Dilations and Scale Factors

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Learning goals

  • Locate image points from a center and a positive scale factor
  • Calculate scaled lengths and coordinates, including centers away from the origin
  • Describe fixed points and the images of lines under a dilation
  • Distinguish a uniform dilation from a stretch in one direction

Resize from a center

A dilation tells every point how far to sit from one chosen point. Suppose a point PP is 44 units from OO. To scale from OO by a factor of 32\frac 32, place P′P' on ray OPOP, 66 units from OO.

OP′=32⋅4,=6.\begin{aligned}OP'&=\frac32\cdot4,\\&=6.\end{aligned}

The mark P′P' is read “PP prime.” It names the image, the point after the transformation; PP is the original point, or preimage. The ray fixes the direction, so the distance does not leave us choosing between two opposite sides of OO.

Scale the distance from the centerThe center O is the ray’s endpoint. P is 4 units from O and P prime is 6 units from O, on the same ray. The drawing shows an enlargement with scale factor three halves.OPP′OP = 4OP′ = 6
The image stays on the same ray from O, at the scaled distance. Here the factor is three halves.

A dilation with center OO and positive scale factor kk maps each point P≠OP\ne O to the point P′P' on ray OPOP satisfying the rule below. The center itself maps to OO.

OP′=k⋅OP.OP'=k\cdot OP.

The same center and factor apply to every point of a figure, not just its vertices. Join the images of the vertices to draw the image polygon.

Zero and negative scale factors are outside this lesson. A fraction need not mean reduction; 54\frac 54 is greater than 11.

Check your understanding

A point is 1818 units from the center. Its image is on the same ray, 1212 units from the center. What is the scale factor?

Answer choices

Investigate what changes

A single factor appears to resize the whole figure without changing its angles. Test that claim in the figure. Blue solid edges show the original; red dashed edges show its image.

One factor changes lengths while angles keep their opening

The center O is (-1, -1). The positive scale factor is 1.5. This is an enlargement. Only O is fixed. AB is 3 units long. A′B′ is 4.5 units long. Angle CAB and angle C′A′B′ each measure about 63.4°. Line m passes through O and maps onto the same line as a set. Line ℓ is away from O and maps onto a distinct parallel line ℓ′. Blue solid triangle ABC and its red dashed image share center-to-vertex guide rays from O. Horizontal line m passes through O. Horizontal line ℓ contains AB and its image ℓ′ contains A′B′. Only drawn portions of lines and rays are shown. Paired names merge when the image coincides with the original. ABCA′B′C′O m = m′ ℓ ℓ′ Blue solid original · Red dashed image
Center x Center y Scale factor

The center O is (-1, -1). The positive scale factor is 1.5. This is an enlargement. Only O is fixed. AB is 3 units long. A′B′ is 4.5 units long. Angle CAB and angle C′A′B′ each measure about 63.4°. Line m passes through O and maps onto the same line as a set. Line ℓ is away from O and maps onto a distinct parallel line ℓ′.

Guide rays connect O to matching vertices. Line m passes through O; line ℓ stays away from O. Only portions of the lines and rays are drawn.
  1. Keep the center still. Set the scale factor to 0.50.5, then 11, then 22. Compare ABAB with A′B′A'B' and compare the two displayed angles.
  2. Choose a factor other than 11 and change each center coordinate. Follow the guide rays. Does each vertex image remain on its ray from the new center?
  3. Watch the lines. Line mm contains OO. Line ℓ\ell does not. Compare each line with its image, and then test k=1k=1 again.

At k=2k=2, the 33-unit side becomes 66 units; at k=0.5k=0.5, it becomes 1.51.5 units. The angle opening stays the same. The away-center line shifts, while the line through the center still occupies the same straight path. With scripting unavailable, the displayed state shows one enlargement; the same comparisons can be checked with a ruler and protractor on a paper drawing.

