12 multiple-choice questions, progressively harder.
A solid is made of a 444 cm cube with a second 444 cm cube stacked exactly on top. What is the total volume?
Solution
Correct answer: D
Each cube has volume s3=43=64 cm3s^3 = 4^3 = 64 \text{ cm}^3s3=43=64 cm3. Volume is additive, so add the two.
V=64+64=128 cm3V = 64 + 64 = 128 \text{ cm}^3V=64+64=128 cm3
A box is 999 cm by 555 cm by 222 cm. What is its volume?
Correct answer: C
Multiply the three dimensions.
V=9×5×2=90 cm3V = 9 \times 5 \times 2 = 90 \text{ cm}^3V=9×5×2=90 cm3
Doubling which single dimension of a box doubles its volume?
Correct answer: A
Volume is l×w×hl \times w \times hl×w×h, a product of the three. Multiplying any one factor by 222 multiplies the whole product by 222.
V=l×w×h → (2l)×w×h=2(lwh)V = l \times w \times h \;\to\; (2l) \times w \times h = 2(lwh)V=l×w×h→(2l)×w×h=2(lwh)
So doubling any one dimension doubles the volume.
A cube has a volume of 1000 cm31000 \text{ cm}^31000 cm3. What is the length of one edge?
The edge is the number that cubes to give the volume.
s3=1000 ⇒ s=10 cms^3 = 1000 \;\Rightarrow\; s = 10 \text{ cm}s3=1000⇒s=10 cm
because 10×10×10=100010 \times 10 \times 10 = 100010×10×10=1000.
A box holds exactly 111 litre, which is 1000 cm31000 \text{ cm}^31000 cm3. Its base is 101010 cm by 101010 cm. What is its height?
Correct answer: B
Divide the volume by the base area.
base area=10×10=100 cm2\text{base area} = 10 \times 10 = 100 \text{ cm}^2base area=10×10=100 cm2
h=1000100=10 cmh = \frac{1000}{100} = 10 \text{ cm}h=1001000=10 cm
A cylinder has radius 111 cm and height 100100100 cm (a thin rod). What is its volume? Use π≈3.14\pi \approx 3.14π≈3.14.
Use V=πr2hV = \pi r^2 hV=πr2h.
V=3.14×12×100=3.14×100=314 cm3V = 3.14 \times 1^2 \times 100 = 3.14 \times 100 = 314 \text{ cm}^3V=3.14×12×100=3.14×100=314 cm3
A cylinder has radius 101010 cm and height 111 cm (a flat disk). What is its volume? Use π≈3.14\pi \approx 3.14π≈3.14.
Use V=πr2hV = \pi r^2 hV=πr2h, even though the height is small.
V=3.14×102×1=3.14×100=314 cm3V = 3.14 \times 10^2 \times 1 = 3.14 \times 100 = 314 \text{ cm}^3V=3.14×102×1=3.14×100=314 cm3
A wide, thin disk can still hold a sizable volume because its base area is large.
Two boxes are joined to make a step shape. The lower box is 10×4×310 \times 4 \times 310×4×3 and the upper box is 6×4×36 \times 4 \times 36×4×3. What is the total volume?
Find each box's volume and add, since volume is additive.
V1=10×4×3=120 cm3,V2=6×4×3=72 cm3V_1 = 10 \times 4 \times 3 = 120 \text{ cm}^3, \qquad V_2 = 6 \times 4 \times 3 = 72 \text{ cm}^3V1=10×4×3=120 cm3,V2=6×4×3=72 cm3
V=120+72=192 cm3V = 120 + 72 = 192 \text{ cm}^3V=120+72=192 cm3
A cube has edge 101010 cm. By what factor does its volume grow if every edge is tripled to 303030 cm?
Volume is s3s^3s3, so tripling the edge multiplies the volume by 333^333.
(3s)3s3=27s3s3=27\frac{(3s)^3}{s^3} = \frac{27 s^3}{s^3} = 27s3(3s)3=s327s3=27
The new volume is 272727 times the old one. (Check: 103=100010^3 = 1000103=1000 and 303=2700030^3 = 27000303=27000.)
A cube of edge 222 cm has a volume of 8 cm38 \text{ cm}^38 cm3. A cube of edge 444 cm has a volume of 64 cm364 \text{ cm}^364 cm3. The edge doubled; by what factor did the volume grow?
Volume is s3s^3s3, so doubling the edge multiplies the volume by 23=82^3 = 823=8.
648=8\frac{64}{8} = 8864=8
The volume grew by a factor of 888.
A cylinder of radius 777 cm and height 101010 cm sits inside a box just large enough to contain it, 141414 cm by 141414 cm by 101010 cm. What volume of the box is NOT taken up by the cylinder? Use π≈3.14\pi \approx 3.14π≈3.14.
Subtract the cylinder's volume from the box's volume.
Vbox=14×14×10=1960 cm3V_{\text{box}} = 14 \times 14 \times 10 = 1960 \text{ cm}^3Vbox=14×14×10=1960 cm3
Vcyl=3.14×72×10=3.14×49×10=1538.6 cm3V_{\text{cyl}} = 3.14 \times 7^2 \times 10 = 3.14 \times 49 \times 10 = 1538.6 \text{ cm}^3Vcyl=3.14×72×10=3.14×49×10=1538.6 cm3
1960−1538.6=421.4 cm31960 - 1538.6 = 421.4 \text{ cm}^31960−1538.6=421.4 cm3
That leftover space is the four corners the round cylinder cannot reach.
A closed box is 555 cm by 555 cm by 888 cm. How much wrapping paper, at minimum, covers it exactly?
Wrapping paper covers the surface area. Find one face of each kind, then double the total.
lw=5×5=25,lh=5×8=40,wh=5×8=40lw = 5 \times 5 = 25, \quad lh = 5 \times 8 = 40, \quad wh = 5 \times 8 = 40lw=5×5=25,lh=5×8=40,wh=5×8=40
S=2(25+40+40)=2×105=210 cm2S = 2(25 + 40 + 40) = 2 \times 105 = 210 \text{ cm}^2S=2(25+40+40)=2×105=210 cm2
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