This site is a work in progress. New lessons are added regularly. Contact us
Chapter Review · a rapid pre-test review (speedrun)

Complex Numbers and the Quadratic Formula: Chapter Review

A rapid review before the test: the chapter's vocabulary and notation, every formula with the conditions to use it, the standard problem types step by step, and the traps that cost points.

Vocabulary and notation

The imaginary unit ii
The number defined by i2=1i^2 = -1, equivalently i=1i = \sqrt{-1}.
Pure imaginary number
A real multiple of ii, such as 3i3i or 12i-\tfrac{1}{2}i.
Complex number, standard form a+bia + bi
A real part aa plus an imaginary part bb. Every answer should end in this form; a quotient with ii still in the denominator is unfinished.
Real and imaginary parts
For z=a+biz = a + bi: Re(z)=a\operatorname{Re}(z) = a and Im(z)=b\operatorname{Im}(z) = b, a real number, not bibi.
Equality of complex numbers
a+bi=c+dia + bi = c + di exactly when a=ca = c and b=db = d: the parts match separately.
Complex conjugate z\overline{z}
For z=a+biz = a + bi, the conjugate is abia - bi: only the imaginary part flips sign.
Completed-square form (xh)2+k(x - h)^2 + k
A quadratic rewritten as a perfect square plus a constant, solvable by one square root.
Standard form ax2+bx+c=0ax^2 + bx + c = 0
A quadratic set equal to zero, with a0a \neq 0. Read aa, bb, cc, with their signs, only from this form.
The discriminant D=b24acD = b^2 - 4ac
The quantity under the root in the quadratic formula. Its sign alone decides the kind of roots.
Complex conjugate pair
The two roots p+qip + qi and pqip - qi that a quadratic with real coefficients has when D<0D < 0: same real part, opposite imaginary parts.

Formulas and theorems

  • Definition of ii

    i2=1i^2 = -1

    Use when Always; it is the definition. Every simplification of a power of ii or a root of a negative traces back to it.

    e.g. (3i)2=9i2=9(3i)^2 = 9i^2 = -9.

  • Powers of ii

    i1=i,i2=1i3=i,i4=1\begin{gathered} i^1 = i, \quad i^2 = -1 \\ i^3 = -i, \quad i^4 = 1 \end{gathered}
    Multiplying by i turns a quarter of the way round, so the powers repeat every fourCurved arrows join the four points counterclockwise in the order 1, i, minus 1, minus i, each arrow one quarter turn and each arrow a multiplication by i, so starting at 1 and taking four steps arrives back at 1.ReIm1i−1−i× i
    Text description

    The values 1, i, minus 1 and minus i sit a quarter turn apart around the origin, and each multiplication by i steps counterclockwise to the next, so four steps return to 1.

    Use when The cycle repeats every four: reduce ini^n to the power given by the remainder of nn on division by 44 (remainder 00 gives 11).

  • Square root of a negative

    n=in\sqrt{-n} = i\sqrt{n}

    Use when n>0n > 0. Convert BEFORE multiplying roots: ab=ab\sqrt{a}\cdot\sqrt{b} = \sqrt{ab} fails when both radicands are negative.

    e.g. 12=i12=2i3\sqrt{-12} = i\sqrt{12} = 2i\sqrt{3}.

  • Addition and subtraction

    (a+bi)±(c+di)=(a±c)+(b±d)i\begin{gathered} (a + bi) \pm (c + di) \\ = (a \pm c) + (b \pm d)i \end{gathered}
    Adding complex numbers adds the two steps, so the sum is the far corner of a parallelogramDashed segments run from 3 plus i and from 1 plus 2i to a fourth point, completing a parallelogram whose highlighted diagonal from the origin is the sum 4 plus 3i, because the real parts 3 and 1 add to 4 and the imaginary parts 1 and 2 add to 3.ReIm03 + i1 + 2i4 + 3i
    Text description

    Arrows from the origin to 3 plus i and to 1 plus 2i are two sides of a parallelogram whose far corner is their sum, 4 plus 3i.

    Use when Any two complex numbers: real parts combine with real parts, ii parts with ii parts.

    e.g. (62i)(3+4i)=36i(6 - 2i) - (3 + 4i) = 3 - 6i: the minus reaches both parts.

  • Multiplication

    (a+bi)(c+di)=(acbd)+(ad+bc)i\begin{gathered} (a + bi)(c + di) \\ = (ac - bd) + (ad + bc)i \end{gathered}

    Use when Any two complex numbers. In practice: expand as binomials, then replace i2i^2 with 1-1 before collecting.

    e.g. (1+2i)(3i)=3i+6i2i2=5+5i(1 + 2i)(3 - i) = 3 - i + 6i - 2i^2 = 5 + 5i.

