Mixed Numbers

Learning goals

  • Read a mixed number as a whole plus a proper fraction, and explain why that space means add
  • Convert an improper fraction to a mixed number by dividing with a remainder
  • Rewrite a mixed number as an improper fraction, keeping the denominator, then simplify if needed
  • Multiply or divide mixed numbers by first converting both to improper fractions
  • Add or subtract mixed numbers, carrying or borrowing a whole when needed

What a mixed number means

A mixed number is a whole number written directly beside a proper fraction, like 2342\tfrac{3}{4}, and it stands for their sum. By a long-standing convention, a whole number set beside a fraction means add:

234  =  2+34.2\tfrac{3}{4} \;=\; 2 + \tfrac{3}{4}.

So 2342\tfrac{3}{4} is read “two and three fourths,” and the word “and” is doing real work: it is the plus sign you do not write. The whole-number part counts complete wholes, and the fraction part counts the leftover that has not reached another whole. That fraction part is always a proper fraction, with a numerator smaller than its denominator. Picture three identical bars, each cut into fourths. Fill two of them completely and shade three fourths of the third, and the total shaded amount is 2342\tfrac{3}{4}.

Two whole bars fully shaded, plus three fourths of a third bar: together they show the mixed number 2 and 3/4. Rectangular bars divided into equal parts, with some parts shaded to show a fraction. 1 1 3 4
Two whole bars fully shaded, plus three fourths of a third bar: together they show the mixed number 2 and 3/4.

This is genuinely the same number as an improper fraction. Every one of those bars is cut into fourths, so count all the shaded fourths. The two full bars give 4+4=84 + 4 = 8 fourths, and the partial bar gives 33 more, for 1111 fourths in total. So the picture you just read as 2342\tfrac{3}{4} is the very same shaded amount as 114\frac{11}{4}:

234  =  114.2\tfrac{3}{4} \;=\; \frac{11}{4}.

Recall that 12\frac{1}{2} and 24\frac{2}{4} were two names for one value in the equivalent-fractions lesson. A mixed number and an improper fraction are therefore two names for one value in exactly the same way. A mixed number is easier to picture and to compare at a glance, since you can see immediately that 2342\tfrac{3}{4} sits between 22 and 33. An improper fraction is easier to calculate with: it is usually the more convenient form for multiplying or dividing, and addition or subtraction can use either an improper fraction or the whole and fraction parts directly.

Why “side by side” means add, not multiply

In algebra, writing a number directly beside a variable, like 2x2x, means multiply. Yet 2342\tfrac{3}{4} means 2+342 + \tfrac34, an addition. Why the exception?

It is a convention, kept because it is so useful for everyday measuring. Reading 2342\tfrac{3}{4} as a product would give 2×34=322 \times \tfrac34 = \tfrac{3}{2}, which is less than 22, an odd thing to write a "22" in front of. Reading it as a sum gives a value between 22 and 33, which matches what the leading 22 promises. That is not special to 2342\tfrac{3}{4}. A mixed number always pairs a whole number with a proper fraction, a fraction whose value is less than 11. If the two were meant to be multiplied, the result would be smaller than the whole number, because multiplying by a proper fraction shrinks a quantity.

Check your understanding

What does the mixed number 5235\tfrac{2}{3} stand for?

Answer choices

From an improper fraction to a mixed number

Sometimes an answer comes out as an improper fraction and you want to see its size. Going from 114\frac{11}{4} to 2342\tfrac{3}{4} is the conversion you reach for whenever that happens. The tool is division with remainder, the same idea that the very first fractions lesson used to read the fraction bar as a division.

Recall what the bar means: 114\frac{11}{4} is 11÷411 \div 4. So ask the plain division question, how many whole groups of 44 fit inside 1111, and what is left over? Four goes into 1111 two times, using up 88, and leaves a remainder of 33:

11÷4=2 remainder 3.11 \div 4 = 2 \text{ remainder } 3.

The quotient 22 counts the complete groups of four fourths, and four fourths is one whole. So 22 is the number of whole units, the whole-number part. The remainder 33 is the count of fourths that did not make it into a complete whole. So it is 33 leftover fourths, the fraction part 34\tfrac34. Putting the whole part and the leftover fraction together gives the mixed number:

114=234.\frac{11}{4} = 2\tfrac{3}{4}.

