angles at O are vertical.
The equal included vertical angles complete SAS similarity.
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