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Chapter Review · a rapid pre-test review (speedrun)

Fractions: Chapter Review

A rapid review before the test: the chapter's vocabulary and notation, every formula with the conditions to use it, the standard problem types step by step, and the traps that cost points.

Vocabulary and notation

Numerator and denominator
In ab\frac{a}{b}, the denominator bb names the SIZE of each part (the whole was cut into bb EQUAL parts) and the numerator aa COUNTS how many of them you have.
Unit fraction 1b\frac{1}{b}
One single equal part. Every fraction is a count of these: ab\frac{a}{b} is aa copies of 1b\frac{1}{b}.
Proper fraction
Numerator smaller than the denominator, so the value is less than 11.
Improper fraction
Numerator at least the denominator, so the value is 11 or more. 44\frac{4}{4} is improper yet equals exactly 11, and an improper answer is never a wrong form to leave.
Equivalent fractions
Two fractions naming the same number, such as 12\frac{1}{2} and 24\frac{2}{4}. They share one lowest-terms form.
Lowest terms (simplest form)
The numerator and denominator share no common factor above 11, so nothing is left to divide out.
Mixed number wabw\tfrac{a}{b}
A whole number beside a proper fraction, standing for their SUM: wab=w+abw\tfrac{a}{b} = w + \tfrac{a}{b}. The space means plus, not times.

Formulas and theorems

  • The bar means divide

    ab=a÷b\frac{a}{b} = a \div b

    Use when b0b \neq 0. Top divided by bottom, so 34\frac{3}{4} is 3÷43 \div 4, never 4÷34 \div 3.

    e.g. 5÷8=585 \div 8 = \frac{5}{8}, and 123=4\frac{12}{3} = 4.

  • Zero and one inside a fraction

    nn=1,n1=n0b=0,a0 is undefined\begin{gathered} \frac{n}{n} = 1, \qquad \frac{n}{1} = n \\ \frac{0}{b} = 0, \qquad \frac{a}{0} \text{ is undefined} \end{gathered}

    Use when n0n \neq 0 in the first two, b0b \neq 0 in the third. A numerator of 00 is fine; a denominator of 00 is not, since no number times 00 returns a nonzero aa.

  • Comparing at a glance

    Same denominator: the larger NUMERATOR is larger. Same numerator: the SMALLER denominator is larger, because fewer cuts make bigger parts.

    Same numerator: fewer cuts make bigger parts, so three quarters beats three seventhsTwo identical horizontal bars. The upper bar, labelled 3/4, is divided into four equal parts with the left three shaded. The lower bar, labelled 3/7, is divided into seven equal parts with the left three shaded. Both shade three parts, but the upper shading covers far more of the bar. A note below reads fewer cuts, bigger parts.3/43/7fewer cuts, bigger parts
    Text description

    Two equal bars each with three parts shaded: the quarters on the upper bar cover far more length than the sevenths on the lower one.

    Use when One of the two numbers must genuinely match. A shared numerator must be nonzero, since 03\frac{0}{3} and 05\frac{0}{5} both equal 00.

    e.g. 58>38\frac{5}{8} > \frac{3}{8}, and 34>37\frac{3}{4} > \frac{3}{7}.

  • Building rule

    ab=a×cb×c\frac{a}{b} = \frac{a \times c}{b \times c}
    One half and two quarters shade the same length of the same barTwo identical horizontal bars, one above the other. The upper bar is divided into two equal parts with the left part shaded, labelled 1/2. The lower bar is divided into four equal parts with the left two shaded, labelled 2/4. A dashed vertical line runs down through the right edge of both shaded regions, marked same length, showing the two shadings cover exactly the same portion of the bar.1/22/4same length
    Text description

    Two equal bars, one cut into halves with one part shaded and one cut into quarters with two shaded, whose shadings stop at the same point.

    Use when b0b \neq 0 and c0c \neq 0. The multiplier hits BOTH numbers, and it multiplies rather than adds: 1+12+1\frac{1+1}{2+1} is 23\frac{2}{3}, a different number from 12\frac{1}{2}.

  • Simplifying rule

    ab=a÷cb÷c\frac{a}{b} = \frac{a \div c}{b \div c}

    Use when cc must be a common factor, dividing BOTH aa and bb exactly, with c0c \neq 0 and b0b \neq 0. Dividing by the greatest common factor reaches lowest terms in one step.

