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Adding and Subtracting Fractions

Learning goals

  • Add or subtract numerators once the denominators match
  • Explain why parts must be the same size before counting them
  • Rewrite unlike fractions over a common denominator first
  • Choose the least common denominator to keep the numbers small
  • Treat a whole number as a fraction over one, then combine
  • Simplify the answer to lowest terms at the end

Why the parts must be the same size

Think about why 3+2=53 + 2 = 5 never needs explaining. You are counting copies of a single unit, the apple, so you total the copies. A fraction is exactly the same kind of object: 25\frac{2}{5} means two copies of the unit “one fifth.” In the same way, 15\frac{1}{5} means one more copy of that same unit. Counting the copies gives three fifths:

25+15=35.\frac{2}{5} + \frac{1}{5} = \frac{3}{5}.

The denominator stayed 55 because the size of the piece never changed; only the count went up. Fractions add by counting parts, and counting only works when the parts are identical. A fifth and a fifth can be tallied together. A half and a third cannot, in the same way that two apples and three oranges are not five of any single thing. They only become five of something once you describe both as, say, five pieces of fruit. So the rule splits into two cases: when the denominators already match, you add at once. When they do not match, your first job is to make them match.

Two fifths plus one fifth. The pieces are all the same size, so you just count them: 2 shaded plus 1 more shaded makes 3 shaded, and each piece is still a fifth, giving 3/5. Rectangular bars divided into equal parts, with some parts shaded to show a fraction. 2 5 1 5 3 5
Two fifths plus one fifth. The pieces are all the same size, so you just count them: 2 shaded plus 1 more shaded makes 3 shaded, and each piece is still a fifth, giving 3/5.

Adding and subtracting with the same denominator

When two fractions share a denominator, they are built from identical pieces, so you combine them by working only with the numerators. For example,

38+18=3+18=48=12,\frac{3}{8} + \frac{1}{8} = \frac{3 + 1}{8} = \frac{4}{8} = \frac{1}{2},

Three eighths is three of those pieces, and one eighth is one more, so together you are holding four of them. Only the count changed, so the denominator is still 88. The last step divides the top and bottom by their greatest common factor 44, exactly the simplifying skill from the previous lesson.

Like-denominator rule. For any whole numbers aa, bb, and cc with cc not zero, ac+bc=a+bcandacbc=abc.\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c} \qquad\text{and}\qquad \frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}. Here aa and bb are the two numerators, and cc is the denominator they share.

Why same-denominator fractions add by adding the numerators#

Run the argument on 411+311\frac{4}{11} + \frac{3}{11} first. Cutting a whole into 1111 equal parts makes each part 111\frac{1}{11}. So 411\frac{4}{11} is 44 copies of 111\frac{1}{11}, and 311\frac{3}{11} is 33 more copies of that same piece. Lining them up gives 77 copies of 111\frac{1}{11}, and 77 copies of 111\frac{1}{11} is the fraction 711\frac{7}{11}. Running it backwards, taking those 33 copies away again leaves 44 copies, which is 411\frac{4}{11}.

Nothing in that depended on the numbers 44, 33 and 1111. Recall from the first fractions lesson that a fraction is built from unit fractions: ac\frac{a}{c} is aa copies of the unit 1c\frac{1}{c}. The reason is that cutting a whole into cc equal parts makes each part 1c\frac{1}{c}, and ac\frac{a}{c} takes aa of them.

So ac\frac{a}{c} is aa copies of 1c\frac{1}{c}, and bc\frac{b}{c} is bb more copies of the very same unit 1c\frac{1}{c}. Lining them all up, you are holding a+ba + b copies of 1c\frac{1}{c} in total. By that same meaning, a+ba + b copies of 1c\frac{1}{c} is the fraction a+bc\frac{a + b}{c}. Therefore

ac+bc=a+bc.\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}.

Subtraction is the same argument run the other way. Taking bb copies of 1c\frac{1}{c} away from aa copies leaves aba - b copies, which is abc\frac{a - b}{c}. The denominator never moves, because the size of the unit piece, 1c\frac{1}{c}, is exactly what stays fixed. Only the number of those pieces changes.

