12 multiple-choice questions, progressively harder.
What is 35\frac{3}{5}53 of 454545?
Solution
Correct answer: A
One fifth of 454545 is 45÷5=945 \div 5 = 945÷5=9, then take 333 of those parts.
3×9=273 \times 9 = 273×9=27
So 35\frac{3}{5}53 of 454545 is 272727.
A team played 242424 games and won 58\frac{5}{8}85 of them. How many games did the team lose?
Correct answer: D
Winning 58\frac{5}{8}85 means losing the other 38\frac{3}{8}83. One eighth of 242424 is 24÷8=324 \div 8 = 324÷8=3, so the losses are 3×3=93 \times 3 = 93×3=9.
38 of 24=9\frac{3}{8} \text{ of } 24 = 983 of 24=9
So the team lost 999 games. (Check: 58\frac{5}{8}85 of 242424 is 151515 wins, and 15+9=2415 + 9 = 2415+9=24.)
Which of these is NOT equal to a whole number?
Correct answer: B
A fraction equals a whole number when the numerator is a multiple of the denominator. Check each by dividing.
153=5,81=8,1212=1\frac{15}{3} = 5, \quad \frac{8}{1} = 8, \quad \frac{12}{12} = 1315=5,18=8,1212=1
But 94=9÷4\frac{9}{4} = 9 \div 449=9÷4 is not whole, since 444 goes into 999 twice with 111 left over.
The fraction 12d\frac{12}{d}d12 is a proper fraction. What is the smallest whole number ddd can be?
A proper fraction has a denominator larger than its numerator.
d>12d > 12d>12
The smallest whole number greater than 121212 is 131313, giving 1213\frac{12}{13}1312, which is just under 111.
Which list of unit fractions is ordered from least to greatest?
These are unit fractions, all with numerator 111, so the larger the denominator, the smaller the fraction.
14<13<12\frac{1}{4} < \frac{1}{3} < \frac{1}{2}41<31<21
From least to greatest the order is 14,13,12\frac{1}{4}, \frac{1}{3}, \frac{1}{2}41,31,21, since fourths are the smallest pieces and halves the largest.
Written as one improper fraction, how many eighths are in 333 whole units and 222 extra eighths?
Each whole is 888 eighths, so 333 wholes is 3×8=243 \times 8 = 243×8=24 eighths, plus the 222 extra eighths.
24+2=26 ⇒ 26824 + 2 = 26 \;\Rightarrow\; \frac{26}{8}24+2=26⇒826
So the total is 268\frac{26}{8}826, an improper fraction between 333 and 444.
Which fraction is greater, 56\frac{5}{6}65 or 78\frac{7}{8}87? (Hint: compare how far each falls short of 111.)
Each fraction is one unit fraction short of 111: 56=1−16\frac{5}{6} = 1 - \frac{1}{6}65=1−61 and 78=1−18\frac{7}{8} = 1 - \frac{1}{8}87=1−81. The one missing the smaller piece is closer to 111, hence larger.
18<16 ⇒ 78>56\frac{1}{8} < \frac{1}{6} \;\Rightarrow\; \frac{7}{8} > \frac{5}{6}81<61⇒87>65
Since 78\frac{7}{8}87 falls only 18\frac{1}{8}81 short while 56\frac{5}{6}65 falls 16\frac{1}{6}61 short, 78\frac{7}{8}87 is greater.
If 25\frac{2}{5}52 of a number is 888, what is the whole number?
If two fifths is 888, then one fifth is half of that, 8÷2=48 \div 2 = 48÷2=4. The whole is 555 fifths.
5×4=205 \times 4 = 205×4=20
So the whole number is 202020, and 25\frac{2}{5}52 of 202020 is indeed 888.
Which statement about 05\frac{0}{5}50 and 50\frac{5}{0}05 is correct?
Correct answer: C
A zero numerator means you took none of the parts, which is a valid amount of 000. A zero denominator means dividing by 000, which has no answer.
05=0÷5=0,50=5÷0 → undefined\frac{0}{5} = 0 \div 5 = 0, \qquad \frac{5}{0} = 5 \div 0 \;\to\; \text{undefined}50=0÷5=0,05=5÷0→undefined
So only the denominator being 000 causes a problem.
What is 59\frac{5}{9}95 of 727272?
One ninth of 727272 is 72÷9=872 \div 9 = 872÷9=8, then take 555 of those parts.
5×8=405 \times 8 = 405×8=40
So 59\frac{5}{9}95 of 727272 is 404040.
A board is 78\frac{7}{8}87 of a meter long. You cut off 38\frac{3}{8}83 of a meter. What fraction of a meter is left?
Both lengths are measured in eighths of a meter, so subtract the numerators over the common denominator 888.
78−38=48\frac{7}{8} - \frac{3}{8} = \frac{4}{8}87−83=84
Since 7−3=47 - 3 = 47−3=4 eighths remain, the leftover length is 48\frac{4}{8}84 of a meter.
Three friends equally share 777 identical sandwiches. Written as an improper fraction, how much does each friend get?
Sharing equally is division: each friend gets 7÷37 \div 37÷3, and the fraction bar means divide.
7÷3=737 \div 3 = \frac{7}{3}7÷3=37
So each friend gets 73\frac{7}{3}37 of a sandwich, which is two whole sandwiches and one third more.
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