12 multiple-choice questions, progressively harder.
Solve 23x=10\dfrac{2}{3}x = 1032x=10 for xxx.
Solution
Correct answer: D
The variable is multiplied by 23\tfrac{2}{3}32. Dividing by a fraction is multiplying by its reciprocal, so multiply both sides by 32\tfrac{3}{2}23.
32⋅23x=32⋅10 ⇒ x=15\frac{3}{2} \cdot \frac{2}{3}x = \frac{3}{2} \cdot 10 \;\Rightarrow\; x = 1523⋅32x=23⋅10⇒x=15
Check: 23(15)=303=10\tfrac{2}{3}(15) = \tfrac{30}{3} = 1032(15)=330=10, which is true.
Solve x+34=14x + \tfrac{3}{4} = \tfrac{1}{4}x+43=41 for xxx.
Correct answer: B
Subtract 34\tfrac{3}{4}43 from both sides; the fractions share the denominator 444.
x=14−34=−24=−12x = \tfrac{1}{4} - \tfrac{3}{4} = -\tfrac{2}{4} = -\tfrac{1}{2}x=41−43=−42=−21
Check: −12+34=14-\tfrac{1}{2} + \tfrac{3}{4} = \tfrac{1}{4}−21+43=41, which is true.
A number multiplied by −6-6−6 gives −48-48−48. Which equation models this, and what is the number?
Correct answer: C
"A number multiplied by −6-6−6" is −6x-6x−6x, and it equals −48-48−48. Divide both sides by −6-6−6.
−6x−6=−48−6 ⇒ x=8\frac{-6x}{-6} = \frac{-48}{-6} \;\Rightarrow\; x = 8−6−6x=−6−48⇒x=8
A negative divided by a negative is positive, so x=8x = 8x=8. Check: −6(8)=−48-6(8) = -48−6(8)=−48.
Solve 1.2x=3.61.2x = 3.61.2x=3.6 for xxx.
Divide both sides by the coefficient 1.21.21.2.
1.2x1.2=3.61.2 ⇒ x=3\frac{1.2x}{1.2} = \frac{3.6}{1.2} \;\Rightarrow\; x = 31.21.2x=1.23.6⇒x=3
Check: 1.2(3)=3.61.2(3) = 3.61.2(3)=3.6, which is true.
After a 777-dollar deposit, a savings account holds 404040 dollars. If bbb is the balance before the deposit, the equation is b+7=40b + 7 = 40b+7=40. What was the balance before?
Correct answer: A
Subtract 777 from both sides of b+7=40b + 7 = 40b+7=40 to undo the deposit.
b+7−7=40−7 ⇒ b=33b + 7 - 7 = 40 - 7 \;\Rightarrow\; b = 33b+7−7=40−7⇒b=33
Check: 33+7=4033 + 7 = 4033+7=40, which is true.
Solve −12x=7-\tfrac{1}{2}x = 7−21x=7 for xxx.
Multiply both sides by the reciprocal of −12-\tfrac{1}{2}−21, which is −2-2−2.
−2⋅(−12x)=−2⋅7 ⇒ x=−14-2 \cdot \left(-\tfrac{1}{2}x\right) = -2 \cdot 7 \;\Rightarrow\; x = -14−2⋅(−21x)=−2⋅7⇒x=−14
Check: −12(−14)=7-\tfrac{1}{2}(-14) = 7−21(−14)=7, which is true.
Solve x+56=2x + \tfrac{5}{6} = 2x+65=2 for xxx.
Subtract 56\tfrac{5}{6}65 from both sides. Write 222 as 126\tfrac{12}{6}612 to subtract.
x=126−56=76=116x = \tfrac{12}{6} - \tfrac{5}{6} = \tfrac{7}{6} = 1\tfrac{1}{6}x=612−65=67=161
Check: 116+56=21\tfrac{1}{6} + \tfrac{5}{6} = 2161+65=2, which is true.
Three identical bags weigh 13.513.513.5 kg in total. If www is one bag's weight, then 3w=13.53w = 13.53w=13.5. How much does one bag weigh?
Divide both sides of 3w=13.53w = 13.53w=13.5 by 333.
3w3=13.53 ⇒ w=4.5\frac{3w}{3} = \frac{13.5}{3} \;\Rightarrow\; w = 4.533w=313.5⇒w=4.5
Check: 3(4.5)=13.53(4.5) = 13.53(4.5)=13.5, which is true.
Solve −8=x−5-8 = x - 5−8=x−5 for xxx.
The variable still has 555 subtracted from it, so add 555 to both sides even though the variable is on the right.
−8+5=x−5+5 ⇒ −3=x-8 + 5 = x - 5 + 5 \;\Rightarrow\; -3 = x−8+5=x−5+5⇒−3=x
Check: −3−5=−8-3 - 5 = -8−3−5=−8, which is true.
Solve 45x=−8\tfrac{4}{5}x = -854x=−8 for xxx.
Multiply both sides by the reciprocal 54\tfrac{5}{4}45.
54⋅45x=54⋅(−8) ⇒ x=−10\frac{5}{4} \cdot \frac{4}{5}x = \frac{5}{4} \cdot (-8) \;\Rightarrow\; x = -1045⋅54x=45⋅(−8)⇒x=−10
Check: 45(−10)=−405=−8\tfrac{4}{5}(-10) = \tfrac{-40}{5} = -854(−10)=5−40=−8, which is true.
Solve 24=−3x24 = -3x24=−3x for xxx.
Divide both sides by −3-3−3, even though the variable term is on the right.
24−3=−3x−3 ⇒ −8=x\frac{24}{-3} = \frac{-3x}{-3} \;\Rightarrow\; -8 = x−324=−3−3x⇒−8=x
Check: −3(−8)=24-3(-8) = 24−3(−8)=24, which is true.
Solve x+2.75=2.75x + 2.75 = 2.75x+2.75=2.75 for xxx.
Subtract 2.752.752.75 from both sides.
x+2.75−2.75=2.75−2.75 ⇒ x=0x + 2.75 - 2.75 = 2.75 - 2.75 \;\Rightarrow\; x = 0x+2.75−2.75=2.75−2.75⇒x=0
Check: 0+2.75=2.750 + 2.75 = 2.750+2.75=2.75, which is true.
Reset this practice set?
This clears every answer you have given and starts the set again from question 1.