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Multiplying and Dividing Fractions

Learning goals

  • Multiply numerators and denominators, with no common denominator needed
  • Read a fraction of a fraction as rows against columns
  • Cancel a common factor before multiplying to keep numbers small
  • Flip the divisor to turn division into multiplication
  • Explain why multiplying by the reciprocal is the same as dividing

What “a fraction of a fraction” means

When you see 12×6\frac{1}{2} \times 6, you already read it as half of six, which is 33. The word of is what multiplication means here, and it does not change when the second number is also a fraction. So 12×13\frac{1}{2} \times \frac{1}{3} means one half of one third: start with one third of a whole, then take half of that piece.

Picture a single whole as a square. Slice it into thirds with two vertical cuts and shade one of the three strips. That shaded strip is 13\frac{1}{3} of the square. Now take half of just that strip by cutting it across the middle. Half of the strip is a smaller rectangle, and the question is what fraction of the whole square that small rectangle is. Extend the horizontal cut all the way across and you can count. The square is now divided into 66 equal small rectangles, and the doubly shaded piece is exactly one of them. So one half of one third is one sixth:

12×13=16.\frac{1}{2} \times \frac{1}{3} = \frac{1}{6}.
Area model of one half times one third equals one sixthA unit square cut into thirds vertically and halves horizontally, giving six equal rectangles. One vertical strip is one third; half of that strip is one of the six rectangles, which is one sixth.1/3 of width1/2 of height
One third of the square is shaded as a vertical strip. Taking half of that strip (the darker piece) cuts the whole square into 6 equal rectangles, and the darker piece is 1 of them. So one half of one third is one sixth.

Look at where the 66 came from. The whole square was cut into thirds across its width and into halves down its height. The two sets of cuts make the number of small rectangles the denominators multiplied together, 3×2=63 \times 2 = 6. The doubly shaded piece is the overlap of “one of the thirds” and “one of the halves.” So the number of shaded rectangles is the numerators multiplied together, 1×1=11 \times 1 = 1. Multiply the bottoms to count the pieces in the new whole, and multiply the tops to count how many of those pieces you keep.

The rule for multiplying fractions

The same picture works when each fraction keeps more than one part. Take 23×45\frac{2}{3} \times \frac{4}{5}, which reads as two thirds of four fifths:

23×45=2×43×5=815.\frac{2}{3} \times \frac{4}{5} = \frac{2 \times 4}{3 \times 5} = \frac{8}{15}.
Area model of two thirds times four fifths equals eight fifteenthsA unit square cut into five columns and three rows, giving fifteen equal rectangles. Four fifths of the width and two thirds of the height overlap in a block of eight rectangles, which is eight fifteenths.4 of 5 columns2 of 3 rows
Two thirds of four fifths. The square is cut into 5 columns and 3 rows, making 15 equal rectangles. Four of the columns and two of the rows overlap in a block of 4 times 2, that is 8, shaded rectangles, so the product is 8/15.

The five columns and three rows cut the square into 1515 equal rectangles, which is where the 1515 comes from. The kept block is 22 rows crossing 44 columns, so it covers 88 of them, and that is the 88. Simplify the answer whenever you can: here 88 and 1515 share no factor above 11, so 815\frac{8}{15} is already in lowest terms.

Multiplication rule. For any fractions ab\frac{a}{b} and cd\frac{c}{d} with bb and dd not zero, ab×cd=a×cb×d.\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}.

The square diagram shows the rule for fractions between 00 and 11, where you shade part of one whole. The very same rule, multiply the tops and multiply the bottoms, carries over to improper fractions and to whole numbers. A whole number is a fraction over 11, so 5×27=51×27=1075 \times \frac{2}{7} = \frac{5}{1} \times \frac{2}{7} = \frac{10}{7}. You just may end up with a result larger than one whole.

Check your understanding

What is 34×25\frac{3}{4} \times \frac{2}{5}, written in lowest terms?

Answer choices

Cancelling before you multiply

Multiplying the tops and bottoms first and simplifying afterward always works, but the numbers can grow large and then need a big simplification. There is a shortcut that keeps the numbers small: cancel any common factor between a numerator and a denominator before multiplying.

