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Chapter Review · a rapid pre-test review (speedrun)

Data, Counting, and Probability: Chapter Review

A rapid review before the test: the chapter's vocabulary and notation, every formula with the conditions to use it, the standard problem types step by step, and the traps that cost points.

Vocabulary and notation

Outlier
A value far from the rest. It drags the mean toward itself but barely moves the median, which is why the two disagree.
Frequency table
Pairs each category (what was counted) with its frequency (how many). The frequencies add to the total number of data values.
Key (pictograph)
The note saying how many one symbol stands for. Without it a row of symbols has no value.
Double bar graph
Two bars per category, one per group, with a legend naming which is which. Pick the category, then read that group's bar.
Experiment, outcome, sample space
An experiment has an uncertain result, each possible result is an outcome, and the sample space lists them all: a die gives {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\}.
Event
Any collection of outcomes from the sample space. "Roll an even number" is the event {2,4,6}\{2, 4, 6\}.
Equally likely
Every outcome has the same chance. Promised by fair, equal sectors, or at random, and it must be checked, never assumed.
Law of large numbers
As trials pile up, the experimental probability settles toward the theoretical value. It promises nothing about one short run.

Formulas and theorems

  • Mean

    mean=sumn,sum=n×mean\text{mean} = \frac{\text{sum}}{n}, \qquad \text{sum} = n \times \text{mean}

    Use when Numeric data, n1n \ge 1. The second form answers a missing-value question; as a check, deviations from the mean always add to 00.

  • Median

    n odd: middle valuen even: mean of the middle two\begin{gathered} n \text{ odd: middle value} \\ n \text{ even: mean of the middle two} \end{gathered}

    Use when SORT least to greatest first; the middle is at position n+12\tfrac{n+1}{2}. With an even nn the median can fall between data points and need not be in the list.

    e.g. 2,4,7,102, 4, 7, 10: median 4+72=5.5\tfrac{4 + 7}{2} = 5.5.

  • Mode

    mode=the most frequent value\text{mode} = \text{the most frequent value}

    Use when Counting only, no arithmetic. SEVERAL modes when values tie, NONE when every value occurs equally often. Also the only summary here that works on non-numeric data.

    e.g. 1,1,5,8,81, 1, 5, 8, 8 has two modes, 11 and 88; 3,6,93, 6, 9 has none.

  • Range

    range=maximumminimum\text{range} = \text{maximum} - \text{minimum}

    Use when Measures SPREAD, not center, so it says nothing about where the data sits. Never divided by the count, never negative.

    e.g. 3,5,8,2-3, 5, -8, 2: range 5(8)=135 - (-8) = 13.

  • Pictograph value

    value=symbols×key\text{value} = \text{symbols} \times \text{key}

    Use when A symbol is never worth 11 by default, and a partial symbol is that fraction of the key.

  • Circle graph: count and angle

    count=percent100×totalangle=counttotal×360\begin{gathered} \text{count} = \frac{\text{percent}}{100} \times \text{total} \\ \text{angle} = \frac{\text{count}}{\text{total}} \times 360^\circ \end{gathered}
    A slice's share of the total is its share of 360 degreesA circle with a narrow shaded wedge running clockwise from the top. The two straight edges of the wedge meet at the centre dot, where a small arc between them carries the label 54 degrees. To the right of the circle three short lines of text read 15 percent slice, 36 of 240, and 54 degrees of 360 degrees, one under the other.54°15% slice36 of 24054° of 360°
    Text description

    A circle graph whose shaded wedge is the 15 percent slice, worth 36 of 240, drawn with a 54 degree angle at the centre.

    Use when Slices must be parts of ONE whole, and their percents add to 100%100\%, which finds a missing slice. A count needs the total stated.

    e.g. A 15%15\% slice of 240240: 3636 students, drawn as 5454^\circ.

  • Multiplication principle

    (stage 1 choices)×(stage 2 choices)×\begin{gathered} (\text{stage 1 choices}) \\ \times (\text{stage 2 choices}) \times \cdots \end{gathered}
    Every stage one choice reopens the whole stage two list, so the counts multiplyA tree drawn left to right. A single dot at the left has three lines running to three dots in a middle column, labelled stage 1 with 3 shirts. Each middle dot has two lines running to highlighted dots in a right column, labelled stage 2 with 2 hats each, so the right column holds six dots. A label below reads 3 times 2 equals 6 outfits.stage 1: 3 shirtsstage 2: 2 hats each3 × 2 = 6 outfits
    Text description

    A tree for choosing an outfit. Its single start splits into 3 stage one branches, one for each shirt, and each of those splits into 2 stage two branches, one for each hat, ending in 6 highlighted end dots: the 6 possible outfits.

