Solving One-Step Equations: Practice

The variable has $3$ added to it, so subtract $3$ from both sides to undo it.

$x + 3 - 3 = 10 - 3 \;\Rightarrow\; x = 7$

Check: $7 + 3 = 10$, which is true.

The variable is multiplied by $5$, so divide both sides by $5$.

$\frac{5x}{5} = \frac{35}{5} \;\Rightarrow\; x = 7$

Check: $5(7) = 35$, which is true.

The variable is divided by $2$, so multiply both sides by $2$.

$2 \cdot \frac{x}{2} = 2 \cdot 6 \;\Rightarrow\; x = 12$

Check: $\frac{12}{2} = 6$, which is true.

Divide both sides by $9$ to undo the multiplication.

$\frac{9x}{9} = \frac{0}{9} \;\Rightarrow\; x = 0$

Check: $9(0) = 0$, which is true.

Subtract $11$ from both sides.

$x + 11 - 11 = 20 - 11 \;\Rightarrow\; x = 9$

Check: $9 + 11 = 20$, which is true.

The variable is multiplied by $6$, and the inverse of multiplication is division.

$\frac{6x}{6} = \frac{18}{6} \;\Rightarrow\; x = 3$

Dividing both sides by $6$ cancels the coefficient and leaves the variable alone.

Add $10$ to both sides.

$x - 10 + 10 = 6 + 10 \;\Rightarrow\; x = 16$

Check: $16 - 10 = 6$, which is true.

Divide both sides by $8$.

$\frac{8x}{8} = \frac{24}{8} \;\Rightarrow\; x = 3$

Check: $8(3) = 24$, which is true.

Subtract $2$ from both sides.

$x + 2 - 2 = 9 - 2 \;\Rightarrow\; x = 7$

Check: $7 + 2 = 9$, which is true.

Substitute $8$ for $x$ in the original left side.

$8 - 3 = 5$

The left side equals $5$, the same as the right side, so the solution checks out.

Subtract $5$ from both sides.

$x + 5 - 5 = 13 - 5 \;\Rightarrow\; x = 8$

Check: $8 + 5 = 13$, which is true.

Add $1$ to both sides to undo the subtraction.

$x - 1 + 1 = 0 + 1 \;\Rightarrow\; x = 1$

Check: $1 - 1 = 0$, which is true.