Take 34×89\frac{3}{4} \times \frac{8}{9}. Before multiplying, notice that 33 on top shares the factor 33 with 99 on the bottom. The 88 on top also shares the factor 44 with the 44 on the bottom. Divide each pair by its common factor. The 33 becomes 11 and the 99 becomes 33 after dividing both by 33. The 88 becomes 22 and the 44 becomes 11 after dividing both by 44:

34×89=11×23=1×21×3=23.\frac{3}{4} \times \frac{8}{9} = \frac{1}{1} \times \frac{2}{3} = \frac{1 \times 2}{1 \times 3} = \frac{2}{3}.

Multiplying the small leftovers gives 23\frac{2}{3} directly, in lowest terms, with no large product to reduce. To see that this is the same answer the long way gives, multiply first instead: 34×89=2436\frac{3}{4} \times \frac{8}{9} = \frac{24}{36}. Then 2436\frac{24}{36} simplifies by its greatest common factor 1212 to 23\frac{2}{3}. Same result, but cancelling first kept the numbers to single digits.

That cancel paired the 33 on top of one fraction with the 99 on the bottom of the other. It is allowed because the product is one fraction, 3×84×9\frac{3 \times 8}{4 \times 9}. In that single fraction the 33 is a numerator and the 99 is a denominator. Simplifying a fraction means dividing its top and its bottom by a common factor, exactly the rule from the equivalent-fractions lesson. So it makes no difference which of the two starting fractions each number came from.

Worked example 1 Compute 29×38\frac{2}{9} \times \frac{3}{8} by cancelling first

Look for common factors across the two fractions before multiplying. The numerator 22 and the denominator 88 share a factor of 22, and the numerator 33 and the denominator 99 share a factor of 33.

Divide the first pair by 22: the 22 becomes 11 and the 88 becomes 44. Divide the second pair by 33: the 33 becomes 11 and the 99 becomes 33. The product is now built from small numbers:

29×38=13×14=1×13×4=112.\frac{2}{9} \times \frac{3}{8} = \frac{1}{3} \times \frac{1}{4} = \frac{1 \times 1}{3 \times 4} = \frac{1}{12}.

Check the long way to be sure: 29×38=672\frac{2}{9} \times \frac{3}{8} = \frac{6}{72}, and dividing top and bottom by their greatest common factor 66 gives 112\frac{1}{12}. The two routes agree, and cancelling first avoided the awkward 672\frac{6}{72}.

The reciprocal of a fraction

The reciprocal of a nonzero fraction is what you get by swapping its numerator and denominator, that is by flipping it over. The reciprocal of 35\frac{3}{5} is 53\frac{5}{3}, and the reciprocal of 27\frac{2}{7} is 72\frac{7}{2}. A whole number such as 44 is 41\frac{4}{1}, so its reciprocal is 14\frac{1}{4}.

The reason the reciprocal matters is a single clean fact: a nonzero fraction times its reciprocal is always 11.

A nonzero fraction times its reciprocal equals 11#

Start with 58\frac{5}{8}, whose reciprocal is 85\frac{8}{5}. Multiplying tops and bottoms gives 58×85=5×88×5=4040\frac{5}{8} \times \frac{8}{5} = \frac{5 \times 8}{8 \times 5} = \frac{40}{40}. Top and bottom are the same product 4040, and a fraction whose top equals its bottom is 11.

Nothing there used the digits 55 and 88. Take any fraction ab\frac{a}{b} in which neither aa nor bb is zero, so that flipping it gives a genuine fraction ba\frac{b}{a}. Multiply the two using the multiplication rule:

ab×ba=a×bb×a.\frac{a}{b} \times \frac{b}{a} = \frac{a \times b}{b \times a}.

The numerator a×ba \times b and the denominator b×ab \times a are the same product in a different order, since multiplication does not care about order. A fraction whose numerator equals its denominator is 11, as the first fractions lesson showed:

a×bb×a=a×ba×b=1.\frac{a \times b}{b \times a} = \frac{a \times b}{a \times b} = 1.