  • Cross-product test for equality

    ab=cdexactly whena×d=b×c\frac{a}{b} = \frac{c}{d} \quad \text{exactly when} \quad a \times d = b \times c

    Use when b0b \neq 0 and d0d \neq 0. It runs both ways, so differing products prove the fractions differ. Each numerator pairs with the OTHER denominator, so a×ba \times b tests nothing.

    e.g. 610\frac{6}{10} and 915\frac{9}{15}: 6×15=90=10×96 \times 15 = 90 = 10 \times 9, so they are equal.

  • Like-denominator rule

    ac+bc=a+bc,acbc=abc\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}, \qquad \frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

    Use when c0c \neq 0, and the SAME cc in both. The denominator never moves, and only the numerators combine.

    e.g. 911411=511\frac{9}{11} - \frac{4}{11} = \frac{5}{11}.

  • Least common denominator

    LCD of ab and cd=lcm(b,d)\text{LCD of } \tfrac{a}{b} \text{ and } \tfrac{c}{d} = \operatorname{lcm}(b, d)

    Use when The denominators are whole numbers, so the LCD is a whole NUMBER, with b0b \neq 0 and d0d \neq 0. Any common multiple works, including b×db \times d; the least one only keeps the numbers small. When one denominator divides the other, the LCD is the larger one.

    e.g. lcm(6,8)=24\operatorname{lcm}(6, 8) = 24, but lcm(6,12)=12\operatorname{lcm}(6, 12) = 12.

  • Multiplication rule

    ab×cd=a×cb×d\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}

    Use when b0b \neq 0 and d0d \neq 0. No common denominator is wanted or needed. A whole number joins as n=n1n = \frac{n}{1}.

  • Cancelling before multiplying

    A factor shared by any numerator and any denominator of the product divides out of both first, taken from either fraction.

    Use when The cancel pairs a NUMERATOR with a DENOMINATOR, never a top with a top. It must divide the WHOLE numerator, never one term of a sum: in a+cb\frac{a + c}{b} a factor of aa alone cancels nothing.

    e.g. 29×38\frac{2}{9} \times \frac{3}{8}: cancel 22 with 88 and 33 with 99, leaving 13×14=112\frac{1}{3} \times \frac{1}{4} = \frac{1}{12}.

  • A fraction times its reciprocal

    ab×ba=1\frac{a}{b} \times \frac{b}{a} = 1

    Use when The reciprocal swaps numerator and denominator, so it needs a0a \neq 0 as well as b0b \neq 0: flipping 0b\frac{0}{b} would put 00 underneath. Every number but 00 has one.

    e.g. 35×53=1\frac{3}{5} \times \frac{5}{3} = 1, and the reciprocal of 6=616 = \frac{6}{1} is 16\frac{1}{6}.

  • Division rule (flip the divisor)

    ab÷cd=ab×dc\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

    Use when b0b \neq 0, d0d \neq 0, and the divisor must be nonzero, so c0c \neq 0. ONLY the divisor flips; the first fraction is left exactly as it is.

  • Mixed number and improper fraction

    wab=w×b+abnd=qrd   where   n=q×d+r\begin{gathered} w\tfrac{a}{b} = \frac{w \times b + a}{b} \\ \frac{n}{d} = q\tfrac{r}{d} \;\text{ where }\; n = q \times d + r \end{gathered}
    Two wholes and three quarters is eleven quarters in allThree equal bars in a row, each divided into four equal parts. The first two bars are labelled 1 and fully shaded; the third is labelled 3/4, with its left three parts shaded and its last part empty. Each shaded part carries a number, running 1 to 11 from left to right, and a note below reads count the quarters: 11.113/41234567891011count the quarters: 11
    Text description

    Two whole bars cut into quarters plus a third bar with three of its quarters shaded, numbering eleven shaded quarters in all.

    Use when b0b \neq 0, d0d \neq 0, and a<ba < b, so the fraction part is proper. The denominator never changes in either direction. A remainder is always below the divisor, so 0r<d0 \le r < d; when r=0r = 0 the value is the whole number qq.

