Chapter Review · a rapid pre-test review (speedrun)

Solid Geometry: Chapter Review

A rapid review before the test: the chapter's vocabulary and notation, every formula with the conditions to use it, the standard problem types step by step, and the traps that cost points.

Vocabulary and notation

Polyhedron
A solid bounded entirely by polygonal faces. The straight segments shared by faces are edges, and the corners are vertices; a circular rim is not a polyhedron edge.
Prism and pyramid
A prism joins two congruent parallel polygonal bases by parallel edges. A pyramid joins one polygonal base to an off-plane apex by triangular faces. Circular counterparts are the cylinder and cone.
Right and oblique
A right prism’s joining edges and a right cylinder’s axis are perpendicular to their base planes. A right cone’s apex is directly over its base center; obliqueness concerns the solid, regardless of page orientation.
Parallel and skew lines
Distinct parallel lines are coplanar and disjoint. Skew lines are noncoplanar, so they neither meet nor run parallel.
Lines and planes
Distinct planes are parallel or intersect in a complete line. A line parallel to a plane has no point in it; a perpendicular line meets every plane line through its foot at a right angle.
Net
A connected flat arrangement of surface pieces that folds into the complete boundary without gaps or overlapping interiors. Cut edges can meet again; separated faces can become neighbors.
Orthographic view
A projection along parallel sight lines. Front records width and height; top, width and depth; right, depth and height.
Cross-section and axis of rotation
A cross-section is the intersection with a plane, with no thickness. An axis of rotation is the fixed line about which a filled plane region turns to sweep out a solid.
Base area BB, perimeter PP, height hh
B and P measure one base. Height h is perpendicular separation between base planes or from an apex to its base plane.
Slant height ℓ\ell and apothem aa
A regular pyramid’s slant height is its common triangular face altitude; its base apothem joins the center to a side midpoint. A right cone’s slant height joins its apex to the base rim.
Lateral and total surface area
Lateral area excludes bases. Total area counts the stated boundary, including any exposed rear or cavity surfaces.
Sphere, ball, great circle
A sphere is the surface at a fixed positive distance from its center; a ball is that surface and its interior. A central cut gives a great circle with the sphere radius.
Annulus
The ring between concentric circles. A thick open pipe has annular ends, an outer wall, and an inner bore wall.
Similar solids
Uniformly resized copies, allowing a move, turn, or reflection. Every corresponding length uses one positive factor.

Formulas and theorems

  • Prism and pyramid counts

    prism: (n+2, 3n, 2n)pyramid: (n+1, 2n, n+1)\begin{gathered} \text{prism: }(n+2,\,3n,\,2n)\\ \text{pyramid: }(n+1,\,2n,\,n+1) \end{gathered}

    Use when Counts are faces, edges, and vertices, in that order. The polygonal base has n≥3n\ge3 sides. Include hidden parts; changing a prism’s lean does not change the counts.

  • True section shapes

    Base-parallel sections repeat a prism or cylinder’s base, or shrink toward a pyramid or cone’s apex. A right cylinder’s axial section is rectangular; a right cone’s is isosceles triangular.

    Use when Interior cuts of positive area. An oblique section is elliptical if its entire closed boundary lies on the curved side of a right circular cylinder or cone, missing flat ends and any apex.

  • Cavalieri’s principle

    Two ordinary solids between the same parallel boundary planes have equal volumes if every parallel cutting plane gives equal section areas.

    Use when Align both solids over the same perpendicular height and compare every corresponding level. Section shapes may differ; matching only the base or several sampled levels is insufficient.

  • Prism and cylinder volume

    Vprism=BhVcylinder=πr2h\begin{gathered} V_{\text{prism}}=Bh\\ V_{\text{cylinder}}=\pi r^2h \end{gathered}

    Use when Positive base area and perpendicular height; positive radius for a circular cylinder. Applies to right and oblique cases.

  • Right prism boundary

    L=PhSclosed=Ph+2B\begin{gathered} L=Ph\\S_{\text{closed}}=Ph+2B \end{gathered}

    Use when Right prism only: its lateral rectangles share height h. Include only the bases present. For an oblique prism, use actual lateral face areas; their altitudes may differ from h.

  • Right cylinder boundary

    L=2πrhSclosed=2πrh+2πr2\begin{gathered} L=2\pi rh\\S_{\text{closed}}=2\pi rh+2\pi r^2 \end{gathered}

    Use when Right circular cylinder with positive radius and height. Its unrolled side is a rectangle of width equal to the circumference. Include zero, one, or two end disks as specified; thickness can add surfaces.