  • Conjugate product

    (a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2
    A conjugate is the mirror image across the real axisTwo marked points in the complex plane, 5 plus 2i above the horizontal real axis and 5 minus 2i directly below it, joined by a dashed vertical segment. A small square marks the right angle where that segment crosses the axis, and one tick on each half shows the two halves are the same length, so the highlighted real axis acts as a mirror and only the imaginary part changes sign.ReIm0mirror line5 + 2i5 − 2i
    Text description

    The points for 5 plus 2i and 5 minus 2i sit the same distance directly above and below the real axis, so a conjugate is the mirror image across that axis.

    Use when Any complex number; the result is real and nonnegative. A sum, not the difference of squares.

    e.g. (5+2i)(52i)=25+4=29(5 + 2i)(5 - 2i) = 25 + 4 = 29.

  • Division

    a+bic+di=(a+bi)(cdi)c2+d2\frac{a + bi}{c + di} = \frac{(a + bi)(c - di)}{c^2 + d^2}

    Use when c+di0c + di \neq 0. Multiply top and bottom by the denominator's conjugate, then finish in standard form.

  • Completing the square

    x2+bx+(b2)2=(x+b2)2x^2 + bx + \left(\tfrac{b}{2}\right)^2 = \left(x + \tfrac{b}{2}\right)^2

    Use when Leading coefficient 11: divide the equation by aa first if a1a \neq 1. In an equation, add (b2)2\left(\tfrac{b}{2}\right)^2 to both sides; in an expression, add and subtract it in the same line.

    e.g. x2+8x+16=(x+4)2x^2 + 8x + 16 = (x + 4)^2.

  • The quadratic formula

    x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

    Use when a0a \neq 0, and the equation must be in standard form ax2+bx+c=0ax^2 + bx + c = 0 before reading the coefficients. The whole numerator sits over 2a2a.

  • The discriminant

    D=b24acD = b^2 - 4ac

    Use when Coefficients read from standard form, signs included.

  • Root classification by DD

    D>0D > 0: two distinct real roots. D=0D = 0: one repeated real root, x=b2ax = -\tfrac{b}{2a}. D<0D < 0: a complex conjugate pair.

    Use when Standard form with real coefficients. Answers how many and what kind of roots without solving.

  • Projectile height model

    h=16t2+v0t+h0h = -16t^2 + v_0 t + h_0

    Use when Height in feet, tt in seconds, v0v_0 the initial upward speed, h0h_0 the launch height; in metres the first term is 4.9t2-4.9t^2. Set h=0h = 0 for landing, h=Hh = H for a target height.

    e.g. Thrown up at 3232 ft/s from 4848 ft: h=16t2+32t+48h = -16t^2 + 32t + 48.

Problem types, step by step

Simplify a power of ii

  1. Divide the exponent by 44 and keep the remainder.
  2. Replace: remainder 010 \to 1, 1i1 \to i, 212 \to -1, 3i3 \to -i. Never multiply the exponent out.

e.g. i23i^{23}: 23=45+323 = 4 \cdot 5 + 3, so i23=i3=ii^{23} = i^3 = -i.

Simplify roots of negatives, alone or in products

  1. Rewrite every n\sqrt{-n} as ini\sqrt{n} first, before any other move.
  2. Simplify the remaining real radical: 12=23\sqrt{12} = 2\sqrt{3}.
  3. Multiply or combine, replacing i2i^2 with 1-1.

e.g. 49=(2i)(3i)=6i2=6\sqrt{-4}\cdot\sqrt{-9} = (2i)(3i) = 6i^2 = -6.

Add, subtract, or multiply complex numbers

  1. Distribute: a subtraction's minus reaches both parts; a product expands like binomials.
  2. Replace every i2i^2 with 1-1.
  3. Combine real parts together and ii parts together.
  4. Report the result as a+bia + bi.

e.g. (2i)(3+2i)=6+4i3i2i2=8+i(2 - i)(3 + 2i) = 6 + 4i - 3i - 2i^2 = 8 + i.

Divide complex numbers (write a quotient in standard form)

  1. Multiply top and bottom by the conjugate of the denominator.
  2. Expand: the denominator becomes the real number c2+d2c^2 + d^2.
  3. Replace i2i^2 with 1-1 in the numerator and collect.
  4. Split into realc2+d2+imagc2+d2i\tfrac{\text{real}}{c^2 + d^2} + \tfrac{\text{imag}}{c^2 + d^2}i.

e.g. 2+i12i=(2+i)(1+2i)1+4=5i5=i\frac{2 + i}{1 - 2i} = \frac{(2 + i)(1 + 2i)}{1 + 4} = \frac{5i}{5} = i.