The numerator aa has to be nonzero for the reciprocal to exist. Flipping 0b\frac{0}{b} would put a 00 in the denominator, which is undefined.

Two numbers whose product is 11 are called reciprocals of each other. You can read the relation both ways: 35×53=1\frac{3}{5} \times \frac{5}{3} = 1, so each is the reciprocal of the other. This is the multiplication version of how a number and its negative add to 00. There, adding the opposite undoes an addition; here, multiplying by the reciprocal undoes a multiplication.

Check your understanding

What is the reciprocal of 74\frac{7}{4}, and what do you get when you multiply 74\frac{7}{4} by it?

Answer choices

Why dividing by a fraction means multiplying by its reciprocal

Division asks a counting question: a÷ba \div b asks “how many bb‘s fit into aa?” Keep that meaning and apply it to fractions. The expression 34÷18\frac{3}{4} \div \frac{1}{8} asks “how many eighths fit into three fourths?” Three fourths is the same amount as six eighths, because 34=68\frac{3}{4} = \frac{6}{8}, and six eighths obviously holds six of the one-eighth pieces. So 34÷18=6\frac{3}{4} \div \frac{1}{8} = 6. Notice what flipping does here: 6=34×816 = \frac{3}{4} \times \frac{8}{1}, which is 34\frac{3}{4} times the reciprocal of 18\frac{1}{8}.

Division rule. To divide by a nonzero fraction, multiply by its reciprocal: ab÷cd=ab×dc.\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}.

The rule needs cc to be nonzero, because the reciprocal of 0d\frac{0}{d} would be d0\frac{d}{0}, and nothing can be divided by zero.

So to divide by a fraction, leave the first fraction alone, flip the second, and multiply, using the cancelling shortcut if it helps. For example,

23÷49=23×94=2×93×4=1812=32,\frac{2}{3} \div \frac{4}{9} = \frac{2}{3} \times \frac{9}{4} = \frac{2 \times 9}{3 \times 4} = \frac{18}{12} = \frac{3}{2},

where the last step divides top and bottom by their greatest common factor 66. A common slip is to flip the wrong fraction. Only the divisor, the fraction you are dividing by, gets turned over; the first fraction stays exactly as it is.

Rectangular bars divided into equal parts, with some parts shaded to show a fraction. 3 4 1 4
How many one-fourths fit into three-fourths? Three-fourths is three of the one-fourth pieces, so the answer is 3. This is why 3/4 divided by 1/4 equals 3, matching 3/4 times the reciprocal 4/1.

That picture answers the question for one size of piece. Below you can change the size. The top bar is fixed at three fourths. The bottom bar is that same three fourths, with each of its parts cut into as many pieces as you choose.

How many pieces of each size fit into three fourths

3/4 = 6/8. Each part is cut into two, so 6 of 8 parts are shaded. So 6 pieces of size 1/8 fit into the shaded part. Two bars of the same width. The top bar is cut into 4 equal parts with 3 shaded. The bottom bar shows the same shaded length cut into finer parts. Use the controls below the figure to change how fine the cut is. 3 4 6 8
Cut each part into

3/4 = 6/8. Each part is cut into two, so 6 of 8 parts are shaded. So 6 pieces of size 1/8 fit into the shaded part.

The same three fourths twice. The top bar is cut into fourths, and you choose how finely each of those parts is cut on the bottom bar.

The numerator on the bottom bar is the answer to a division. Cut each fourth into 22 and the bar reads 68\frac{6}{8}, so six eighths cover the same amount. That means six one-eighth pieces fit into three fourths, and 34÷18=6\frac{3}{4} \div \frac{1}{8} = 6. Cut into 33 instead and it reads 912\frac{9}{12}, so 34÷112=9\frac{3}{4} \div \frac{1}{12} = 9. Check that one against the rule: 34×121=364=9\frac{3}{4} \times \frac{12}{1} = \frac{36}{4} = 9, the same count.

Now run the cut all the way to its finest and watch which direction the count moves. The pieces keep shrinking and more of them fit, which is exactly why dividing by a smaller fraction gives a larger answer.

