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Percent Increase and Decrease

Learning goals

  • Divide the change by the original, never by the new value
  • Build one multiplier for any increase or decrease
  • Match discounts to decreases and tax, tip and markup to increases
  • Recover the original by dividing by the multiplier
  • Show why a rise then an equal fall does not return to the start

Why we measure change against the original

Suppose a price moves from one amount to another. The plain amount of change is just the difference:

change=new valueoriginal value.\text{change} = \text{new value} - \text{original value}.

If the new value is bigger, the change is positive (the quantity went up). If the new value is smaller, the change is negative (the quantity went down). That difference alone is not enough, because the same difference can be huge or tiny depending on the size of the thing it happened to. A raise of 1,0001{,}000 dollars is life-changing on a 2,0002{,}000 dollar salary and a rounding error on a 200,000200{,}000 dollar salary.

So we need a baseline to compare the change against. The only sensible baseline is the original value, the amount you had before the change happened. The change grew out of that starting amount, so the fair question is “how big is this change compared to where we started.” Asking what fraction the change is of the original, and then writing that fraction as a percent, is the percent change:

percent change=changeoriginal value×100%.\text{percent change} = \frac{\text{change}}{\text{original value}} \times 100\%.

The original value must not be zero. Dividing by zero is undefined, so a quantity that starts at zero has no percent change at all.

This is the second percent task from the last lesson, “what percent is one number of another,” applied to the change and the original. You take the ratio changeoriginal\frac{\text{change}}{\text{original}} and rescale it to a denominator of 100100, which is what multiplying by 100%100\% does. A positive result is a percent increase; a negative result is a percent decrease.

The original goes on the bottom for a concrete reason: it is the whole that the change is being measured as a part of. Putting the new value on the bottom would answer a different and less natural question. Doing that is the single most common error in this whole topic.

Worked example 1 A price rises from 4040 to 5050 dollars. Find the percent increase.

First find the amount of change by subtracting the original from the new value:

change=5040=10.\text{change} = 50 - 40 = 10.

The price went up, so this is an increase. Now ask what percent 1010 is of the original 4040, by making the ratio of change to original and writing it over 100100:

1040×100%=0.25×100%=25%.\frac{10}{40} \times 100\% = 0.25 \times 100\% = 25\%.

The price rose by 25%25\%. Notice the 1010 is compared to the original 4040, not to the new 5050. If you divided by 5050 you would get 20%20\%, the answer to a different question.

Worked example 2 A class shrinks from 3030 to 2424 students. Find the percent decrease.

Subtract to find the change:

change=2430=6.\text{change} = 24 - 30 = -6.

The count went down, so the change is negative. Put that signed change over the original 3030:

630×100%=0.2×100%=20%.\frac{-6}{30} \times 100\% = -0.2 \times 100\% = -20\%.

The percent change is 20%-20\%, and the minus sign is what marks it as a decrease. The size of that decrease is 20%20\%, the same number with the sign dropped.

Both readings are in ordinary use, so keep them apart. The signed percent change here is 20%-20\%, while the class shrank by 20%20\%. Saying “a 20%20\% decrease” names the size, and the word decrease already carries the direction.

Check your understanding

A book's price increases from 2525 dollars to 3030 dollars. What is the percent increase?

Answer choices

Finding the new value with a multiplier

Often you know the original amount and the percent change, and you want the new value. There are two ways to get it, and they always agree.

The two-step way matches how you would explain it in words. To increase 200200 by 15%15\%, first find 15%15\% of the original, then add it on:

15% of 200=0.15×200=30,new value=200+30=230.15\% \text{ of } 200 = 0.15 \times 200 = 30, \qquad \text{new value} = 200 + 30 = 230.

For a decrease you subtract instead. To decrease 200200 by 15%15\%, find the same 3030 and take it away: 20030=170200 - 30 = 170.

The one-step way does it with a single multiplication.

Why a p%p\% increase multiplies the original by 1+p1001 + \frac{p}{100}#

Take a 12%12\% increase on an original of 150150. The two-step route finds 12%12\% of 150150, which is 1818, and adds it on:

150+0.12×150=150+18=168.150 + 0.12 \times 150 = 150 + 18 = 168.

Both pieces on the left are built from the same 150150, so pull it out. The first piece is the whole 150150, which is 1×1501 \times 150, and the second piece is 12100×150\frac{12}{100} \times 150:

(1+12100)×150=1.12×150=168.\left(1 + \frac{12}{100}\right) \times 150 = 1.12 \times 150 = 168.

The same argument runs with letters in place of those digits. Increasing the original by p%p\% means adding p%p\% of the original to the original:

new value=original+(p% of original).\text{new value} = \text{original} + (p\% \text{ of original}).