Problem types, step by step

Name a fraction from a picture, a story, or a number line

  1. Count the equal parts the whole was cut into for the denominator, and the parts taken for the numerator.
  2. To place it, split the segment from 00 to 11 into bb equal steps and count aa of them, continuing past 11 for an improper fraction.
  3. Check the size: numerator below denominator lands before 11, equal on 11, above past 11.

e.g. A bar in 88 equal parts with 55 shaded is 58\frac{5}{8}, five steps along a 00-to-11 segment cut into eighths.

Find a fraction of a quantity, or recover the whole from a part

  1. Divide the quantity by the denominator for the size of one part, then multiply by the numerator.
  2. For "how much is left", subtract from the total, or take the leftover fraction instead.
  3. Backwards, from a part to the whole: divide by the numerator, then multiply by the denominator.

e.g. 35\frac{3}{5} of 4545: 45÷5=945 \div 5 = 9, then 3×9=273 \times 9 = 27; backwards, if 25\frac{2}{5} of a number is 88, the number is 8÷2×5=208 \div 2 \times 5 = 20.

Compare or order fractions

  1. Take the matching-denominator or matching-numerator shortcut when one applies.
  2. Otherwise rewrite every fraction over one common denominator and compare the new numerators; for just two, cross products settle it.
  3. List the ORIGINAL fractions in the answer, not the rewritten ones.

e.g. 56\frac{5}{6} against 79\frac{7}{9} over 1818: 1518>1418\frac{15}{18} > \frac{14}{18}, so 56\frac{5}{6} is larger.

Build an equivalent fraction with a required denominator

  1. Ask what the old denominator was multiplied by to reach the new one.
  2. Multiply the numerator by that same number.
  3. If the missing number is the denominator instead, read the multiplier off the two numerators and apply it to the bottom.

e.g. 712=?60\frac{7}{12} = \frac{?}{60}: since 12×5=6012 \times 5 = 60, the numerator is 7×5=357 \times 5 = 35.

Simplify a fraction to lowest terms

  1. Find the greatest common factor of the numerator and denominator, and divide both by it in one step.
  2. Confirm the result shares no factor above 11.
  3. If you divided by a smaller common factor, the answer is correct but unfinished, so simplify again.

e.g. 5490\frac{54}{90} has GCF=18\operatorname{GCF} = 18, so 54÷1890÷18=35\frac{54 \div 18}{90 \div 18} = \frac{3}{5}.

Add or subtract two fractions

  1. Matching denominators: go straight to the numerators. Otherwise find the LCD.
  2. Rebuild each fraction over the LCD, multiplying top and bottom by the same number.
  3. Add or subtract the numerators, keep the common denominator, then simplify.
  4. A whole number enters over the common denominator, so 11 becomes cc\frac{c}{c}.

e.g. 38+512\frac{3}{8} + \frac{5}{12} over the LCD 2424: 924+1024=1924\frac{9}{24} + \frac{10}{24} = \frac{19}{24}.

Multiply fractions

  1. Write any whole number over 11 and any mixed number as an improper fraction.
  2. Cancel each factor shared by a numerator and a denominator, taken from either fraction.
  3. Multiply the remaining tops together and the remaining bottoms together, then simplify anything missed.

e.g. 512×815\frac{5}{12} \times \frac{8}{15}: cancel 44 from 88 and 1212, and 55 from 55 and 1515, giving 13×23=29\frac{1}{3} \times \frac{2}{3} = \frac{2}{9}.

Divide by a fraction

  1. Write any whole number over 11 and any mixed number as an improper fraction.
  2. Leave the first fraction alone and replace the divisor by its reciprocal, turning ÷\div into ×\times.
  3. Cancel, multiply across, and simplify.

e.g. 710÷1425=710×2514=12×52=54\frac{7}{10} \div \frac{14}{25} = \frac{7}{10} \times \frac{25}{14} = \frac{1}{2} \times \frac{5}{2} = \frac{5}{4}.

Convert between an improper fraction and a mixed number

  1. Improper to mixed: divide numerator by denominator; the quotient is the whole part, the remainder is the new numerator.
  2. Mixed to improper: multiply the whole number by the denominator, then add the numerator.
  3. Keep the denominator either way, simplify the fraction part, and read a remainder of 00 as a plain whole number.

e.g. 476\frac{47}{6}: 47÷6=747 \div 6 = 7 remainder 55, so 7567\tfrac{5}{6}; back the other way, 7×6+5=477 \times 6 + 5 = 47.