Worked example 2 Compute 56÷23\frac{5}{6} \div \frac{2}{3}

Dividing by 23\frac{2}{3} is multiplying by its reciprocal 32\frac{3}{2}. Rewrite the division as a multiplication, keeping the first fraction as it is:

56÷23=56×32.\frac{5}{6} \div \frac{2}{3} = \frac{5}{6} \times \frac{3}{2}.

Cancel before multiplying. The numerator 33 and the denominator 66 share a factor of 33, so the 33 becomes 11 and the 66 becomes 22:

56×32=52×12=5×12×2=54.\frac{5}{6} \times \frac{3}{2} = \frac{5}{2} \times \frac{1}{2} = \frac{5 \times 1}{2 \times 2} = \frac{5}{4}.

So 56÷23=54\frac{5}{6} \div \frac{2}{3} = \frac{5}{4}. Since 55 and 44 share no factor above 11, this is in lowest terms. The answer is more than 11, which makes sense: 56\frac{5}{6} is larger than 23\frac{2}{3}, so 23\frac{2}{3} fits into it more than once.

Worked example 3 Compute 6÷346 \div \frac{3}{4}

A whole number divides by a fraction the same way, once you write it over 11. Here 6=616 = \frac{6}{1}, and dividing by 34\frac{3}{4} means multiplying by its reciprocal 43\frac{4}{3}:

6÷34=61×43.6 \div \frac{3}{4} = \frac{6}{1} \times \frac{4}{3}.

Cancel the common factor 33 between the 66 on top and the 33 on the bottom. That turns the 66 into 22 and the 33 into 11:

61×43=21×41=2×41×1=8.\frac{6}{1} \times \frac{4}{3} = \frac{2}{1} \times \frac{4}{1} = \frac{2 \times 4}{1 \times 1} = 8.

So 6÷34=86 \div \frac{3}{4} = 8. This reads correctly as a counting question: how many three-quarter pieces fit into 66 wholes? Each whole holds 43\frac{4}{3} of them, and 66 wholes hold 88.

Check your understanding

What is 47÷821\frac{4}{7} \div \frac{8}{21}?

Answer choices

Common mistakes

Practice

Multiple Choice Questions (MCQ)

Progressively harder sets of questions. Each opens on its own page.

Free Response Questions (FRQ)

Longer questions in parts, to be worked out on paper. Progressive hints, the answer on its own so you can check yourself and try again, then the full worked solution, plus a rubric to mark your own work against.

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Why the grid counts every product, not just the ones drawn

The lesson draws the grid for 12×13\frac{1}{2} \times \frac{1}{3} and for 23×45\frac{2}{3} \times \frac{4}{5}. This runs the same count on any two fractions at once, which is what makes multiplying the tops and the bottoms a rule rather than a pattern.

Why multiplying fractions multiplies the tops and the bottoms#

Run the argument on 25×37\frac{2}{5} \times \frac{3}{7} first, and then on letters. That product is 25\frac{2}{5} of 37\frac{3}{7} of one whole, so draw the whole as a square.

Cut the square into 77 equal vertical strips and shade 33 of them, so the shaded region is 37\frac{3}{7} of the whole. Now cut the square into 55 equal horizontal rows and keep 22 of those rows over the part already shaded. The piece shaded both ways is 25\frac{2}{5} of 37\frac{3}{7}.

The two sets of cuts leave 77 columns and 55 rows, so the square holds 3535 equal small rectangles. The doubly shaded piece is 22 rows crossing 33 shaded columns, which is 66 of those rectangles. Six equal pieces out of 3535 equal pieces is 635\frac{6}{35}, so 25×37=635\frac{2}{5} \times \frac{3}{7} = \frac{6}{35}.

Now the same argument with letters, and nothing in it used the particular numbers 22, 55, 33 and 77. Read the product as a fraction of a fraction: ab×cd\frac{a}{b} \times \frac{c}{d} is ab\frac{a}{b} of cd\frac{c}{d} of one whole. Draw the whole as a square.

First mark off cd\frac{c}{d} of the square. Cut the square into dd equal vertical strips and shade cc of them, so the shaded region is cd\frac{c}{d} of the whole. Now take ab\frac{a}{b} of that shaded region. Cut the square into bb equal horizontal rows, and keep aa of those rows over the part already shaded. The piece shaded both ways is ab\frac{a}{b} of cd\frac{c}{d}, which is the product you want.