Since p%p\% of the original is p100×original\frac{p}{100} \times \text{original}, substitute that in:

new value=original+p100×original.\text{new value} = \text{original} + \frac{p}{100} \times \text{original}.

Now both terms on the right have a factor of the original, so factor it out. The first term is 1×original1 \times \text{original}, because the whole original is 100%100\% of itself:

new value=(1+p100)×original.\text{new value} = \left(1 + \frac{p}{100}\right) \times \text{original}.

Nothing in that first run used anything special about the 1212 or the 150150. The 11 keeps the original amount you already had (100%100\% of it), and the p100\frac{p}{100} adds the extra p%p\% on top. A decrease runs the identical argument with a subtraction, giving (1p100)×original\left(1 - \frac{p}{100}\right) \times \text{original}: you keep 100%100\% and remove p%p\%.

So to grow an amount by p%p\%, multiply by 1+p1001 + \frac{p}{100}; to shrink it by p%p\%, multiply by 1p1001 - \frac{p}{100}. The number you multiply by is called the multiplier. Returning to the 15%15\% increase on 200200:

(1+15100)×200=1.15×200=230,\left(1 + \frac{15}{100}\right) \times 200 = 1.15 \times 200 = 230,

the same 230230 as before, in one step. The decrease is (115100)×200=0.85×200=170\left(1 - \frac{15}{100}\right) \times 200 = 0.85 \times 200 = 170. A useful way to read the multiplier: a 15%15\% increase leaves you with 115%115\% of the original. A 15%15\% decrease leaves you with 85%85\% of the original, and those two readings are why the multipliers are 1.151.15 and 0.850.85.

A 20 percent increase from 200 to 240The original bar of length 200 is 100 percent. The new bar repeats that 200 and adds a 20 percent segment of 40, reaching 240, which is 120 percent of the original.Original200 (100%)After a 20% increase200+40= 240
A 20 percent increase on an original of 200. The new bar is the full original (100 percent) plus an extra 20 percent, so it reaches 240, which is 1.20 times the original.

Worked example 3 Increase 250250 by 8%8\% two ways

Two-step way. Find 8%8\% of the original, then add it on. Since 8%=0.088\% = 0.08,

0.08×250=20,250+20=270.0.08 \times 250 = 20, \qquad 250 + 20 = 270.

One-step way. An 8%8\% increase keeps the original 100%100\% and adds 8%8\%, so the multiplier is 1+8100=1.081 + \frac{8}{100} = 1.08:

1.08×250=270.1.08 \times 250 = 270.

Both routes give 270270, because the multiplier is just the two-step calculation packed into one number.

Check your understanding

What single number do you multiply by to decrease an amount by 30%30\%?

Answer choices

Discounts, tax, tip, and markup

These multipliers are exactly the arithmetic behind everyday money problems. Every one of them is either a percent decrease or a percent increase on a starting price.

A discount (a sale) is a percent decrease. ”25%25\% off” means you pay 100%25%=75%100\% - 25\% = 75\% of the original, so the sale price is 0.750.75 times the original. Sales tax and a tip are percent increases added to a bill. A 7%7\% tax means you pay 107%107\% of the listed price, a multiplier of 1.071.07. A markup is a percent increase a store adds to its cost to set the selling price. A 40%40\% markup on cost means the price is 1.401.40 times the cost. In every case, decide whether the percent is added or removed, build the matching multiplier, and multiply.

Worked example 4 A 6060 dollar backpack is 35%35\% off. Find the sale price.

A discount is a percent decrease, so you pay the part of the price that is left after the discount. A 35%35\% discount leaves 100%35%=65%100\% - 35\% = 65\% of the original, so the multiplier is 10.35=0.651 - 0.35 = 0.65:

0.65×60=39.0.65 \times 60 = 39.

The sale price is 3939 dollars. As a check by the two-step route, 35%35\% of 6060 is 0.35×60=210.35 \times 60 = 21 off, and 6021=3960 - 21 = 39, the same price.

Read the whole grid below, all 100100 squares of it, as the original price, and shade only the squares a shopper still pays for.

Shade 6565 of them and the readout hands you 0.650.65, the multiplier from the backpack above. The 3535 unshaded squares are the discount and the shaded ones are the sale price. Shade 7070 instead and you have the multiplier for 30%30\% off, and 9090 gives the one for 10%10\% off. The pattern to catch is that the number named in the sale is the part that leaves. The number you multiply by in the sale is the part that stays, so a 30%30\% discount multiplies by 0.700.70 and never by 0.300.30.

Why a discount multiplies by the part that stays, not the part taken off

65 squares of 100 shaded. The part that stays is 65%, so the multiplier is 0.65. The other 35 squares are the 35% taken away. One hundred equal squares arranged 10 across and 10 down, filling from the top left. Use the controls below the figure to change how many are shaded.
Squares shaded

65 squares of 100 shaded. The part that stays is 65%, so the multiplier is 0.65. The other 35 squares are the 35% taken away.