  • Pyramid and cone volume

    Vpyramid=13BhVcone=13πr2h\begin{gathered} V_{\text{pyramid}}=\tfrac13Bh\\V_{\text{cone}}=\tfrac13\pi r^2h \end{gathered}

    Use when Positive perpendicular height; a simple polygonal base of positive area or a circular base of positive radius. Applies to right and oblique cases, including a height foot outside the base.

  • Parallel sections of pointed solids

    length factor=thA(t)=B(th)2\begin{gathered} \text{length factor}=\frac th\\A(t)=B\left(\frac th\right)^2 \end{gathered}

    Use when Pyramid or circular cone, with B,h>0B,h>0. Measure perpendicular distance t from the apex toward a base-parallel section, 0≤t≤h0\le t\le h. For a level z above the base, use t=h−zt=h-z.

  • Perpendicular height and slant height

    right cone: ℓ2=h2+r2regular pyramid: ℓ2=h2+a2\begin{gathered} \text{right cone: }\ell^2=h^2+r^2\\\text{regular pyramid: }\ell^2=h^2+a^2 \end{gathered}
    Perpendicular height and slant height of a right coneHalf of a right cone’s axial section is a right triangle with apex V above base center O, and rim point M to the right. VO is the perpendicular height h, OM is the base radius r, and VM is the slant height ell. The right angle is at O. Slant height is the hypotenuse, separate from the perpendicular height.VOMhℓr
    Half of a right cone’s axial section.
    Text description

    Half of a right cone’s axial section is a right triangle with apex V above base center O, and rim point M to the right. VO is the perpendicular height h, OM is the base radius r, and VM is the slant height ell. The right angle is at O. Slant height is the hypotenuse, separate from the perpendicular height.

    Use when Positive dimensions. In the pyramid, a reaches a side midpoint, not a vertex; for square side s, a=s/2a=s/2. These right triangles require the stated right or regular solid.

  • Regular pyramid surface

    L=12PℓSclosed=12Pℓ+B\begin{gathered} L=\tfrac12P\ell\\S_{\text{closed}}=\tfrac12P\ell+B \end{gathered}

    Use when Convex regular base and apex directly above its center; all side faces share slant height ℓ\ell. If face altitudes differ, add their individual triangle areas instead. Include the base only when present.

  • Right cone surface and sector

    L=πrℓSclosed=πrℓ+πr2sector radius=ℓsector arc=2πrθ=360∘rℓ\begin{gathered} L=\pi r\ell\\S_{\text{closed}}=\pi r\ell+\pi r^2\\\text{sector radius}=\ell\\\text{sector arc}=2\pi r\\\theta=360^\circ\frac r\ell \end{gathered}

    Use when Right circular cone, r,h>0r,h>0, so ℓ>r\ell>r and 0<θ<360∘0<\theta<360^\circ. The whole selected arc becomes the rim without overlap. An open base adds no disk; an oblique cone has no single-slant-height shortcut.

  • Sphere measures and sections

    S=4πR2Vball=43πR3ρ2=R2−d2\begin{gathered} S=4\pi R^2\\V_{\text{ball}}=\tfrac43\pi R^3\\\rho^2=R^2-d^2 \end{gathered}

    Use when Sphere radius R>0R>0. A plane at perpendicular center distance 0≤d<R0\le d<R cuts a circle of radius ρ\rho; the ball section is its disk. At d=Rd=R it touches one point; at d>Rd>R it misses.

  • Hemisphere measures

    V=23πr3Scurved=2πr2Stotal=3πr2\begin{gathered} V=\tfrac23\pi r^3\\S_{\text{curved}}=2\pi r^2\\S_{\text{total}}=3\pi r^2 \end{gathered}
    A hemisphere has a curved cap and a flat diskThe curved cap of a hemisphere rises above its circular flat base disk, shown as an ellipse in perspective. A label above identifies the curved cap; a leader below identifies the flat disk. The curved cap and flat disk are separate boundary pieces; total hemisphere area includes both.Curved capFlat disk
    Text description

    The curved cap of a hemisphere rises above its circular flat base disk, shown as an ellipse in perspective. A label above identifies the curved cap; a leader below identifies the flat disk. The curved cap and flat disk are separate boundary pieces; total hemisphere area includes both.