Count it with the grid the two sets of cuts create. The vertical cuts made dd columns and the horizontal cuts made bb rows. So the whole square is divided into b×db \times d equal small rectangles, all the same size. The doubly shaded region is aa rows of the kept part crossing cc shaded columns, so it covers a×ca \times c of those small rectangles. A region of a×ca \times c equal pieces out of b×db \times d equal pieces is, by the meaning of a fraction, a×cb×d\frac{a \times c}{b \times d}. Therefore

ab×cd=a×cb×d.\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}.

No common denominator entered anywhere, because we were never combining same-size parts the way addition does. We were cutting one whole two ways at once, and the grid did the counting.

Why cancelling early and simplifying late give the same answer

The lesson cancels 34×89\frac{3}{4} \times \frac{8}{9} down to 23\frac{2}{3} and checks it against the long way. This shows the two routes agree for any shared factor, so cancelling early can never cost you the right answer.

Why flipping the second fraction is what division asks for

The lesson counts how many eighths fit into three fourths and notices that flipping gives the same answer. This shows that flipping is forced: it produces the only number that answers the division question, for any two fractions.

Why ab÷cd=ab×dc\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}#

A quotient is a missing factor. Run that on 45÷27\frac{4}{5} \div \frac{2}{7}. It asks for the number QQ with Q×27=45Q \times \frac{2}{7} = \frac{4}{5}, the same way 12÷3=412 \div 3 = 4 because 4×3=124 \times 3 = 12. Multiply both sides by 72\frac{7}{2}, the reciprocal of 27\frac{2}{7}. On the left, 27×72=1\frac{2}{7} \times \frac{7}{2} = 1, so the left side is just QQ:

Q=45×72=2810=145.Q = \frac{4}{5} \times \frac{7}{2} = \frac{28}{10} = \frac{14}{5}.

Check it against the missing factor: 145×27=2835=45\frac{14}{5} \times \frac{2}{7} = \frac{28}{35} = \frac{4}{5}.

The letters run the same way, and nothing above needed the numbers 44, 55, 22 and 77. Saying ab÷cd=Q\frac{a}{b} \div \frac{c}{d} = Q means QQ is the number that multiplies cd\frac{c}{d} back up to ab\frac{a}{b}, that is

Q×cd=ab.Q \times \frac{c}{d} = \frac{a}{b}.

To find QQ, get rid of the cd\frac{c}{d} that is multiplying it. Multiply both sides by dc\frac{d}{c}, the reciprocal of cd\frac{c}{d}.

Q×cd×dc=ab×dc.Q \times \frac{c}{d} \times \frac{d}{c} = \frac{a}{b} \times \frac{d}{c}.

On the left, cd×dc=1\frac{c}{d} \times \frac{d}{c} = 1, because a fraction times its reciprocal is 11, and multiplying QQ by 11 leaves QQ unchanged. So the left side collapses to QQ, and

Q=ab×dc.Q = \frac{a}{b} \times \frac{d}{c}.

Dividing by cd\frac{c}{d} undoes a multiplication by cd\frac{c}{d}, and the move that undoes multiplying by a fraction is multiplying by its reciprocal. “Flip and multiply” is that one-line cancellation written as a slogan.

A bit of history (Optional)

Generations of students met division by a fraction as a rhyme: “Ours is not to reason why, just invert and multiply.”

The joke borrows its opening from a famous poem. In 1854 Alfred Tennyson, an English poet, wrote about a cavalry charge. The order was a blunder, and the riders knew it. They rode up the valley anyway. Theirs not to reason why, he wrote; theirs but to do and die.

Somebody in a classroom saw how neatly that fitted a rule nobody explained. Turning the divisor over works. It explains nothing, and it gets marked correct. Taught that way, a student is a soldier: told what to do, and told not to ask.

You are out of that position now. A nonzero fraction times its reciprocal is one, so flipping the divisor is the single move that clears it away. The rhyme is easier to remember than the proof. The proof is the reason the answer is right.