    Use when Stages must be INDEPENDENT: each later stage offers the same choices whatever came before. If an earlier pick changes a later count, adjust it before multiplying.

    e.g. 33 flavors, 22 sauces, 44 toppings: 3×2×4=243 \times 2 \times 4 = 24 sundaes.

  • Addition principle

    (group 1 size)+(group 2 size)+(\text{group 1 size}) + (\text{group 2 size}) + \cdots

    Use when Exactly ONE item is chosen, and the groups must not overlap, or a shared item is counted twice. "Or" adds, "and then" multiplies.

  • Arrangements

    n×(n1)×(n2)×(r factors for r positions)\begin{gathered} n \times (n - 1) \times (n - 2) \times \cdots \\ (r \text{ factors for } r \text{ positions}) \end{gathered}

    Use when Distinct items, no reuse, and ORDER matters, so ABC and CBA are different. Stop after one factor per position; filling all nn runs the product down to 11.

  • Repeated choices

    c×c××cn stages=cn\underbrace{c \times c \times \cdots \times c}_{n \text{ stages}} = c^{\,n}

    Use when Repetition allowed, so every stage keeps all cc choices. The base counts the choices at one stage, the exponent the stages.

  • Theoretical probability

    P(E)=favorable outcomestotal equally likely outcomesP(E) = \frac{\text{favorable outcomes}}{\text{total equally likely outcomes}}

    Use when Valid only when the outcomes are EQUALLY LIKELY (fair, equal sectors, at random). "Favorable" means counted, not good. Simplify the fraction.

  • The probability scale

    0P(E)10 \le P(E) \le 1

    Use when P=0P = 0 is impossible, P=1P = 1 certain. Write any value as a fraction, decimal, or percent. A result off the scale means the counts are wrong.

    e.g. 14=0.25=25%\tfrac{1}{4} = 0.25 = 25\%; rolling a 77 on a standard die has P=0P = 0.

  • Complement rule

    P(not A)=1P(A)P(\text{not } A) = 1 - P(A)
    The two pieces fill one bar, so the complement is what is left of 1One horizontal bar split by a vertical divider into a short left piece labelled P of A and a long shaded right piece labelled P of not A. Below the bar a measuring line with a tick at each end spans the full width and is labelled total equals 1.P(A)P(not A)total = 1
    Text description

    One bar of total 1 split into a short piece for the probability of A and a shaded remainder for the probability of not A.

    Use when Holds for any event in any sample space. All the outcome probabilities add to 11: SUBTRACT from 11, do not flip the fraction.

  • Experimental probability

    Pexp(E)=times E happenedtrialsP_{\text{exp}}(E) = \frac{\text{times } E \text{ happened}}{\text{trials}}

    Use when Comes from recorded data, so it needs no equally-likely assumption. A short run will not match the theoretical value exactly.

    e.g. 2727 heads in 5050 flips: 2750=0.54\tfrac{27}{50} = 0.54, against a theoretical 0.50.5.

Problem types, step by step

Find the mean, median, mode, and range

  1. Mean: add every value, divide by how many there are.
  2. Median: sort, then the middle value, or the mean of the middle two for an even count.
  3. Mode: tally, take the most frequent; report all ties, or none if nothing repeats.
  4. Range: largest minus smallest.

e.g. 5,8,3,8,65, 8, 3, 8, 6: mean 66; sorted 3,5,6,8,83, 5, 6, 8, 8 gives median 66, mode 88, range 55.

Find a missing value from a given mean

  1. Multiply the target mean by the number of values: the total the set must reach.
  2. Add the values you have.
  3. Subtract; the difference is the missing value.
  4. Check by recomputing the mean.

e.g. 78,85,9078, 85, 90, target mean 8585 over 44 tests: 4×85=3404 \times 85 = 340, and 340253=87340 - 253 = 87.

Decide which center to report, or predict an outlier's effect

  1. Scan the sorted data for a value far from the rest.
  2. With one, the mean is pulled toward it and the median is not, so report the median.
  3. Without one, the two land close and either serves.
  4. "Which changes more": any change to the total moves the mean, the median only if the ordering's middle moves.

e.g. Incomes 30,35,40,45,100030, 35, 40, 45, 1000: mean 230230, median 4040.

Read an exact value off a bar graph, pictograph, or line graph

  1. Bar: follow the bar's end across to the scale and read the number, not the height.
  2. Pictograph: count the symbols, a partial one as its fraction, times the key.
  3. Line: read the point across to the scale; a rising segment is an increase, falling a decrease, flat no change.
  4. For a difference, total, or net change, read each value first, then combine.

e.g. Bars at 2020 and 1414: October is 2014=620 - 14 = 6 more, not 3434.

Answer a circle-graph question

  1. Read the labelled percent on each slice you need.
  2. Missing slice: subtract the labelled percents from 100%100\%.
  3. Count: multiply the slice's percent by the stated total.
  4. Comparison: convert both slices to counts, then subtract.

e.g. 20%20\%, 15%15\%, 30%30\% leave 35%35\%, which is 105105 of 300300 students.

