Mean, Median, Mode, and Range: Practice

Add the five values and divide by $5$.

$\text{mean} = \frac{7 + 9 + 8 + 6 + 10}{5} = \frac{40}{5} = 8$

Add the four values and divide by $4$.

$\text{mean} = \frac{3 + 4 + 6 + 7}{4} = \frac{20}{4} = 5$

Add the four values and divide by $4$.

$\text{mean} = \frac{12 + 7 + 11 + 10}{4} = \frac{40}{4} = 10$

Sort the values: $3, 6, 9, 14, 14$. With five values the third one is the middle.

$\text{median} = 9$

Sort the values: $2, 3, 5, 6, 8, 8$. With an even count, average the two middle values, $5$ and $6$.

$\text{median} = \frac{5 + 6}{2} = 5.5$

The three values must add to $3 \times 9 = 27$. Subtract the two known values.

$x = 27 - 6 - 10 = 11$

Sort the values: $4, 7, 9, 11, 100$. With five values the third one is the middle.

$\text{median} = 9$

The large value $100$ does not change the median, which depends only on position.

Add the five values and divide by $5$.

$\text{mean} = \frac{4 + 7 + 1 + 9 + 4}{5} = \frac{25}{5} = 5$

Sort the values: $11, 12, 14, 15, 18, 20$. With an even count, average the two middle values, $14$ and $15$.

$\text{median} = \frac{14 + 15}{2} = 14.5$

Add the five temperatures and divide by $5$.

$\text{mean} = \frac{71 + 68 + 74 + 80 + 72}{5} = \frac{365}{5} = 73$

The sum is $75$, so the mean is $\frac{75}{5} = 15$. The values are sorted and the middle one is also $15$.

$\text{mean} = 15, \qquad \text{median} = 15$

The largest value is $9$ and the smallest is $0$.

$\text{range} = 9 - 0 = 9$