The leftover is always a proper fraction, and that is not luck. A remainder is by definition smaller than the number you divided by, so the remainder is always less than the denominator. That means the fraction part always has a numerator smaller than its denominator.

To rewrite an improper fraction as a mixed number, divide the numerator by the denominator. The quotient is the whole-number part, the remainder is the new numerator, and the denominator stays the same. Then simplify the fraction part if it is not already in lowest terms, the way 146=226=213\frac{14}{6} = 2\tfrac{2}{6} = 2\tfrac{1}{3} does. When the division comes out even, with remainder 00, the fraction is really a whole number. Then there is no fraction part at all, for example 124=3\frac{12}{4} = 3.

The grouping is worth doing with your hands. In the figure below, each dot is one of the equal parts. The row width is how many of those parts it takes to fill one whole. Set the dots to 1111 and the row width to 44 to lay out eleven fourths.

Reading a mixed number off the rows

11 dots in rows of 4 make 2 full rows with 3 dots left over. So 11/4 = 2 3/4 as a mixed number. Dots laid out in equal rows, filling from the top left. Dots that do not complete a row are drawn hollow. Use the controls below the figure to change the number of dots or the row width.
Dots Rows of

11 dots in rows of 4 make 2 full rows with 3 dots left over. So 11/4 = 2 3/4 as a mixed number.

Dots laid into equal rows, filling from the top left. Choose how many dots there are and how many go in each row; any dots that do not complete a row are drawn hollow.

Read the mixed number straight off the rows. Two complete rows are two whole units, and the hollow dots are the fourths that could not finish a third row. Those leftover fourths are the remainder that sits over the denominator, so 114=234\frac{11}{4} = 2\tfrac{3}{4}. Step the count down and the leftover shrinks, 33 then 22 then 11. It shrinks until at 88 dots the rows come out even, and 84\frac{8}{4} is the whole number 22 with no fraction part at all.

The row width is the denominator, so changing it changes what each dot represents. Put the count back to 1111 and set the row width to 33. The same eleven dots regroup into 33 full rows with 22 left over, which is the conversion 113=323\frac{11}{3} = 3\tfrac{2}{3} done by eye.

Check your understanding

Write 175\frac{17}{5} as a mixed number.

Answer choices

From a mixed number to an improper fraction

The reverse conversion is the one you do most often. To multiply or divide mixed numbers, you always rewrite them as improper fractions first; to add or subtract them, converting is one option, and combining the whole and fraction parts directly is often quicker.

A mixed number is a sum, 234=2+342\tfrac34 = 2 + \tfrac34, so the task is to add the whole number to the fraction. The adding and subtracting lesson in this chapter showed how to add a whole number to a fraction. Write the whole number over the common denominator. Each whole is 44\frac{4}{4}, because four fourths make one whole, so 22 wholes is 2×4=82 \times 4 = 8 fourths:

2=2×44=84.2 = \frac{2 \times 4}{4} = \frac{8}{4}.

Now both terms are fourths, so add the numerators:

234=84+34=8+34=114.2\tfrac{3}{4} = \frac{8}{4} + \frac{3}{4} = \frac{8 + 3}{4} = \frac{11}{4}.

Look at what the arithmetic actually did: it multiplied the whole number by the denominator and then added the numerator, all over the original denominator.

Multiply the whole number by the denominator, add the numerator, and write the result over the same denominator. For 3253\tfrac{2}{5} that is 3×5+2=173 \times 5 + 2 = 17 over 55, giving 175\frac{17}{5}, which matches the checkpoint above run in reverse. In this conversion step the denominator stays the same, because rewriting a whole number in fifths does not change the size of the pieces, only how many of them you have. (As with the reverse conversion, a later simplification can still change it.)

Check your understanding

Convert 5165\tfrac{1}{6} to an improper fraction.

