12 multiple-choice questions, progressively harder.
Evaluate 2+322 + 3^22+32.
Solution
Correct answer: A
Powers come before addition in the order of operations.
32=9,2+9=113^2 = 9, \qquad 2 + 9 = 1132=9,2+9=11
It is not 52=255^2 = 2552=25; the addition waits until after the power.
Evaluate (2+3)2(2 + 3)^2(2+3)2.
Correct answer: B
Parentheses are resolved before the exponent.
2+3=5,52=252 + 3 = 5, \qquad 5^2 = 252+3=5,52=25
Compare with 2+32=112 + 3^2 = 112+32=11, where there are no parentheses.
Evaluate 5×235 \times 2^35×23.
Correct answer: C
Evaluate the power before multiplying.
23=8,5×8=402^3 = 8, \qquad 5 \times 8 = 4023=8,5×8=40
It is not (5×2)3=1000(5 \times 2)^3 = 1000(5×2)3=1000; the exponent attaches only to the 222.
Evaluate 23+222^3 + 2^223+22.
Correct answer: D
Evaluate each power, then add the results.
23=8,22=4,8+4=122^3 = 8, \quad 2^2 = 4, \quad 8 + 4 = 1223=8,22=4,8+4=12
You cannot add the exponents here; each power is worked out on its own first.
What is 10410^4104?
A power of ten is a 111 followed by as many zeros as the exponent.
104=10,00010^4 = 10{,}000104=10,000
That is a 111 followed by four zeros.
Evaluate 42−324^2 - 3^242−32.
Evaluate each power first, then subtract.
42=16,32=9,16−9=74^2 = 16, \quad 3^2 = 9, \quad 16 - 9 = 742=16,32=9,16−9=7
It is not (4−3)2=1(4 - 3)^2 = 1(4−3)2=1; subtract the values, not the bases.
Evaluate 1+2×321 + 2 \times 3^21+2×32.
Power first, then multiplication, then addition.
32=9,2×9=18,1+18=193^2 = 9, \quad 2 \times 9 = 18, \quad 1 + 18 = 1932=9,2×9=18,1+18=19
The exponent acts only on the 333, before the ×\times× or the +++.
What is 434^343?
The exponent 333 means three factors of 444.
43=4×4×4=644^3 = 4 \times 4 \times 4 = 6443=4×4×4=64
Evaluate 3×1023 \times 10^23×102.
102=100,3×100=30010^2 = 100, \qquad 3 \times 100 = 300102=100,3×100=300
It is not (3×10)2=900(3 \times 10)^2 = 900(3×10)2=900; the exponent attaches only to the 101010.
Evaluate 52+175^2 + 1^752+17.
Evaluate each power, then add.
52=25,17=1,25+1=265^2 = 25, \quad 1^7 = 1, \quad 25 + 1 = 2652=25,17=1,25+1=26
Any power of 111 is 111.
Write 5×5×5×55 \times 5 \times 5 \times 55×5×5×5 using an exponent, then evaluate it.
There are four 555's multiplied together, so the base is 555 and the exponent is 444.
54=5×5×5×5=6255^4 = 5 \times 5 \times 5 \times 5 = 62554=5×5×5×5=625
Evaluate (−1)5(-1)^5(−1)5.
Multiply five factors, each equal to −1-1−1.
(−1)5=(−1)(−1)(−1)(−1)(−1)=−1(-1)^5 = (-1)(-1)(-1)(-1)(-1) = -1(−1)5=(−1)(−1)(−1)(−1)(−1)=−1
An odd number of −1-1−1 factors leaves the product negative; an even number would give +1+1+1.
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