12 multiple-choice questions, progressively harder.
A salary of 40,00040{,}00040,000 dollars gets a 10%10\%10% raise, and the next year another 10%10\%10% raise. What is the salary after both raises?
Solution
Correct answer: C
Each raise multiplies by 1.101.101.10, and the second raise is figured on the already-raised salary.
1.10×1.10×40,000=1.21×40,000=48,4001.10 \times 1.10 \times 40{,}000 = 1.21 \times 40{,}000 = 48{,}4001.10×1.10×40,000=1.21×40,000=48,400
The total rise is 21%21\%21%, not 20%20\%20%, because the second 10%10\%10% is taken of the larger amount.
A car was bought for 24,00024{,}00024,000 dollars and is now worth 18,00018{,}00018,000 dollars. What is the percent decrease in value?
Correct answer: A
The size of the change is 24,000−18,000=6,00024{,}000 - 18{,}000 = 6{,}00024,000−18,000=6,000. Compare it to the original 24,00024{,}00024,000.
6,00024,000×100%=0.25×100%=25%\frac{6{,}000}{24{,}000} \times 100\% = 0.25 \times 100\% = 25\%24,0006,000×100%=0.25×100%=25%
So the value dropped by 25%25\%25%. Dividing by the new value 18,00018{,}00018,000 would give the wrong 33.3%33.3\%33.3%.
After a 35%35\%35% discount, a chair costs 130130130 dollars. What was the original price?
Correct answer: D
A 35%35\%35% discount leaves 65%65\%65%, so 130130130 is 65%65\%65% of the original. Divide the part by 0.650.650.65.
1300.65=200\frac{130}{0.65} = 2000.65130=200
So the original price was 200200200 dollars. Check: 35%35\%35% of 200200200 is 707070 off, and 200−70=130200 - 70 = 130200−70=130.
A store buys an item for 505050 dollars, marks it up 60%60\%60%, then puts it on sale at 25%25\%25% off the marked price. What is the sale price?
First the markup: 1.60×50=801.60 \times 50 = 801.60×50=80 is the marked price. Then the 25%25\%25% discount is taken of 808080.
0.75×80=600.75 \times 80 = 600.75×80=60
The sale price is 606060 dollars. The 25%25\%25% off is figured on the marked 808080, not the original 505050 cost.
A price rises from 808080 dollars to 100100100 dollars. What is the percent increase?
Correct answer: B
The change is 100−80=20100 - 80 = 20100−80=20. Compare it to the original 808080, not the new 100100100.
2080×100%=0.25×100%=25%\frac{20}{80} \times 100\% = 0.25 \times 100\% = 25\%8020×100%=0.25×100%=25%
So the price rose by 25%25\%25%. Comparing 202020 to the new 100100100 would give the wrong 20%20\%20%.
After a 12%12\%12% increase, an attendance count is 560560560. What was the original attendance?
A 12%12\%12% increase makes the new value 112%112\%112% of the original, so divide by 1.121.121.12.
5601.12=500\frac{560}{1.12} = 5001.12560=500
So the original attendance was 500500500. Check: 1.12×500=5601.12 \times 500 = 5601.12×500=560.
A 454545 dollar restaurant bill has 8%8\%8% tax added first, then a 15%15\%15% tip is taken on the after-tax amount. What is the total to the nearest cent?
First add the tax: 1.08×45=48.601.08 \times 45 = 48.601.08×45=48.60. Then the tip is 15%15\%15% of that after-tax amount.
1.15×48.60=55.891.15 \times 48.60 = 55.891.15×48.60=55.89
The total is 55.8955.8955.89 dollars. Because the tip is on the after-tax total, you cannot just add 8%8\%8% and 15%15\%15% and take 23%23\%23% of 454545.
What percent of 808080 must you remove to be left with 686868?
The amount removed is 80−68=1280 - 68 = 1280−68=12. The percent removed compares that to the original 808080.
1280×100%=0.15×100%=15%\frac{12}{80} \times 100\% = 0.15 \times 100\% = 15\%8012×100%=0.15×100%=15%
So a 15%15\%15% decrease takes 808080 down to 686868.
A coat is marked up by some percent from a 404040 dollar cost to a 525252 dollar price. What is the percent markup?
The markup amount is 52−40=1252 - 40 = 1252−40=12, and a markup is measured against the cost (the original).
1240×100%=0.30×100%=30%\frac{12}{40} \times 100\% = 0.30 \times 100\% = 30\%4012×100%=0.30×100%=30%
So the markup is 30%30\%30%. Comparing 121212 to the price 525252 would give the wrong base.
A phone's price drops from 600600600 dollars to 480480480 dollars, then drops another 25%25\%25%. What is the final price?
The first price is 480480480. The second drop of 25%25\%25% leaves 75%75\%75% of 480480480.
0.75×480=3600.75 \times 480 = 3600.75×480=360
The final price is 360360360 dollars.
A worker's hours fall from 404040 to 343434. What is the percent decrease?
The size of the change is 40−34=640 - 34 = 640−34=6. Compare it to the original 404040.
640×100%=0.15×100%=15%\frac{6}{40} \times 100\% = 0.15 \times 100\% = 15\%406×100%=0.15×100%=15%
So the hours dropped by 15%15\%15%.
Which leaves you with more money: a 20%20\%20% raise followed by a 20%20\%20% cut, or no change at all?
Test it on 100100100 dollars. The raise gives 1.20×100=1201.20 \times 100 = 1201.20×100=120, and the 20%20\%20% cut is taken of 120120120.
0.80×120=960.80 \times 120 = 960.80×120=96
That leaves 969696 dollars, less than the 100100100 you started with, so no change at all leaves more. The cut acts on the larger raised amount, so it removes more than the raise added.
Reset this practice set?
This clears every answer you have given and starts the set again from question 1.