Answer choices

Multiplying and dividing mixed numbers

Multiplication and division both use one strategy: turn each mixed number into an improper fraction, then apply the fraction rule you already know. Take 112×2131\tfrac12 \times 2\tfrac13. Rewrite each factor as an improper fraction, 112=321\tfrac12 = \frac{3}{2} and 213=732\tfrac13 = \frac{7}{3}, then multiply across and cancel where you can:

112×213=32×73=3×72×3=216=72=312.1\tfrac{1}{2} \times 2\tfrac{1}{3} = \frac{3}{2} \times \frac{7}{3} = \frac{3 \times 7}{2 \times 3} = \frac{21}{6} = \frac{7}{2} = 3\tfrac{1}{2}.

The last steps simplify 216\frac{21}{6} by its greatest common factor 33 to 72\frac{7}{2}. They then convert back to the mixed number 3123\tfrac12 by dividing 7÷2=37 \div 2 = 3 remainder 11.

For multiplication and division, converting first is the reliable method, and it always works. A tempting shortcut, multiplying the whole parts and the fraction parts separately, does not work. That is because a mixed number is a sum, and a product of sums is not the product of the parts. Division works the same way: convert, then flip and multiply, using the reciprocal of the divisor. Convert the answer back to a mixed number if the problem asks for that form.

Check your understanding

What is 223×1122\tfrac{2}{3} \times 1\tfrac{1}{2}, written as a mixed number or whole number?

Answer choices

Worked example 1 Compute 312÷1163\tfrac{1}{2} \div 1\tfrac{1}{6}

Convert each mixed number to an improper fraction. For 3123\tfrac12, the shortcut gives 3×2+1=73 \times 2 + 1 = 7 over 22, so 312=723\tfrac12 = \frac{7}{2}. For 1161\tfrac16, it gives 1×6+1=71 \times 6 + 1 = 7 over 66, so 116=761\tfrac16 = \frac{7}{6}.

Dividing by 76\frac{7}{6} means multiplying by its reciprocal 67\frac{6}{7}. Keep the first fraction and flip the second:

312÷116=72÷76=72×67.3\tfrac{1}{2} \div 1\tfrac{1}{6} = \frac{7}{2} \div \frac{7}{6} = \frac{7}{2} \times \frac{6}{7}.

Cancel before multiplying: the 77 on top cancels the 77 on the bottom. The 66 also shares a factor of 22 with the 22 on the bottom, leaving 33:

72×67=11×31=3.\frac{7}{2} \times \frac{6}{7} = \frac{1}{1} \times \frac{3}{1} = 3.

So 312÷116=33\tfrac12 \div 1\tfrac16 = 3, a whole number. The result reads sensibly: 1161\tfrac16 fits into 3123\tfrac12 exactly three times.

Check your understanding

What is 214÷1122\tfrac{1}{4} \div 1\tfrac{1}{2}, written as a whole or mixed number?

Answer choices

Adding and subtracting mixed numbers

Addition and subtraction can also be done by converting to improper fractions, and that always works. But there is a second method that is often quicker and matches how you would do it in your head. That method handles the whole parts and the fraction parts separately.

Take 214+1122\tfrac14 + 1\tfrac12. Add the whole numbers, 2+1=32 + 1 = 3, and separately add the fractions, 14+12\tfrac14 + \tfrac12. The fractions need a common denominator: 12=24\tfrac12 = \tfrac24, so 14+24=34\tfrac14 + \tfrac24 = \tfrac34. Combine the whole part and the fraction part:

214+112=(2+1)+(14+24)=3+34=334.2\tfrac{1}{4} + 1\tfrac{1}{2} = (2 + 1) + \left(\tfrac{1}{4} + \tfrac{2}{4}\right) = 3 + \tfrac{3}{4} = 3\tfrac{3}{4}.

This separate-parts method is allowed because addition lets you change the order of the terms and how they are grouped without changing the total: 2+14+1+122 + \tfrac14 + 1 + \tfrac12 can be reordered and rearranged as (2+1)+(14+12)(2 + 1) + (\tfrac14 + \tfrac12) without changing the total. When the fraction parts add up to 11 or more, the extra whole has to be carried over to the whole-number part. For instance 34+34=64=112\tfrac34 + \tfrac34 = \tfrac64 = 1\tfrac12, so that whole 11 joins the others. Subtraction has a different wrinkle: the fraction you are subtracting may be bigger than the fraction you have. When that happens, borrow one whole from the whole-number part and rewrite it as a fraction first.