So the procedure with like denominators is short: add (or subtract) the numerators and keep the common denominator. Then simplify the result to lowest terms. A common slip is to add the denominators too, writing 38+18=416\frac{3}{8} + \frac{1}{8} = \frac{4}{16}. That is wrong, because the denominator names the size of the piece. The pieces also did not get smaller when you put two groups of them together, so 88 stays 88.

Check your understanding

What is 59+29\frac{5}{9} + \frac{2}{9}?

Answer choices

Unlike denominators: make the pieces match first

When the denominators differ, the pieces are different sizes and cannot be counted together yet. The fix is the building rule from the last lesson: rewrite each fraction as an equivalent one over a denominator they share. Then the like-denominator rule finishes the job.

Take 12+13\frac{1}{2} + \frac{1}{3}. Halves and thirds are different sizes, so picture cutting both into a size they have in common. Sixths work: a half is three sixths, and a third is two sixths. Once both are written in sixths, they are made of identical pieces and you can count:

One half rewritten as 3/6 and one third rewritten as 2/6. Now every piece is a sixth, so 3 sixths plus 2 sixths is 5 sixths. Rectangular bars divided into equal parts, with some parts shaded to show a fraction. 3 6 2 6 5 6
One half rewritten as 3/6 and one third rewritten as 2/6. Now every piece is a sixth, so 3 sixths plus 2 sixths is 5 sixths.

To rewrite 12\frac{1}{2} in sixths, the denominator goes from 22 to 66 by multiplying by 33, so the numerator does too: 12=1×32×3=36\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}. To rewrite 13\frac{1}{3} in sixths, the denominator goes from 33 to 66 by multiplying by 22: 13=1×23×2=26\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}. Now both are sixths, so add the numerators:

12+13=36+26=3+26=56.\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{3 + 2}{6} = \frac{5}{6}.

Notice what the common denominator 66 is: it is a multiple of both 22 and 33. Being a multiple of both is what lets each fraction be rebuilt over 66. Any common multiple of the two denominators would serve. We could rewrite both over 1212 instead and still get the right answer, just with larger numbers to simplify at the end. The cleanest choice is the smallest common multiple, and you already know how to find it.

You can do that rebuilding yourself.

Which finer cuts of thirds can also be counted in fourths

2/3 = 4/6. Each part is cut into two, so 4 of 6 parts are shaded. 6 is not a multiple of 4, so 4ths cannot be counted in 6ths. Two bars of the same width. The top bar is cut into 3 equal parts with 2 shaded. The bottom bar shows the same shaded length cut into finer parts. Use the controls below the figure to change how fine the cut is. 2 3 4 6
Cut each part into

2/3 = 4/6. Each part is cut into two, so 4 of 6 parts are shaded. 6 is not a multiple of 4, so 4ths cannot be counted in 6ths.

The same two thirds twice. The top bar is cut into thirds, and you choose how finely each of those parts is cut on the bottom bar.

Say the problem were 23+14\frac{2}{3} + \frac{1}{4}. Fourths cannot be counted alongside thirds, so hunt for a cut that lands on a denominator fourths can reach as well. Cutting each third into 44 gives 812\frac{8}{12}, and a fourth can be rewritten in twelfths, so that cut does the job. Cutting into 88 gives 1624\frac{16}{24}, which also works, with numbers twice as large for the same sum. Try the other cuts: 11, 22, 33, 55, 66 and 77 all produce denominators that no whole number of fourths can reach.

Whichever cut you pick, keep an eye on the shaded length. It never moves, because the bar is still two thirds and only its name has changed. That is what makes rewriting a fraction safe in the middle of an addition.

The least common denominator

A common denominator of two fractions is any common multiple of their denominators. The least common denominator (LCD) is the smallest one. For 12\frac{1}{2} and 13\frac{1}{3} the denominators are 22 and 33, whose common multiples run 6,12,186, 12, 18 and on. The smallest is 66, which is why 66 was the natural choice above.

So the LCD is exactly the least common multiple of the two denominators, from the factors chapter:

LCD of ab and cd  =  lcm(b,d).\text{LCD of } \tfrac{a}{b} \text{ and } \tfrac{c}{d} \;=\; \operatorname{lcm}(b, d).

Using the LCD keeps the numbers as small as possible, so there is less arithmetic and usually less simplifying at the end. The full method for unlike denominators is four steps:

  1. Find the LCD, the least common multiple of the two denominators.
  2. Rewrite each fraction as an equivalent fraction over the LCD, using the building rule.
  3. Add or subtract the numerators, keeping the common denominator.
  4. Simplify the result to lowest terms.