Multiply or divide mixed numbers

  1. Convert every mixed number to an improper fraction first, without exception.
  2. Multiply across, or flip the divisor and multiply, cancelling as you go.
  3. Simplify, then convert back to a mixed number if the question asks for that form.

e.g. 334×115=154×65=92=4123\tfrac{3}{4} \times 1\tfrac{1}{5} = \frac{15}{4} \times \frac{6}{5} = \frac{9}{2} = 4\tfrac{1}{2}.

Add or subtract mixed numbers, carrying or borrowing

  1. Combine the whole parts, and separately combine the fraction parts over their LCD.
  2. Adding: if the fraction total reaches 11 or more, convert it and carry its whole into the whole-number total.
  3. Subtracting: if the fraction being taken away is the larger one, borrow 11 from the whole part and add it to the fraction as cc\frac{c}{c} first.
  4. Converting both to improper fractions instead always works and skips the carry and the borrow.

e.g. 5142235\tfrac{1}{4} - 2\tfrac{2}{3}: over 1212 that is 531228125\tfrac{3}{12} - 2\tfrac{8}{12}, so borrow to 415122812=27124\tfrac{15}{12} - 2\tfrac{8}{12} = 2\tfrac{7}{12}.

Exam traps

  • Trap Adding the denominators along with the numerators, so 25+15\frac{2}{5} + \frac{1}{5} is written as 310\frac{3}{10}.

    Fix The answer is 35\frac{3}{5}: the denominator names the piece size, and combining groups of fifths does not shrink the pieces, so only the counts add.

  • Trap Cancelling a number that sits in a SUM, such as striking the bb's in w×b+ab\frac{w \times b + a}{b}.

    Fix Cancelling divides a factor out of the whole numerator, and being one term of a sum does not make a number a factor of it. 234=2×4+34=1142\tfrac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{11}{4}, and 44 does not divide 1111; cancelling the 44s would claim 2+3=52 + 3 = 5.

  • Trap Cancelling a numerator against another numerator, or a denominator against another denominator.

    Fix Every cancel pairs one top with one bottom. In 34×38\frac{3}{4} \times \frac{3}{8} the two 33s are both on top, so nothing cancels and the answer is 932\frac{9}{32}, not 132\frac{1}{32}.

  • Trap Flipping the first fraction in a division, or forgetting to flip and multiplying straight across.

    Fix Only the divisor turns over: 56÷23=56×32=54\frac{5}{6} \div \frac{2}{3} = \frac{5}{6} \times \frac{3}{2} = \frac{5}{4}. Straight across gives 59\frac{5}{9}, and flipping the first gives 45\frac{4}{5}, the reciprocal of the answer.

  • Trap Ordering fractions with a shared numerator by their denominators, smallest denominator first.

    Fix More cuts make smaller pieces, so the order reverses: 34\frac{3}{4}, 37\frac{3}{7}, 310\frac{3}{10} runs from greatest to least.

  • Trap Calling a fraction simplified after dividing out a common factor that was not the greatest.

    Fix Halving 1824\frac{18}{24} gives 912\frac{9}{12}, which still shares a factor of 33. Divide by the greatest common factor 66 once to reach 34\frac{3}{4}.

  • Trap Multiplying mixed numbers part by part, whole against whole and fraction against fraction.

    Fix A mixed number is a sum, and a product of sums is not the product of the parts. 214×1132\tfrac{1}{4} \times 1\tfrac{1}{3} is 94×43=3\frac{9}{4} \times \frac{4}{3} = 3, not the 21122\tfrac{1}{12} that part-by-part suggests.

  • Trap Subtracting mixed numbers by taking the smaller fraction from the larger regardless of which one you started with.

    Fix Borrow instead. 5142235\tfrac{1}{4} - 2\tfrac{2}{3} is 27122\tfrac{7}{12}; taking 312\tfrac{3}{12} from 812\tfrac{8}{12} the wrong way round returns 35123\tfrac{5}{12}, too big by 56\tfrac{5}{6}.

  • Trap Assuming a product must be larger than its factors and a quotient smaller than what it divides.

    Fix Read ×\times as "of" and ÷\div as "how many fit". A product of two fractions each between 00 and 11 falls below both, as 34×25=310\frac{3}{4} \times \frac{2}{5} = \frac{3}{10} does, while 6÷34=86 \div \frac{3}{4} = 8 grows.

Chapter test Questions from across the chapter