Worked example 2 Compute 316+2343\tfrac{1}{6} + 2\tfrac{3}{4}

Add the whole parts and the fraction parts separately. The whole parts give 3+2=53 + 2 = 5.

For the fraction parts 16+34\tfrac16 + \tfrac34, find the least common denominator. The least common multiple of 66 and 44 is 1212, so rewrite each fraction over 1212:

16=212,34=912,212+912=1112.\tfrac{1}{6} = \tfrac{2}{12}, \qquad \tfrac{3}{4} = \tfrac{9}{12}, \qquad \tfrac{2}{12} + \tfrac{9}{12} = \tfrac{11}{12}.

The fraction total 1112\tfrac{11}{12} is already a proper fraction, so nothing carries. Combine the whole part and the fraction part:

316+234=5+1112=51112.3\tfrac{1}{6} + 2\tfrac{3}{4} = 5 + \tfrac{11}{12} = 5\tfrac{11}{12}.

Since 1111 and 1212 share no factor above 11, the fraction part is in lowest terms, so 511125\tfrac{11}{12} is the final answer.

Worked example 3 Compute 413−1564\tfrac{1}{3} - 1\tfrac{5}{6}

Put both fraction parts over their common denominator first, before deciding whether a borrow is needed. The least common denominator of 33 and 66 is 66, and 13=26\tfrac13 = \tfrac26, so the subtraction reads

413−156=426−156.4\tfrac{1}{3} - 1\tfrac{5}{6} = 4\tfrac{2}{6} - 1\tfrac{5}{6}.

Now the trouble is visible: 26\tfrac26 is smaller than 56\tfrac56, so it cannot be subtracted and leave a proper fraction behind. Borrow one whole from the 44, leaving 33, and hand that whole to the fraction part. One whole is 66\tfrac66, so the fraction part grows from 26\tfrac26 to 2+66=86\tfrac{2+6}{6} = \tfrac86:

426=3+66+26=386.4\tfrac{2}{6} = 3 + \tfrac{6}{6} + \tfrac{2}{6} = 3\tfrac{8}{6}.

The fraction part 86\tfrac86 is greater than 11. That is intentional: the borrow just traded one whole for six sixths, so there is now enough to subtract from. The fraction on the left is the bigger one, so the parts subtract without any further trouble. The whole parts give 3−1=23 - 1 = 2, and the fraction parts give 86−56=36\tfrac86 - \tfrac56 = \tfrac36:

386−156=236=212.3\tfrac{8}{6} - 1\tfrac{5}{6} = 2\tfrac{3}{6} = 2\tfrac{1}{2}.

Converting both numbers to improper fractions is the other route, and it needs no borrow at all. The shortcut turns 4134\tfrac13 into 133\frac{13}{3}, which is 266\frac{26}{6}, and turns 1561\tfrac56 into 116\frac{11}{6}. Subtracting gives 156\frac{15}{6}, which simplifies to 52\frac{5}{2}, the same 2122\tfrac12.

Check your understanding

What is 514−2235\tfrac{1}{4} - 2\tfrac{2}{3}, written as a mixed number?

Answer choices

Check your understanding

What is 134+2121\tfrac{3}{4} + 2\tfrac{1}{2}, written as a mixed number?

Answer choices

Common mistakes

Practice

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Why the division rule works for every improper fraction

The lesson turns 114\frac{11}{4} into 2342\tfrac{3}{4} by dividing 1111 by 44 and reading the quotient and remainder back through the fraction. This shows that the same division argument works for any improper fraction, which is what makes the rule dependable rather than a pattern spotted once.

Why dividing the numerator by the denominator gives the mixed number#

Run the whole argument once on 296\frac{29}{6}. Six goes into 2929 four times, using up 2424, and leaves 55, so 29=4×6+529 = 4 \times 6 + 5, and the leftover 55 is smaller than 66. Split the numerator along that line and separate the two pieces:

296=4×6+56=4×66+56=4+56=456.\frac{29}{6} = \frac{4 \times 6 + 5}{6} = \frac{4 \times 6}{6} + \frac{5}{6} = 4 + \frac{5}{6} = 4\tfrac{5}{6}.