The hundred-square is the original amount. Shade the part that remains after a decrease and the decimal in the readout is the multiplier for it, while the unshaded squares are the percent taken away.

Worked example 5 A 4545 dollar meal has 6%6\% tax and a 20%20\% tip, both on the menu price.

When the tax and the tip are each figured on the original menu price, you can add their percents because they share the same base. The bill is the menu price plus 6%6\% of it plus 20%20\% of it, which is 100%+6%+20%=126%100\% + 6\% + 20\% = 126\% of the menu price. The multiplier is 1.261.26:

1.26×45=56.70.1.26 \times 45 = 56.70.

The total is 56.7056.70 dollars. Step by step this is 6%6\% of 45=2.7045 = 2.70 in tax and 20%20\% of 45=9.0045 = 9.00 in tip, and 45+2.70+9.00=56.7045 + 2.70 + 9.00 = 56.70, matching the multiplier. The percents could be combined only because both were taken of the same menu price. If the tip were figured on the after-tax total instead, you could not just add 66 and 2020.

Finding the original from the new value

Sometimes you know the new value and the percent change, and you want the original amount that came before it. You just have to read off what percent of the original the new value is, and then undo the multiplication with division.

That division needs a multiplier that is not zero. A 100%100\% decrease has a multiplier of 00, so the new value is 00 whatever the original was. No division can recover the original from that.

After 20%20\% off, the sale price is what is left of the original, which is 100%20%=80%100\% - 20\% = 80\% of it. So the sale price is 80%80\% of the original, which means

sale price=0.80×original.\text{sale price} = 0.80 \times \text{original}.

This is now the third percent task from the last lesson. You know a part (80%80\% of the original is the sale price) and you want the whole (the original). To recover a whole from a known part, you divide. If the sale price is 4848 dollars, then 4848 is 80%80\% of the original, so

original=480.80=60.\text{original} = \frac{48}{0.80} = 60.

The original price was 6060 dollars. The check runs forward: 80%80\% of 6060 is 0.80×60=480.80 \times 60 = 48, the sale price you were given. The same logic handles an increase. If a number is the result of a 25%25\% increase, it is 125%125\% of the original. So you divide the new value by 1.251.25 to get back to the original.

The reason you divide rather than just subtracting the percent is the trap of the next section. 20%20\% of the sale price is not the same as 20%20\% of the original, so adding 20%20\% of 4848 back on cannot recover it. You must divide by the multiplier that produced the new value.

Worked example 6 After a 30%30\% discount, a coat costs 6363 dollars. Find the original price.

A 30%30\% discount leaves 100%30%=70%100\% - 30\% = 70\% of the original, so the sale price is 70%70\% of the original price:

63=0.70×original.63 = 0.70 \times \text{original}.

The 6363 is a known part (70%70\%) of the whole you want, so divide the part by 0.700.70 to recover the whole:

original=630.70=90.\text{original} = \frac{63}{0.70} = 90.

The original price was 9090 dollars. Check it forward: 30%30\% of 9090 is 2727 off, and 9027=6390 - 27 = 63, the sale price. A tempting wrong move is to take 30%30\% of 6363 and add it back, but 30%30\% of 6363 is only 18.9018.90, and 63+18.90=81.9063 + 18.90 = 81.90, not 9090. That fails because the discount was 30%30\% of the larger original, not 30%30\% of the smaller sale price.

Check your understanding

After a 25%25\% increase, a population is 500500. What was the original population?

Answer choices

Common mistakes

Practice

Multiple Choice Questions (MCQ)

Progressively harder sets of questions. Each opens on its own page.

Free Response Questions (FRQ)

Longer questions in parts, to be worked out on paper. Progressive hints, the answer on its own so you can check yourself and try again, then the full worked solution, plus a rubric to mark your own work against.

Free response Work it out on paper 5 questions Start →
More practice (optional)

Extra sets, as hard as the Challenge set. Each one opens on its own page.

More resources (optional)

Other explanations of this lesson, if you want a second take.

A bit of history (Optional)

Some of the oldest homework we have asks about a loan. Clay tablets from Babylon, written nearly four thousand years ago, work out how a debt grows month after month.

Their counting ran on sixty rather than ten, and their money did too. Silver was weighed in minas. One mina was sixty shekels. A common loan charged a shekel a month on every mina borrowed. That is one part in sixty. No percent sign was needed, because nobody was counting in hundreds. Twelve months of it came to twelve shekels on sixty, which we would now call twenty percent a year.

Notice what that rate is measured against. It is a shekel for every mina borrowed. It is not a shekel for every mina owed later, once months of interest had swollen the debt. The base is the amount at the start.

That is the rule this whole lesson turns on. You divide the change by the original value. A percent means nothing until you say what it is a percent of.