12 multiple-choice questions, progressively harder.
The ratio of Anna's age to Ben's age is 4:34 : 34:3. In 666 years the ratio will be 6:56 : 56:5. How old is Anna now?
Solution
Correct answer: B
Write the ages as 4k4k4k and 3k3k3k. In 666 years, (4k+6):(3k+6)(4k + 6) : (3k + 6)(4k+6):(3k+6) equals 6:56 : 56:5, so cross-multiply.
5(4k+6)=6(3k+6) ⟹ 20k+30=18k+36 ⟹ k=35(4k + 6) = 6(3k + 6) \implies 20k + 30 = 18k + 36 \implies k = 35(4k+6)=6(3k+6)⟹20k+30=18k+36⟹k=3
Anna is 4k=124k = 124k=12.
The ratio of sheep to cows is 9:49 : 49:4, and there are 656565 more sheep than cows. How many animals are there in total?
Correct answer: A
Sheep minus cows is 9k−4k=5k9k - 4k = 5k9k−4k=5k, so 5k=655k = 655k=65 and k=13k = 13k=13. The total is all 9+4=139 + 4 = 139+4=13 parts.
5k=65 ⟹ k=13,13k=1695k = 65 \implies k = 13, \quad 13k = 1695k=65⟹k=13,13k=169
There are 169169169 animals.
A recipe has sugar, flour, and cocoa in the ratio 2:5:12 : 5 : 12:5:1. A baker uses 151515 cups of flour. How many cups of the whole mixture result?
Correct answer: D
Flour is the 555 term, so 5k=155k = 155k=15 and k=3k = 3k=3. The whole mixture is all 2+5+1=82 + 5 + 1 = 82+5+1=8 parts.
5k=15 ⟹ k=3,8k=245k = 15 \implies k = 3, \quad 8k = 245k=15⟹k=3,8k=24
The recipe makes 242424 cups.
Combine x:y=5:2x : y = 5 : 2x:y=5:2 and y:z=6:7y : z = 6 : 7y:z=6:7. If z=42z = 42z=42, find xxx.
Scale yyy to the least common multiple of 222 and 666, which is 666: 5:2=15:65 : 2 = 15 : 65:2=15:6, so x:y:z=15:6:7x : y : z = 15 : 6 : 7x:y:z=15:6:7. Then z=7k=42z = 7k = 42z=7k=42, so k=6k = 6k=6.
7k=42 ⟹ k=6,15k=907k = 42 \implies k = 6, \quad 15k = 907k=42⟹k=6,15k=90
So x=90x = 90x=90.
A mix has almonds to cashews in the ratio 5:35 : 35:3. Removing 888 almonds makes the two counts equal. How many cashews are in the mix?
Correct answer: C
Write almonds as 5k5k5k and cashews as 3k3k3k. Removing 888 almonds makes them equal, so 5k−8=3k5k - 8 = 3k5k−8=3k.
5k−8=3k ⟹ 2k=8 ⟹ k=45k - 8 = 3k \implies 2k = 8 \implies k = 45k−8=3k⟹2k=8⟹k=4
Cashews is 3k=123k = 123k=12.
A rectangle's length to width is 7:47 : 47:4, and its perimeter is 888888 cm. What is its length, in cm?
Write length as 7k7k7k and width as 4k4k4k. The perimeter is 2(7k+4k)=22k=882(7k + 4k) = 22k = 882(7k+4k)=22k=88, so k=4k = 4k=4.
22k=88 ⟹ k=4,7k=2822k = 88 \implies k = 4, \quad 7k = 2822k=88⟹k=4,7k=28
The length is 282828 cm.
Two numbers are in the ratio 5:25 : 25:2. Adding 999 to the smaller makes it equal to the larger. What is the larger number?
Write the numbers as 5k5k5k and 2k2k2k. Adding 999 to the smaller matches the larger, so 2k+9=5k2k + 9 = 5k2k+9=5k.
2k+9=5k ⟹ 3k=9 ⟹ k=32k + 9 = 5k \implies 3k = 9 \implies k = 32k+9=5k⟹3k=9⟹k=3
The larger number is 5k=155k = 155k=15.
Two numbers are in the ratio 5:35 : 35:3. Adding 101010 to each makes the ratio 7:57 : 57:5. What is the larger original number?
Write the numbers as 5k5k5k and 3k3k3k. After adding 101010 to each, (5k+10):(3k+10)(5k + 10) : (3k + 10)(5k+10):(3k+10) equals 7:57 : 57:5, so cross-multiply.
5(5k+10)=7(3k+10) ⟹ 25k+50=21k+70 ⟹ k=55(5k + 10) = 7(3k + 10) \implies 25k + 50 = 21k + 70 \implies k = 55(5k+10)=7(3k+10)⟹25k+50=21k+70⟹k=5
The larger original number is 5k=255k = 255k=25.
A prize of 720072007200 dollars is shared among three people so that the first gets twice the second, and the second gets three times the third. How many dollars does the third person get?
Let the third get 111 part. The second is three times that, 333 parts, and the first is twice the second, 666 parts, so the ratio is 6:3:16 : 3 : 16:3:1. The parts total 101010, so 10k=720010k = 720010k=7200 and k=720k = 720k=720.
10k=7200 ⟹ k=720,1k=72010k = 7200 \implies k = 720, \quad 1k = 72010k=7200⟹k=720,1k=720
The third person gets 720720720 dollars.
The ratio A:B=6:5A : B = 6 : 5A:B=6:5 and C:B=3:5C : B = 3 : 5C:B=3:5. Find A:CA : CA:C.
The shared term BBB is 555 in both, and C:B=3:5C : B = 3 : 5C:B=3:5 makes C=3C = 3C=3 when B=5B = 5B=5, so A:B:C=6:5:3A : B : C = 6 : 5 : 3A:B:C=6:5:3.
A:C=6:3=2:1A : C = 6 : 3 = 2 : 1A:C=6:3=2:1
A tank of antifreeze and water is in the ratio 3:73 : 73:7. Adding 161616 liters of antifreeze makes the ratio 5:75 : 75:7. How many liters of water are in the tank?
Write antifreeze as 3k3k3k and water as 7k7k7k. The water is unchanged, so (3k+16):7k(3k + 16) : 7k(3k+16):7k equals 5:75 : 75:7, and cross-multiplying gives the equation in kkk.
7(3k+16)=5(7k) ⟹ 21k+112=35k ⟹ k=87(3k + 16) = 5(7k) \implies 21k + 112 = 35k \implies k = 87(3k+16)=5(7k)⟹21k+112=35k⟹k=8
Water is 7k=567k = 567k=56 liters.
Three numbers are in the ratio 4:6:94 : 6 : 94:6:9, and the smallest and largest add to 525252. What is the middle number?
Smallest plus largest is 4k+9k=13k4k + 9k = 13k4k+9k=13k, so 13k=5213k = 5213k=52 and k=4k = 4k=4. The middle number is the 666 term.
13k=52 ⟹ k=4,6k=2413k = 52 \implies k = 4, \quad 6k = 2413k=52⟹k=4,6k=24
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