The quotient 44 became the whole part, because 4×66\frac{4 \times 6}{6} cancels to 44. The leftover 55 became the numerator over the same 66, and it is a proper fraction because 55 is smaller than 66.

Nothing in that depended on the numbers 2929 and 66. Take any improper fraction nd\frac{n}{d}, so nn is at least dd. There are whole numbers qq (the quotient) and rr (the remainder) with

n=q×d+r,0≤r<d.n = q \times d + r, \qquad 0 \le r < d.

Here qq groups of dd account for q×dq \times d, and rr is whatever is left, necessarily less than dd or another whole group would fit.

Using the rule for adding fractions over a common denominator, run backwards,

nd=q×d+rd=q×dd+rd.\frac{n}{d} = \frac{q \times d + r}{d} = \frac{q \times d}{d} + \frac{r}{d}.

The first piece simplifies, because q×dd\frac{q \times d}{d} divides top and bottom by dd to give the whole number qq. The second piece is rd\frac{r}{d}, and since r<dr < d, it is a proper fraction. So

nd=q+rd=q rd,\frac{n}{d} = q + \frac{r}{d} = q\,\tfrac{r}{d},

which is the mixed number whose whole part is the quotient and whose fraction part is the remainder over the original denominator. That reading needs rr to be more than zero. If rr is zero there is no fraction part, and the answer is the whole number qq by itself.

Why the shortcut works for every mixed number

The lesson turns 2342\tfrac{3}{4} into 114\frac{11}{4} by writing the 22 as 84\frac{8}{4} and adding. This shows that the same two steps work for any whole number and any proper fraction, which is what makes the shortcut a rule rather than a pattern spotted once.

Why a mixed number wabw\tfrac{a}{b} equals w×b+ab\frac{w \times b + a}{b}#

Run the whole argument once on 5375\tfrac{3}{7}, which means 5+375 + \tfrac{3}{7}. One whole is 77\tfrac{7}{7}, so five wholes is 5×7=355 \times 7 = 35 sevenths. Both parts are sevenths now, so add the numerators:

537=357+37=35+37=387.5\tfrac{3}{7} = \frac{35}{7} + \frac{3}{7} = \frac{35 + 3}{7} = \frac{38}{7}.

The 3535 on top came from multiplying the whole part 55 by the denominator 77, and the 33 was the numerator that was already there.

Nothing in that depended on the numbers 55, 33 and 77. Take any mixed number wabw\tfrac{a}{b}, where ww is the whole-number part and ab\frac{a}{b} is a proper fraction. By the meaning of the notation it is the sum

wab=w+ab.w\tfrac{a}{b} = w + \frac{a}{b}.

Since one whole is bb\frac{b}{b}, the whole number ww is ww copies of that, which is w×bb\frac{w \times b}{b}. This is the building rule from equivalent fractions, applied to w=w1w = \frac{w}{1}:

w=w×bb.w = \frac{w \times b}{b}.

Both terms are now over bb, so add the numerators using the like-denominator rule:

w+ab=w×bb+ab=w×b+ab.w + \frac{a}{b} = \frac{w \times b}{b} + \frac{a}{b} = \frac{w \times b + a}{b}.

So wab=w×b+abw\tfrac{a}{b} = \frac{w \times b + a}{b}: multiply the whole number by the denominator, add the numerator, and keep the denominator.

A bit of history (optional)

A Roman builder measuring a beam had no decimals and no calculator. What he had was twelfths.

The Romans cut their basic unit into twelve equal parts. One part was called an uncia. Twelve was a shrewd choice, because it divides evenly by two, three, four and six. A length or a weight was then written as so many whole units and so many twelfths. That is a whole number with a leftover attached, which is a mixed number in everything but notation.

The word itself never went away, because it became both the inch and the ounce. A foot still holds twelve inches for the same old reason.

The habit survives in any workshop. A carpenter reading a tape measure usually says two and a quarter inches, rather than nine fourths. The whole part gives the size at a glance, and the fraction gives the rest. That is the trade this lesson makes between the two forms, and both forms still have a job.