12 multiple-choice questions, progressively harder.
Solve x2+6x+2=0x^2 + 6x + 2 = 0x2+6x+2=0.
Solution
Correct answer: C
Read off a=1a = 1a=1, b=6b = 6b=6, c=2c = 2c=2, so D=36−8=28D = 36 - 8 = 28D=36−8=28, with 28=27\sqrt{28} = 2\sqrt{7}28=27.
x=−6±272=−3±7x = \frac{-6 \pm 2\sqrt{7}}{2} = -3 \pm \sqrt{7}x=2−6±27=−3±7
Both parts of the numerator are divided by 222.
Solve x2−2x+5=0x^2 - 2x + 5 = 0x2−2x+5=0.
Correct answer: A
Read off a=1a = 1a=1, b=−2b = -2b=−2, c=5c = 5c=5, so −b=2-b = 2−b=2 and D=4−20=−16D = 4 - 20 = -16D=4−20=−16, with −16=4i\sqrt{-16} = 4i−16=4i.
x=2±4i2=1±2ix = \frac{2 \pm 4i}{2} = 1 \pm 2ix=22±4i=1±2i
Divide both the 222 and the 4i4i4i by 222.
Solve 2x2+x−6=02x^2 + x - 6 = 02x2+x−6=0.
Read off a=2a = 2a=2, b=1b = 1b=1, c=−6c = -6c=−6, so −4ac=+48-4ac = +48−4ac=+48 and D=1+48=49D = 1 + 48 = 49D=1+48=49.
x=−1±494=−1±74x = \frac{-1 \pm \sqrt{49}}{4} = \frac{-1 \pm 7}{4}x=4−1±49=4−1±7
So x=64=32x = \frac{6}{4} = \tfrac{3}{2}x=46=23 or x=−84=−2x = \frac{-8}{4} = -2x=4−8=−2.
Rewrite 2x2=5x−12x^2 = 5x - 12x2=5x−1 in standard form and give aaa, bbb, ccc.
Correct answer: D
Move every term to the left side so the other side is 000.
2x2=5x−1⇒2x2−5x+1=02x^2 = 5x - 1 \quad\Rightarrow\quad 2x^2 - 5x + 1 = 02x2=5x−1⇒2x2−5x+1=0
So a=2a = 2a=2, b=−5b = -5b=−5, c=1c = 1c=1. Subtracting 5x5x5x makes bbb negative, and moving −1-1−1 makes c=+1c = +1c=+1.
Solve x2−6x+7=0x^2 - 6x + 7 = 0x2−6x+7=0.
Read off a=1a = 1a=1, b=−6b = -6b=−6, c=7c = 7c=7, so −b=6-b = 6−b=6 and D=36−28=8D = 36 - 28 = 8D=36−28=8, with 8=22\sqrt{8} = 2\sqrt{2}8=22.
x=6±222=3±2x = \frac{6 \pm 2\sqrt{2}}{2} = 3 \pm \sqrt{2}x=26±22=3±2
Solve x2+2x+2=0x^2 + 2x + 2 = 0x2+2x+2=0.
Read off a=1a = 1a=1, b=2b = 2b=2, c=2c = 2c=2, so D=4−8=−4D = 4 - 8 = -4D=4−8=−4, with −4=2i\sqrt{-4} = 2i−4=2i.
x=−2±2i2=−1±ix = \frac{-2 \pm 2i}{2} = -1 \pm ix=2−2±2i=−1±i
Divide both parts of the numerator by 222.
Simplify 48\sqrt{48}48 (the kind of radical that appears when a discriminant is 484848).
Correct answer: B
Factor out the largest perfect square, 48=16×348 = 16 \times 348=16×3.
48=16 3=43\sqrt{48} = \sqrt{16}\,\sqrt{3} = 4\sqrt{3}48=163=43
Since 333 has no square factor left, 434\sqrt{3}43 is fully simplified.
Solve x2−3x−10=0x^2 - 3x - 10 = 0x2−3x−10=0.
Read off a=1a = 1a=1, b=−3b = -3b=−3, c=−10c = -10c=−10, so −b=3-b = 3−b=3 and −4ac=+40-4ac = +40−4ac=+40, giving D=9+40=49D = 9 + 40 = 49D=9+40=49.
x=3±492=3±72x = \frac{3 \pm \sqrt{49}}{2} = \frac{3 \pm 7}{2}x=23±49=23±7
So x=5x = 5x=5 or x=−2x = -2x=−2.
How many real solutions does x2+x+4=0x^2 + x + 4 = 0x2+x+4=0 have?
Compute the discriminant with a=1a = 1a=1, b=1b = 1b=1, c=4c = 4c=4.
D=12−4(1)(4)=1−16=−15D = 1^2 - 4(1)(4) = 1 - 16 = -15D=12−4(1)(4)=1−16=−15
A negative discriminant means no real solutions; both roots are complex.
Solve 9x2−4=09x^2 - 4 = 09x2−4=0 with the quadratic formula.
Read off a=9a = 9a=9, b=0b = 0b=0, c=−4c = -4c=−4, so the −b-b−b term is 000.
x=0±−4(9)(−4)18=±14418=±1218=±23x = \frac{0 \pm \sqrt{-4(9)(-4)}}{18} = \frac{\pm\sqrt{144}}{18} = \frac{\pm 12}{18} = \pm\tfrac{2}{3}x=180±−4(9)(−4)=18±144=18±12=±32
Solve x2−2x+10=0x^2 - 2x + 10 = 0x2−2x+10=0.
Read off a=1a = 1a=1, b=−2b = -2b=−2, c=10c = 10c=10, so −b=2-b = 2−b=2 and D=4−40=−36D = 4 - 40 = -36D=4−40=−36, with −36=6i\sqrt{-36} = 6i−36=6i.
x=2±6i2=1±3ix = \frac{2 \pm 6i}{2} = 1 \pm 3ix=22±6i=1±3i
What is the discriminant of 2x2+7x−4=02x^2 + 7x - 4 = 02x2+7x−4=0?
With a=2a = 2a=2, b=7b = 7b=7, c=−4c = -4c=−4, and ccc negative so −4ac-4ac−4ac is positive.
D=72−4(2)(−4)=49+32=81D = 7^2 - 4(2)(-4) = 49 + 32 = 81D=72−4(2)(−4)=49+32=81
A perfect square, so the equation has two rational roots.
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