    Use when Positive radius and a cut through the sphere center. Total includes one flat disk; curved area excludes it. A support covering that disk leaves only the uncovered cap exposed.

  • Exterior area at a join

    Sjoined=S1+S2−2AS_{\text{joined}}=S_1+S_2-2A

    Use when Two solids with nonoverlapping interiors share exactly one matching patch of area A. Start with both separate total surface areas; no other contacts or excluded surfaces.

  • Open right pipe

    V=π(R2−r2)hLouter=2πRhLinner=2πrhAring=π(R2−r2)S=Louter+Linner+2Aring\begin{gathered} V=\pi(R^2-r^2)h\\L_{\text{outer}}=2\pi Rh\\L_{\text{inner}}=2\pi rh\\A_{\text{ring}}=\pi(R^2-r^2)\\S=L_{\text{outer}}+L_{\text{inner}}+2A_{\text{ring}} \end{gathered}
    An open pipe has walls and annular endsTwo true sections of the same open right circular pipe are shown schematically. The end section is a ring of material around an empty circular bore. In the axial section, two rectangular strips of material border an empty passage which remains open at both ends. The inner bore wall and the two annular end rings are material surfaces as well as the outside wall.End sectionAxial sectionboreboreRing of materialOpen ends
    Text description

    Two true sections of the same open right circular pipe are shown schematically. The end section is a ring of material around an empty circular bore. In the axial section, two rectangular strips of material border an empty passage which remains open at both ends. The inner bore wall and the two annular end rings are material surfaces as well as the outside wall.

    Use when Outer radius R, inner r, length h: 0<r<R0<r<R and h>0h>0. A coaxial bore runs through the full length. V measures material. Include both walls and both end annuli for total exposed area; thickness is R−rR-r.

  • Rectangular box diagonal

    d=a2+b2+c2\begin{gathered} d=\sqrt{a^2+b^2+c^2} \end{gathered}

    Use when Positive perpendicular edge lengths a, b, c. First find a face diagonal, then combine it with the perpendicular third edge. The formula does not apply to an oblique box.

  • Uniform similarity powers

    k=image lengthoriginal length>0SiSo=k2ViVo=k3Si/ViSo/Vo=1k\begin{gathered} k=\frac{\text{image length}}{\text{original length}}>0\\\frac{S_i}{S_o}=k^2\\\frac{V_i}{V_o}=k^3\\\frac{S_i/V_i}{S_o/V_o}=\frac1k \end{gathered}

    Use when Similar solids with positive areas and volumes; i is image and o is original. Use consistent units and corresponding boundary pieces, including openings and joins. Surface area per volume has inverse-length units.

  • Recover a length scale

    k=SiSok=ViVo3\begin{gathered} k=\sqrt{\frac{S_i}{S_o}}\\k=\sqrt[3]{\frac{V_i}{V_o}} \end{gathered}

    Use when Similarity must already be established; use positive areas, volumes, and roots, with matching measured boundaries and units. A volume or area ratio alone does not prove similarity.

    e.g. For similar solids with volume ratio image:original 512:2197512:2197, find the length factor: 8/138/13.

Problem types, step by step

Classify a solid and its spatial relationships

  1. Identify the solid by its bases and joining structure. Count by structural groups, including hidden parts.
  2. Use complete lines and planes. In a rectangular box, opposite face planes are parallel and adjacent ones perpendicular.
  3. Name the complete intersection line of distinct planes from two distinct shared points.

Test a proposed net

  1. Hold one face fixed and follow its neighbors around their shared folds.
  2. Check opposing faces and corners; exactly three faces meet at a cube vertex. Verify full closure without overlapping interiors.

Reconstruct a solid from views

  1. Fix directions and match shared dimensions. A filled-column silhouette uses the greatest height along each sight line.
  2. Check a proposed solid against every view. Try varying hidden columns to test uniqueness.

Determine the true shape of a slice

  1. Name the plane relative to a base, axis, or apex. View the section directly in its plane.
  2. For a convex polyhedron cut containing no edge or vertex, trace one segment per crossed face.
  3. A rectangular box cut perpendicular to its base through a base diagonal gives a rectangle of that diagonal width and the full box height.

Match a filled region and a rotation axis

  1. Name the axis first. A rectangle about a side gives a right cylinder; a right triangle about a leg gives a right cone.
  2. The fixed side or leg gives height; the perpendicular reach gives radius. Reverse by halving the full axial width to recover the generator’s reach.
  3. A filled semicircular region about its diameter gives a whole ball; rotating just the arc gives the sphere.

e.g. Turn a 7.5 cm by 16 cm rectangle about a 16 cm side. Identify the result: a cylinder of height 16 cm and radius 7.5 cm.

