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SSS and SAS Similarity: Practice

12 multiple-choice questions, progressively harder.

Level 2 · Intermediate 0 / 12 answered
Question 1 of 12
  1. 1

    Two triangles have matching side lengths 9,10,149, 10, 14 and 13.5,15,2113.5, 15, 21. Which conclusion follows?

    Answer choices for question 1
  2. 2

    Triangle ABCABC has

    AB=8BC=10CA=12.\begin{aligned}AB&=8\\BC&=10\\CA&=12.\end{aligned}

    Triangle DEFDEF has

    DE=10EF=12FD=8.\begin{aligned}DE&=10\\EF&=12\\FD&=8.\end{aligned}

    Which ordered similarity is justified by SSS?

    Answer choices for question 2
  3. 3

    Sides

    AB=6AC=10\begin{aligned}AB&=6\\AC&=10\end{aligned}

    meet at a 53∘53^\circ angle. Sides

    DE=9DF=15\begin{aligned}DE&=9\\DF&=15\end{aligned}

    meet at the same angle. If BC=tBC=t, what is EFEF?

    Match the same sides in both trianglesThe first solid blue triangle is ABC and the second dashed red triangle is DEF. Side labels follow the same order: first-second, second-third, third-first. The marked corresponding angle is at A and D. The diagram only locates the given equal included angles and side names. It deliberately does not encode the requested relation between EF and t as a measurable drawing scale.ABC6t10DEF9EF15Schematic, not to scale.
    Answer choices for question 3
  4. 4

    The ratios DE/ABDE/AB and EF/BCEF/BC agree. Which added angle equality would establish SAS similarity for the order ABCABC to DEFDEF?

    Match the same sides in both trianglesThe first solid blue triangle is ABC and the second dashed red triangle is DEF. Side labels follow the same order: first-second, second-third, third-first. The drawing is schematic; use the labels rather than measurements.ABCABBCACDEFDEEFDFSchematic, not to scale.
    Answer choices for question 4
  5. 5

    For the correspondence ABCABC to DEFDEF, the side lengths are

    AB=6BC=8CA=11DE=9EF=12FD=x.\begin{aligned}AB&=6\\BC&=8\\CA&=11\\DE&=9\\EF&=12\\FD&=x.\end{aligned}

    What value of xx makes SSS similarity hold?

    Answer choices for question 5
  6. 6

    SAS establishes similarity with factor 85\frac 85 from triangle KLMKLM to triangle PQRPQR. What is the factor from PQRPQR back to KLMKLM?

    Answer choices for question 6
  7. 7

    Both within-triangle ratios AB/BCAB/BC and DE/EFDE/EF equal 3/43/4, and ∠ABC≅∠DEF\angle ABC\cong\angle DEF. Which conclusion is correct?

    Answer choices for question 7
  8. 8

    Triangles satisfy ∠A≅∠D\angle A\cong\angle D, with

    AB=x+4AC=10DE=18DF=15.\begin{aligned}AB&=x+4\\AC&=10\\DE&=18\\DF&=15.\end{aligned}

    What value of xx allows SAS similarity in the stated order?

    Match the same sides in both trianglesThe first solid blue triangle is ABC and the second dashed red triangle is DEF. Side labels follow the same order: first-second, second-third, third-first. The marked corresponding angle is at A and D. The drawing is schematic; use the labels rather than measurements.ABCx + 4BC10DEF18EF15Schematic, not to scale.
    Answer choices for question 8
  9. 9

    A SAS similarity has side factor 0.80.8 and an included angle measuring 44∘44^\circ in the original triangle. What is the corresponding image angle?

    Answer choices for question 9
  10. 10

    A side-ratio test fails for one proposed vertex matching. What can safely be concluded before other matchings have been considered?

    Answer choices for question 10
  11. 11

    In triangle ABCABC, DD lies between AA and BB and EE lies between AA and CC. If

    AD=6AB=14AE=9AC=21\begin{aligned}AD&=6\\AB&=14\\AE&=9\\AC&=21\end{aligned}

    , which criterion establishes △ADE∼△ABC\triangle ADE\sim\triangle ABC without a parallelism assumption?

    Two side ratios around the shared angleD lies between A and B, E between A and C. AD is 6, AB is 14, AE is 9 and AC is 21. No parallelism is marked or assumed. The triangles share their included angle at A.ABCDE614921Schematic, not to scale.
    Answer choices for question 11
  12. 12

    Points A,O,CA,O,C and B,O,DB,O,D are collinear in those orders. If

    AO=5CO=12BO=7DO=16.8\begin{aligned}AO&=5\\CO&=12\\BO&=7\\DO&=16.8\end{aligned}

    , why is △AOB∼△COD\triangle AOB\sim\triangle COD justified without assuming AB∥CDAB\parallel CD?

    Sides around equal vertical anglesA, O, C are collinear in order, and B, O, D are collinear in order. Only the given side labels are shown. No parallelism of AB and CD is assumed. The angles at O are vertical angles.AOCBD512716.8Schematic, not to scale.
    Answer choices for question 12