Solve a quadratic by completing the square

  1. If a1a \neq 1, divide the whole equation by aa.
  2. Move the constant to the right side.
  3. Add (b2)2\left(\tfrac{b}{2}\right)^2 to both sides.
  4. Write the left side as (x+b2)2\left(x + \tfrac{b}{2}\right)^2.
  5. Square-root both sides with ±\pm; a negative right side gives ±ix\pm i\sqrt{\phantom{x}}.
  6. Solve for xx.

e.g. x2+6x7=0x^2 + 6x - 7 = 0: (x+3)2=16(x + 3)^2 = 16, so x=1x = 1 or x=7x = -7.

Solve a quadratic with the quadratic formula

  1. Rearrange to ax2+bx+c=0ax^2 + bx + c = 0 and read aa, bb, cc with their signs.
  2. Compute D=b24acD = b^2 - 4ac first, on its own line.
  3. Substitute into x=b±D2ax = \tfrac{-b \pm \sqrt{D}}{2a}.
  4. Simplify the radical; if D<0D < 0, write D=iD\sqrt{D} = i\sqrt{-D}.
  5. Reduce the fraction, dividing the whole numerator by 2a2a.

e.g. x23x10=0x^2 - 3x - 10 = 0: D=9+40=49D = 9 + 40 = 49, x=3±72=5x = \frac{3 \pm 7}{2} = 5 or 2-2.

Classify roots without solving

  1. Rearrange to standard form.
  2. Compute D=b24acD = b^2 - 4ac.
  3. Read off: D>0D > 0 two distinct real, D=0D = 0 one repeated real, D<0D < 0 a complex conjugate pair. Stop; the full formula is not needed.

e.g. 2x2+3x+5=02x^2 + 3x + 5 = 0: D=940=31<0D = 9 - 40 = -31 < 0, a complex conjugate pair.

Solve a quadratic word problem

  1. Name one variable and write every other quantity in terms of it (ww and w+3w + 3, not ww and ll).
  2. Translate the situation into an equation and rearrange to standard form.
  3. Solve by the fastest method that fits: factoring if it factors, otherwise the formula.
  4. Test each root against the situation: reject a negative length, time, or count, but keep both roots when both fit (a thrown object passes a height going up and coming down).
  5. Answer the quantity actually asked for, in a sentence, with units.

e.g. Width ww metres, length w+3w + 3, area 4040: w2+3w40=0w^2 + 3w - 40 = 0, w=5w = 5 or 8-8; reject 8-8, so the width is 55 metres.

Exam traps

  • Trap Multiplying two negative radicands with the product rule: 49=36=6\sqrt{-4}\cdot\sqrt{-9} = \sqrt{36} = 6.

    Fix The rule fails for two negatives. Convert first: (2i)(3i)=6i2=6(2i)(3i) = 6i^2 = -6.

  • Trap Leaving an i2i^2 term in a product, or treating it as 00 or 11.

    Fix Every i2i^2 becomes 1-1 and merges into the real part: in (2i)(3+2i)(2 - i)(3 + 2i), 2i2-2i^2 becomes +2+2.

  • Trap Conjugate product by the difference-of-squares reflex: (a+bi)(abi)=a2b2(a + bi)(a - bi) = a^2 - b^2.

    Fix (bi)2=+b2-(bi)^2 = +b^2, so the product is a2+b2a^2 + b^2: a sum, always real.

  • Trap Adding (b2)2\left(\tfrac{b}{2}\right)^2 to one side of an equation, or forgetting the matching subtraction in an expression.

    Fix Equation: add it to both sides. Expression: add and subtract it in the same line.

  • Trap Reading aa, bb, cc straight off x2=3x+10x^2 = 3x + 10.

    Fix Coefficients are valid only from standard form: rearrange to x23x10=0x^2 - 3x - 10 = 0, then read the signs.

  • Trap Sign slips inside the formula: b=7b = -7 giving b2=49b^2 = -49, b-b kept as bb, or 4ac-4ac mis-signed when c<0c < 0.

    Fix b2b^2 is never negative; b-b is the opposite of bb; when aa and cc have opposite signs, 4ac-4ac is positive, so it adds.

  • Trap Calling a negative discriminant "no solution".

    Fix D<0D < 0 gives a complex conjugate pair; every quadratic has roots, real or complex.

  • Trap Growing each dimension by xx when a border or frame of width xx surrounds it: (5+x)(7+x)(5 + x)(7 + x).

    Fix A border sits on both ends of each dimension, so each grows by 2x2x: (5+2x)(7+2x)(5 + 2x)(7 + 2x).

  • Trap Auto-rejecting the negative root, or auto-keeping exactly one, in a word problem.

    Fix Test each root against the situation and say why the rejected ones go; two positive times can both be valid.

Chapter test Questions from across the chapter