Measurements support these patterns, but a few drawings cannot prove them for every figure. We explicitly accept the following dilation properties as foundations for the geometry that follows. We will use them to establish later results, rather than use those later results to prove them here.

These accepted properties will be the foundation for similarity in the next lesson.

Preserving an angle means preserving its measure, even when its vertex moves. Scaling a side means multiplying the distance between its endpoints, even when neither endpoint is the center.

Worked example 1 Read one factor in three ways

Problem. A dilation with center OO sends PP to P′P'. The distances OPOP and OP′OP' are 88 cm and 66 cm. A segment QRQR has length 1414 cm, and an angle at QQ measures 42∘42^\circ. Find the scale factor, the image length Q′R′Q'R', and the image angle at Q′Q'.

Solution. Put image distance over original distance.

k=68,=34.\begin{aligned}k&=\frac68,\\&=\frac34.\end{aligned}

This is a reduction. Apply the same factor to the segment, although OO need not be one of its endpoints.

Q′R′=34⋅14,=10.5 cm.\begin{aligned}Q'R'&=\frac34\cdot14,\\&=10.5\text{ cm}.\end{aligned}

The image angle measures 42∘42^\circ. Angles are preserved; their measures are not multiplied by 34\frac 34.

Check your understanding

A dilation has scale factor 11. A line does not pass through the center. What is its image?

Answer choices

Coordinates measure from the center

With the origin as center, multiply both coordinates by the scale factor. For example, a factor of 33 sends (2,−1)(2,-1) to (6,−3)(6,-3). The horizontal displacement and the vertical displacement from the origin both triple, so the point stays in the same direction from the origin.

For a dilation centered at (0,0)(0, 0), the rule is

(x,y)⟼(kx,ky).(x,y)\longmapsto(kx,ky).

Worked example 2 Use the origin rule

Problem. Dilate T(−4,3)T(-4, 3) about the origin by a scale factor of 1.51.5. Find T′T' and classify the dilation.

Solution. Multiply each coordinate by 1.51.5, keeping the sign of each displacement.

x′=1.5(−4),=−6,y′=1.5(3),=4.5.\begin{aligned}x'&=1.5(-4),\\&=-6,\\y'&=1.5(3),\\&=4.5.\end{aligned}

The image is T′(−6,4.5)T'(-6, 4.5). Since 1.5>11.5>1, this is an enlargement.

When the center is away from the origin, measure the displacements from that center first. Multiplying the raw coordinates would resize from the wrong point.

Worked example 3 Move halfway from a different center

Problem. A dilation has center O(2,−1)O(2,-1) and scale factor 12\frac 12. Find the image of P(6,3)P(6, 3).

Solution. From OO to PP, move 44 units right and 44 units up. Halving those displacements gives 22 units right and 22 units up. Start those new moves at OO, not at the origin.

x′=2+12(6−2),=4,y′=−1+12(3−(−1)),=1.\begin{aligned}x'&=2+\frac12(6-2),\\&=4,\\y'&=-1+\frac12(3-(-1)),\\&=1.\end{aligned}

Thus P′=(4,1)P'=(4, 1). It lies halfway along the segment from OO to PP.

Coordinates relative to the stated centerThe point O is at (2, -1), P is at (6, 3), and its image P prime is at (4, 1), halfway along the ray from O through P. Grid spacing is one unit.xy0O(2, -1)P(6, 3)P′(4, 1)
Subtract the center coordinates, scale those displacements, then start again at the center.

The same three moves work for any center O(a,b)O(a,b). Subtract a,ba,b to measure from OO, multiply both displacements by kk, then add a,ba,b to return to the original coordinate system.

x′=a+k(x−a),y′=b+k(y−b).\begin{aligned}x'&=a+k(x-a),\\y'&=b+k(y-b).\end{aligned}

The coordinates a,ba,b locate the center; kk is the scale factor. The origin rule is the special case where both center coordinates are zero.

Check your understanding

A dilation has center (1,2)(1, 2) and scale factor 22. Where does (4,5)(4, 5) map?