Each rewrite in step 2 is an equality, so nothing about the two amounts changes on the way to the common denominator. All that changes is the size of the pieces they are counted in. Once both are counted in the same pieces, step 3 is the like-denominator rule again.

Worked example 1 Compute 23+14\frac{2}{3} + \frac{1}{4}

The denominators 33 and 44 are different, so find the least common denominator first. The least common multiple of 33 and 44 is 1212, so the LCD is 1212.

Rewrite each fraction over 1212 with the building rule. For 23\frac{2}{3}, the denominator goes from 33 to 1212 by multiplying by 44, so the numerator does too:

23=2×43×4=812.\frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12}.

For 14\frac{1}{4}, the denominator goes from 44 to 1212 by multiplying by 33:

14=1×34×3=312.\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}.

Now both are twelfths, so add the numerators and keep the denominator:

23+14=812+312=8+312=1112.\frac{2}{3} + \frac{1}{4} = \frac{8}{12} + \frac{3}{12} = \frac{8 + 3}{12} = \frac{11}{12}.

Finally, check lowest terms: 1111 and 1212 share no factor above 11, so 1112\frac{11}{12} is the final answer.

Worked example 2 Compute 5638\frac{5}{6} - \frac{3}{8}

Subtraction follows the very same plan. The denominators 66 and 88 differ, so find the LCD. The least common multiple of 66 and 88 is 2424, so the LCD is 2424.

Rewrite each fraction over 2424. For 56\frac{5}{6}, the denominator goes from 66 to 2424 by multiplying by 44:

56=5×46×4=2024.\frac{5}{6} = \frac{5 \times 4}{6 \times 4} = \frac{20}{24}.

For 38\frac{3}{8}, the denominator goes from 88 to 2424 by multiplying by 33:

38=3×38×3=924.\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24}.

Both are twenty-fourths now, so subtract the numerators:

5638=2024924=20924=1124.\frac{5}{6} - \frac{3}{8} = \frac{20}{24} - \frac{9}{24} = \frac{20 - 9}{24} = \frac{11}{24}.

Check lowest terms: 1111 and 2424 share no factor above 11, so 1124\frac{11}{24} is the final answer.

Check your understanding

To compute 14+56\frac{1}{4} + \frac{5}{6}, what is the least common denominator you should use?

Answer choices

When one denominator is already a multiple of the other

Sometimes the larger denominator is itself a multiple of the smaller one. Take 16+712\frac{1}{6} + \frac{7}{12}. Since 1212 is a multiple of 66 (because 6×2=126 \times 2 = 12), the least common multiple of 66 and 1212 is 1212, so the LCD is 1212. The fraction 712\frac{7}{12} is already over 1212 and stays as it is; only 16\frac{1}{6} needs rebuilding:

16=1×26×2=212,so16+712=212+712=912=34.\frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}, \qquad\text{so}\qquad \frac{1}{6} + \frac{7}{12} = \frac{2}{12} + \frac{7}{12} = \frac{9}{12} = \frac{3}{4}.

The last step simplifies 912\frac{9}{12} by dividing the top and bottom by their greatest common factor 33. Whenever the larger denominator is a multiple of the smaller one, the LCD is that larger denominator. Only the fraction with the smaller denominator has to be rewritten, so spotting a pair like this saves half the work.

Adding a whole number to a fraction

A whole number can join a fraction the same way, once you remember that every whole number is a fraction with denominator 11. To add 2+352 + \frac{3}{5}, write 22 as 21\frac{2}{1}, then give it the denominator 55 so the pieces match. The LCD of 11 and 55 is 55, and 21=2×51×5=105\frac{2}{1} = \frac{2 \times 5}{1 \times 5} = \frac{10}{5}, which just says two wholes is ten fifths. Then add:

2+35=105+35=10+35=135.2 + \frac{3}{5} = \frac{10}{5} + \frac{3}{5} = \frac{10 + 3}{5} = \frac{13}{5}.

The improper fraction 135\frac{13}{5} is a complete and correct answer. (Rewriting it as a whole-number part plus a fraction is the subject of the later lesson on mixed numbers.) The same idea handles a subtraction like 1271 - \frac{2}{7}: write 1=771 = \frac{7}{7}, so that 127=7727=571 - \frac{2}{7} = \frac{7}{7} - \frac{2}{7} = \frac{5}{7}.