Recover a dimension from volume

  1. Separate base geometry from the perpendicular solid height. Recover any needed length using a true right triangle.
  2. Choose the constant-section or one-third formula. Solve for the unknown, taking a positive root when needed.
  3. Check positivity, units, and every supplied geometric constraint.

e.g. For a pyramid with base area 48 cm248\text{ cm}^2 and volume 296 cm3296\text{ cm}^3, find its perpendicular height: 18.5 cm18.5\text{ cm}.

Find surface area or rebuild a net

  1. List the included boundary pieces, separating lateral surfaces from bases and openings.
  2. Find the actual face altitude or slant height using the appropriate right triangle. Apply only the right-solid or regular-pyramid shortcut justified by the givens.
  3. For a cone pattern, match sector radius to slant height and arc to circumference. Check positive height and the sector angle bounds.

Measure a composite or hollow object

  1. Split into pieces with nonoverlapping interiors; add occupied volumes and subtract cavities.
  2. List exposed patches independently: exclude internal joins and covered surfaces; include cavity walls, floors of blind holes, and annular rims where present.
  3. Recover missing component dimensions before calculating. Each hemispherical end adds one radius to axial length; two ends combine as one ball for volume and one sphere for curved area.

Use sections to recover a sphere

  1. For an off-center interior cut, the sphere radius is the right triangle’s hypotenuse. Its legs are the section radius and perpendicular center distance.
  2. Solve for the missing length. For a central cut, use the full sphere radius as the section radius.

Transfer or challenge a scale claim

  1. Establish one factor for all corresponding lengths and fix image-over-original direction. Convert units first.
  2. Recover the positive length factor from area or volume if needed; then use its appropriate power, or reciprocal for surface area per volume.
  3. If only one dimension changes, recalculate using the actual dimensions. Check all recorded measurements before accepting similarity.

e.g. For a similar resize with length factor 5/45/4 and original area 112 cm2112\text{ cm}^2, find the image area: 175 cm2175\text{ cm}^2.

Exam traps

  • Trap Trusting a perspective angle or apparent oval

    Fix Use stated spatial relationships and the cutting plane. A drawing can shorten lengths and show a true circle as an oval.

  • Trap Calling every pair of disjoint lines parallel

    Fix Check complete lines and coplanarity. Noncoplanar lines are skew; two edge segments not touching is insufficient evidence.

  • Trap Using a slanted length as volume height

    Fix Volume uses perpendicular separation. For pyramid and cone lateral area, use the face altitude or common slant height required by the formula.

  • Trap Using equal bases and heights for arbitrary solids

    Fix Cavalieri needs equal section areas at every corresponding height. Finite samples do not supply this requirement.

  • Trap Squaring the wrong radius or section fraction

    Fix Halve a diameter first. For pointed parallel sections, measure from the apex and square the length fraction for area.

  • Trap Halving sphere area for a whole hemisphere boundary

    Fix Half gives the curved cap only. Add one flat disk for total area; use half-ball volume for enclosed space.

  • Trap Turning the removed cone upside down in the hemisphere comparison

    Fix Place its apex at the cylinder’s bottom center and its base across the top. Cylinder radius and height are both R. At height z above the bottom, the removed radius is z; both retained sections have area π(R2−z2)\pi(R^2-z^2).

  • Trap Treating the radial sphere-area sketch as exact finite pyramids

    Fix Curved patches are replaced by flat approximations, whose heights approach the radius under refinement. The argument is informal and limiting.

  • Trap Subtracting an inner surface because volume was removed

    Fix Subtract removed volume but add newly exposed walls. A through bore removes two end patches; a blind cavity removes one and exposes a floor.

  • Trap Scaling only the visible dimensions or mismatching boundaries

    Fix Similarity powers require the entire solid and corresponding measured surfaces to scale together. A one-axis stretch needs direct formulas.

  • Trap Mixing length, area, volume, and capacity units

    Fix Use one length unit before calculating: area is squared, volume cubed, and S/VS/V has inverse-length units. 1 L=1000 cm31\text{ L}=1000\text{ cm}^3 and 1 mL=1 cm31\text{ mL}=1\text{ cm}^3; capacity uses inside dimensions.

Chapter Test Questions from across the chapter