Answer choices

Fixed points and unchanged lines

A fixed point has its own location as its image. The center is always fixed because its distance from itself is zero. At scale factor 11, all points are fixed.

For a different scale factor, a point away from the center cannot stay put. A point 55 units from OO, for example, moves to distance 1010 when k=2k=2. In general, staying put would require both

OP′=OPOP′=k⋅OP.\begin{aligned}OP'&=OP\\OP'&=k\cdot OP.\end{aligned}

Since OPOP is positive away from the center, dividing by it forces k=1k=1. Thus when k≠1k\ne 1, the center is the only fixed point.

A line can stay the same as a set while its points move. On a line through OO, scaling sends points along its two opposite rays, and every location on that line is the image of some point. With k=2k=2, a point 33 units from OO moves to the location 66 units from OO; the original 33-unit location is now occupied by the image of the point 1.51.5 units from OO. The entire line remains, but its individual points are not all fixed.

Worked example 4 Recover the center from a point and its image

Problem. A dilation with scale factor 22 sends P(1,3)P(1, 3) to P′(5,7)P'(5, 7). Find its center O(a,b)O(a,b).

Solution. The move from PP to P′P' is 44 right and 44 up. When the distance from the center doubles, that move equals the move from OO to PP. Go 44 left and 44 down from PP to locate O(−3,−1)O(-3,-1).

Check with the coordinate rule.

5=a+2(1−a),a=−3,7=b+2(3−b),b=−1.\begin{aligned}5&=a+2(1-a),\\a&=-3,\\7&=b+2(3-b),\\b&=-1.\end{aligned}

The center is (−3,−1)(-3,-1). Both coordinate equations give the same dilation, and O,P,P′O,P,P' lie on the required ray in that order.

A stretch changes the shape

Making every horizontal distance twice as large while keeping vertical distances unchanged is a stretch in one direction. It uses different factors for different directions, so it is not a dilation of the plane.

Worked example 5 Test whether one factor works

Problem. A transformation sends (x,y)(x,y) to (2x,y)(2x,y). Consider O(0,0)O(0, 0), A(2,0)A(2, 0) and B(0,2)B(0, 2). Decide whether their images could come from one dilation, and justify your decision using lengths.

Solution. The images are O′(0,0)O'(0, 0), A′(4,0)A'(4, 0) and B′(0,2)B'(0, 2). The horizontal segment OAOA, originally 22 units long, becomes 44 units long. It requires a scale factor of 22.

The vertical segment OBOB, also 22 units long, stays 22 units long. It requires a scale factor of 11.

One dilation cannot give two different length factors. These three images therefore do not come from a single dilation, whatever center we try.

A stretch uses different factors in different directionsThe original triangle has two perpendicular legs of length 2. The dashed image has horizontal leg 4 and vertical leg 2. The shared vertical endpoints have paired labels.OAA′B = B′Horizontal length doubles; vertical length stays fixed.
A uniform dilation would multiply both of these lengths by the same number. This stretch does not.

Some angles can survive a stretch, such as the right angle between these horizontal and vertical legs. One unchanged angle does not establish that the whole transformation is a dilation. Check one common center, the ray condition, and one common factor for all points.

Check your understanding

A transformation doubles every horizontal distance but leaves every vertical distance unchanged. Which observation rules out a dilation?

Answer choices

Common mistakes

Practice

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A bit of history (optional)

Before a digital image could be resized with a slider, drawing instruments could make enlarged or reduced copies. A pantograph linked movable bars to a tracing point and a drawing point. Following the original with one point guided the other across the paper.

The Jesuit astronomer and mathematician Christoph Scheiner devised a wooden pantograph in 1603 and described it in a book published in 1631. Other makers later built brass and ebony versions. These were practical copying tools, not just mathematical demonstrations. The Smithsonian’s collection of pantographs includes instruments from the nineteenth and twentieth centuries and describes how the same copying principle reached printing and textile design.

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