Worked example 3 Compute 71014\frac{7}{10} - \frac{1}{4} and simplify

The denominators 1010 and 44 differ, so find the LCD. The least common multiple of 1010 and 44 is 2020, so the LCD is 2020. To see why, list the multiples of 1010: they are 10,20,10, 20, \ldots, and 2020 is the first that 44 also divides.

Rewrite each fraction over 2020. For 710\frac{7}{10}, multiply top and bottom by 22:

710=7×210×2=1420.\frac{7}{10} = \frac{7 \times 2}{10 \times 2} = \frac{14}{20}.

For 14\frac{1}{4}, multiply top and bottom by 55:

14=1×54×5=520.\frac{1}{4} = \frac{1 \times 5}{4 \times 5} = \frac{5}{20}.

Subtract the numerators over the common denominator:

71014=1420520=14520=920.\frac{7}{10} - \frac{1}{4} = \frac{14}{20} - \frac{5}{20} = \frac{14 - 5}{20} = \frac{9}{20}.

Check lowest terms: 99 and 2020 share no factor above 11, so 920\frac{9}{20} is the final answer.

Check your understanding

What is 1381 - \frac{3}{8}?

Answer choices

Common mistakes

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Why a common denominator does not change the answer

The lesson rewrites both fractions over a common denominator and then adds the numerators. This shows that the rewrite never moves either amount, so the sum it produces is the true one, for any common denominator at all.

Why rewriting over a common denominator gives the correct sum#

Run it on 79+512\frac{7}{9} + \frac{5}{12} first, rewriting both over 3636, a common multiple of 99 and 1212. Since 36=9×436 = 9 \times 4, the building rule turns 79\frac{7}{9} into 7×436=2836\frac{7 \times 4}{36} = \frac{28}{36}. Since 36=12×336 = 12 \times 3, it turns 512\frac{5}{12} into 5×336=1536\frac{5 \times 3}{36} = \frac{15}{36}. Both are thirty-sixths now, so the like-denominator rule gives 2836+1536=4336\frac{28}{36} + \frac{15}{36} = \frac{43}{36}. Each rewrite was an equality, so 4336\frac{43}{36} is exactly the sum we started with.

Nothing in those steps depended on the particular numbers, only on 3636 being a common multiple of 99 and 1212. So let the two fractions be ab\frac{a}{b} and cd\frac{c}{d}, and let mm be any nonzero common multiple of bb and dd. Then there are nonzero whole numbers ss and tt with m=b×sm = b \times s and m=d×tm = d \times t.

By the building rule, multiplying the top and bottom of a fraction by the same number does not change its value, so

ab=a×smandcd=c×tm.\frac{a}{b} = \frac{a \times s}{m} \qquad\text{and}\qquad \frac{c}{d} = \frac{c \times t}{m}.

Now both rewrites have the same denominator mm, meaning they are made of pieces of the identical size 1m\frac{1}{m}. The like-denominator rule then applies exactly:

ab+cd=a×sm+c×tm=(a×s)+(c×t)m.\frac{a}{b} + \frac{c}{d} = \frac{a \times s}{m} + \frac{c \times t}{m} = \frac{(a \times s) + (c \times t)}{m}.

The choice of which common multiple to use for mm affects only the size of the numbers, never the value. Taking m=lcm(b,d)m = \operatorname{lcm}(b, d) simply makes that mm as small as possible.

A bit of history (Optional)

In the 1980s an American burger chain built a new sandwich. It carried a third of a pound of beef. The quarter pound its rivals sold was smaller, and cost the same money. Almost nobody bought it.

The chain went looking for the reason, and the answer has been retold ever since. Customers believed they were being cheated. Three is smaller than four, so a third of a pound sounded like less. The number on top of a fraction had swallowed all their attention.

The real trouble is comparing 33 against 44 as ordinary counts, which is what the customers did. The pieces are different sizes, so the counts on top are counting different things. Cut both into twelfths and the argument is over. A third becomes four twelfths, and a quarter becomes three twelfths. The pieces match now, so the bigger count really is the bigger amount. Finding that shared denominator is the step this lesson turns into a rule.