Expanding and Factoring Expressions: Practice

Multiply the $2$ across both terms inside.

$2(x + 5) = 2 \cdot x + 2 \cdot 5 = 2x + 10$

Multiply the $3$ across each term, keeping the minus sign.

$3(x - 2) = 3x - 6$

Multiply the $5$ across both terms.

$5(2x + 1) = 10x + 5$

Distribute the $x$ across both terms.

$x(x + 7) = x^2 + 7x$

A leading minus is the factor $-1$; it flips the sign of each term.

$-(x - 3) = -x + 3$

Multiply every term of the first by every term of the second, then combine like terms.

$(x + 1)(x + 2) = x^2 + 2x + x + 2 = x^2 + 3x + 2$

Both terms share the factor $2$.

$2x + 4 = 2(x + 2)$

The greatest common factor of $3x$ and $6$ is $3$.

$3x + 6 = 3(x + 2)$

Both terms contain a factor of $x$, and $x = x \cdot 1$.

$x^2 + x = x \cdot x + x \cdot 1 = x(x + 1)$

The common factor of $5x$ and $10$ is $5$.

$5x + 10 = 5(x + 2)$

Multiply the $4$ across both terms.

$4(x + 2) = 4x + 8$

Each term has a factor of $x$.

$x^2 + 5x = x(x + 5)$