12 multiple-choice questions, progressively harder.
Triangle ABCABCABC has angles
Triangle DEFDEFDEF has angles
Which statement follows?
Solution
Correct answer: B
The third angles complete the correspondence.
Thus A matches E, B matches F, and C matches D; AA establishes the similarity.
It is given that △RST∼△KLM\triangle RST\sim\triangle KLM△RST∼△KLM. If
, find STSTST.
Correct answer: A
RS corresponds to KL, while ST corresponds to LM. Use first-triangle lengths over second-triangle lengths.
Given △ABC∼△XYZ\triangle ABC\sim\triangle XYZ△ABC∼△XYZ, suppose
If XZ=19.5XZ=19.5XZ=19.5, find ttt.
Correct answer: C
The factor from ABC to XYZ is nine sixths. AC corresponds to XZ.
In triangle ABCABCABC, DDD lies between AAA and BBB, EEE lies between AAA and CCC, and DE∥BCDE\parallel BCDE∥BC. Which angle equals ∠ADE\angle ADE∠ADE by corresponding angles?
Correct answer: D
AB is a transversal of the parallel segments DE and BC. The angle between DA and DE corresponds to the angle between BA and BC.
Points A,O,CA,O,CA,O,C and B,O,DB,O,DB,O,D are each collinear in the stated orders. Which angle is vertical to ∠AOB\angle AOB∠AOB?
OA and OC are opposite rays, as are OB and OD. Thus angle AOB and angle COD are the opposite, vertical angles at O.
In the crossing configuration, A,O,CA,O,CA,O,C and B,O,DB,O,DB,O,D are collinear in order. In addition, AB∥CDAB\parallel CDAB∥CD. What is a valid second angle match for proving △AOB∼△COD\triangle AOB\sim\triangle COD△AOB∼△COD?
Use AC as a transversal of AB and CD. The angles at A and C are alternate interior angles, so they are equal. Together with the vertical angles at O, they give AA.
Angles AAA and BBB of triangle ABCABCABC match angles PPP and QQQ of triangle PQRPQRPQR. Which dilation factor makes the included side ABABAB match PQPQPQ?
The image side must equal PQ. Multiply the original side AB by the image-to-original ratio.
Equal angle pairs are AAA to PPP and BBB to QQQ. A dilation has made ACACAC equal to PRPRPR. Without finding another angle, which earlier congruence criterion applies to the dilated triangle and PQRPQRPQR?
The matched side AC lies outside the two selected angle vertices A and B. Two angle pairs plus that nonincluded side give AAS congruence. ASA would require the side between the selected angle vertices.
Two triangles are known similar. One pair of corresponding angles has measures (3x+8)∘(3x+8)^\circ(3x+8)∘ and 86∘86^\circ86∘. Find xxx.
Corresponding angle measures are equal; no length scale is applied to them.
It is given that △ABC∼△XYZ\triangle ABC\sim\triangle XYZ△ABC∼△XYZ. Which equation consistently compares second-triangle lengths with first-triangle lengths?
The ordered statement pairs AB with XY and BC with YZ. Put lengths from XYZ above their matching lengths from ABC in both fractions.
Two similar triangles have scale factor 1, but one is turned and reflected. Which statement is correct?
A factor of one leaves corresponding lengths equal. Turns and reflections are rigid motions, so the triangles are congruent regardless of their present orientation or position.
Given △ABC∼△RQP\triangle ABC\sim\triangle RQP△ABC∼△RQP, suppose
Find RPRPRP.
The statement pairs A with R and C with P, so AC corresponds to RP. The factor from ABC to RQP is two.
RP=2⋅9,=18.\begin{aligned}RP&=2\cdot 9,\\&=18.\end{aligned}RP=2⋅9,=18.
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