Choose the display that fits the question

  1. Separate categories, compared by amount: bar graph or pictograph.
  2. One quantity over ordered times: line graph (its segments need an ordered axis to mean anything).
  3. One whole split into parts: circle graph.
  4. Exact numbers rather than a picture: the frequency table.

e.g. A day split into sleep, school, and play: a circle graph.

Count the possibilities for a choice problem

  1. A sequence of choices ("this AND then that"), or one choice from separate groups ("EITHER here OR there")?
  2. A sequence multiplies the stage counts; non-overlapping groups add their sizes.
  3. Repeats allowed at a stage keep its full count; no repeats shrink it by one.
  4. Mixed problem: multiply inside each type, then add the types.
  5. Verify a small count by listing in a fixed order.

e.g. Sandwich lunch 4×3=124 \times 3 = 12 or salad lunch 5×3=155 \times 3 = 15: 12+15=2712 + 15 = 27.

Count arrangements, including a restricted position

  1. Write a blank for each position.
  2. Fill the RESTRICTED position first, counting only the items allowed there.
  3. Fill the rest in turn, dropping by one each time when items cannot repeat, steady when they can.
  4. Multiply the blanks.

e.g. 33-digit numbers with all digits different: 9×9×8=6489 \times 9 \times 8 = 648, the leading digit barred from 00.

Find the probability of an event

  1. Confirm the outcomes are equally likely: fair, equal, at random.
  2. Count the whole sample space, multiplying stage counts for a multi-stage experiment; a second draw without replacement leaves one fewer item.
  3. Count the favorable outcomes, listing or gridding them if needed.
  4. Divide, simplify, and convert the form if asked.

e.g. Two fair dice summing to 77: 66 favorable of 6×6=366 \times 6 = 36, so P=16P = \tfrac{1}{6}.

Use the complement for "not" and "at least one"

  1. Name the opposite event: "at least one head" flips to "no heads at all".
  2. Find that opposite event's probability, usually the easier count.
  3. Subtract it from 11.
  4. Check against the 00 to 11 scale, or by direct count when the numbers are small.

e.g. Three fair coins: P(no heads)=18P(\text{no heads}) = \tfrac{1}{8}, so P(at least one head)=78P(\text{at least one head}) = \tfrac{7}{8}.

Exam traps

  • Trap Reading the median off the list as handed to you, so 5,9,15, 9, 1 appears to have median 99.

    Fix Sort first: 1,5,91, 5, 9 has median 55. "Middle" always means middle in ORDER.

  • Trap Adding when the problem is a sequence of choices, or multiplying when it is one single choice.

    Fix 55 books and 33 games give 5×3=155 \times 3 = 15 book-and-game pairs but only 5+3=85 + 3 = 8 single prizes.

  • Trap Treating any two outcomes as 12\tfrac{1}{2}, so "rain or no rain" becomes a 50%50\% chance of rain.

    Fix Counting gives a probability only when the outcomes are equally likely; otherwise you need data.

  • Trap Shrinking the choices where repeats are allowed, so a 44-digit code counts as 10×9×8×7=504010 \times 9 \times 8 \times 7 = 5040.

    Fix A digit may repeat, so every position keeps all 1010: 104=10,00010^4 = 10{,}000. Shrink only when an item is used up.

  • Trap Swapping the base and the exponent, writing 55 coin flips as 525^2.

    Fix The base counts the choices at one stage, the exponent the stages: 25=322^5 = 32, not 52=255^2 = 25.

  • Trap Reporting a circle graph's 40%40\% slice as 4040 people.

    Fix A slice is a share: 40100×300=120\tfrac{40}{100} \times 300 = 120. Percent and count agree only when the total is 100100.

  • Trap Comparing bar heights on a value axis that does not start at 00.

    Fix Read the numbers off the scale: bars at 5252 and 4848 differ by 44, not by a factor of two. A truncated axis breaks the length-to-value proportion.

  • Trap Taking a complement by flipping the fraction, turning P(A)=16P(A) = \tfrac{1}{6} into 61\tfrac{6}{1} or 15\tfrac{1}{5}.

    Fix Subtract from 11: 116=561 - \tfrac{1}{6} = \tfrac{5}{6}, matching the 55 faces that are not the one.

  • Trap Counting pictograph symbols as the value, or rounding a half symbol up.

    Fix Multiply by the key, a partial symbol getting that fraction of it: with a key of 1010, four and a half symbols are 4545, not 4.54.5 or 5050.

  • Trap Reading a cause, or a value past the last plotted point, out of a graph.

    Fix A graph reports only what was measured: ice cream sales and sunburns rising together shows no causation, and a line says nothing past its last point.

Chapter test Questions from across the chapter