12 multiple-choice questions, progressively harder.
Divide: 7.2÷0.087.2 \div 0.087.2÷0.08.
Solution
Correct answer: A
The divisor 0.080.080.08 has two decimal places, so slide both points two places to the right. The divisor becomes 888 and the dividend becomes 720720720 (a trailing zero fills the second slide).
7.2÷0.08=720÷8=907.2 \div 0.08 = 720 \div 8 = 907.2÷0.08=720÷8=90
Dividing by a very small number gives a large quotient.
Compute: 5.6−2.34+1.55.6 - 2.34 + 1.55.6−2.34+1.5.
Correct answer: D
Work left to right, padding to two places and lining up the points each time.
5.60−2.34=3.265.60 - 2.34 = 3.265.60−2.34=3.26
Then add the next number.
3.26+1.50=4.763.26 + 1.50 = 4.763.26+1.50=4.76
Multiply: 2.4×0.252.4 \times 0.252.4×0.25.
Correct answer: B
Multiply as whole numbers: 24×25=60024 \times 25 = 60024×25=600. The factor 2.42.42.4 has one place and 0.250.250.25 has two, so the product has 1+2=31 + 2 = 31+2=3 places.
2.4×0.25=0.600=0.62.4 \times 0.25 = 0.600 = 0.62.4×0.25=0.600=0.6
The trailing zeros can be dropped without changing the value.
Multiply: 0.024×0.50.024 \times 0.50.024×0.5.
Multiply as whole numbers: 24×5=12024 \times 5 = 12024×5=120. The factor 0.0240.0240.024 has three places and 0.50.50.5 has one, so the product has 3+1=43 + 1 = 43+1=4 places.
0.024×0.5=0.0120=0.0120.024 \times 0.5 = 0.0120 = 0.0120.024×0.5=0.0120=0.012
The trailing zero in the fourth place can be dropped.
Compute: 9.8×4.99.8 \times 4.99.8×4.9.
Multiply as whole numbers: 98×49=480298 \times 49 = 480298×49=4802. Each factor has one decimal place, so the product has 1+1=21 + 1 = 21+1=2 places.
9.8×4.9=48.029.8 \times 4.9 = 48.029.8×4.9=48.02
The estimate 10×5=5010 \times 5 = 5010×5=50 confirms the size.
Which is larger, 0.4×0.40.4 \times 0.40.4×0.4 or 0.4+0.40.4 + 0.40.4+0.4, and by how much?
Compute each. The product has two decimal places, since 4×4=164 \times 4 = 164×4=16, and the sum lines up the tenths.
0.4×0.4=0.16,0.4+0.4=0.80.4 \times 0.4 = 0.16, \qquad 0.4 + 0.4 = 0.80.4×0.4=0.16,0.4+0.4=0.8
The sum 0.80.80.8 is larger, and 0.8−0.16=0.640.8 - 0.16 = 0.640.8−0.16=0.64, so it is larger by 0.640.640.64.
Divide: 4.8÷0.164.8 \div 0.164.8÷0.16.
Correct answer: C
The divisor 0.160.160.16 has two decimal places, so slide both points two places to the right. The divisor becomes 161616 and the dividend becomes 480480480 (a trailing zero fills the second slide).
4.8÷0.16=480÷16=304.8 \div 0.16 = 480 \div 16 = 304.8÷0.16=480÷16=30
Compute: 4.5÷0.9÷0.54.5 \div 0.9 \div 0.54.5÷0.9÷0.5.
Divide left to right. For the first division, slide both points one place so the divisor is whole.
4.5÷0.9=45÷9=54.5 \div 0.9 = 45 \div 9 = 54.5÷0.9=45÷9=5
Then divide that result by the next number, sliding again.
5÷0.5=50÷5=105 \div 0.5 = 50 \div 5 = 105÷0.5=50÷5=10
Compute: 0.001×2.50.001 \times 2.50.001×2.5.
Multiply as whole numbers: 1×25=251 \times 25 = 251×25=25. The factor 0.0010.0010.001 has three places and 2.52.52.5 has one, so the product has 3+1=43 + 1 = 43+1=4 places.
0.001×2.5=0.00250.001 \times 2.5 = 0.00250.001×2.5=0.0025
Multiplying by 0.0010.0010.001 is the same as dividing by 100010001000, sliding the point three places left.
A board 4.54.54.5 m long has a 1.251.251.25 m piece and a 0.80.80.8 m piece cut from it. How much is left, in m?
Total the two cut pieces first, lining up the points.
1.25+0.80=2.051.25 + 0.80 = 2.051.25+0.80=2.05
Then subtract from the board's length.
4.50−2.05=2.454.50 - 2.05 = 2.454.50−2.05=2.45
So 2.452.452.45 m is left.
Compute: 0.9×0.9−0.010.9 \times 0.9 - 0.010.9×0.9−0.01.
Multiply first, counting places: 9×9=819 \times 9 = 819×9=81 with 1+1=21 + 1 = 21+1=2 places.
0.9×0.9=0.810.9 \times 0.9 = 0.810.9×0.9=0.81
Then subtract, lining up the points.
0.81−0.01=0.80=0.80.81 - 0.01 = 0.80 = 0.80.81−0.01=0.80=0.8
A recipe needs 0.150.150.15 kg of sugar per batch. How many batches can be made from 1.21.21.2 kg of sugar?
The number of batches is the total sugar divided by the sugar per batch. Slide both points two places right so the divisor is whole.
1.2÷0.15=120÷15=81.2 \div 0.15 = 120 \div 15 = 81.2÷0.15=120÷15=8
So 888 batches can be made.
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