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Chapter Review · a rapid pre-test review (speedrun)

Geometry Basics: Chapter Review

A rapid review before the test: the chapter's vocabulary and notation, every formula with the conditions to use it, the standard problem types step by step, and the traps that cost points.

Vocabulary and notation

Line, segment, ray
AB\overleftrightarrow{AB}: no endpoints, forever both ways. AB\overline{AB}: two endpoints, the only one of the three with a length. AB\overrightarrow{AB}: one endpoint, AA, named first.
Plane, collinear
A plane is an endless flat surface. Points on one straight line are collinear; two different lines meet at most once, so lines that do cross share exactly one point.
Angle ABC\angle ABC
Two rays from a shared vertex, the middle letter naming it. Size is the turn between the arms, in degrees, however long they are drawn.
Adjacent angles, linear pair
Adjacent: sharing a vertex and a side, not overlapping. A linear pair is two adjacent angles whose outer sides form a straight line.
m\ell \parallel m and m\ell \perp m
Parallel lines never meet. Perpendicular lines cross at a right angle, which makes all four angles there 9090^\circ.
Transversal
A line crossing two or more others. Its angle facts hold only when the crossed lines are parallel.
Perpendicular height hh
Distance from a base to the opposite side or vertex, at a right angle. Never a slanted side; on an obtuse triangle it can land outside.
Circle parts
Radius rr: center to edge, all equal. Chord: joins two edge points. Diameter dd: the longest chord, through the center. Arc: part of the boundary. Circumference: all of it.
Prism, cylinder, face, net
Prism: two identical bases, unchanging cross-section. Cylinder: the same with a circular base. Face: one flat surface. Net: the solid unfolded flat.
Perimeter, area, volume, surface area
Distance around a flat shape; unit squares covering a region; unit cubes filling a solid; total area of every face. Units: linear, square, cubic, square.
Ordered pair (x,y)(x, y)
Across first (xx, right positive), then up (yy), so (3,2)(2,3)(3, 2) \neq (2, 3). The origin (0,0)(0, 0) is where the axes cross.

Formulas and theorems

  • Angle types by measure

    acute<90=right90<obtuse<180=straight180<reflex<360\begin{gathered} \text{acute} < 90^\circ = \text{right} \\ 90^\circ < \text{obtuse} < 180^\circ = \text{straight} \\ 180^\circ < \text{reflex} < 360^\circ \end{gathered}

    Use when Degrees, full turn 360360^\circ. Any opening between 00^\circ and 180180^\circ has a reflex partner completing 360360^\circ.

    e.g. The reflex angle beside 115115^\circ is 245245^\circ.

  • Complement and supplement of xx

    complement=90xsupplement=180x\begin{gathered} \text{complement} = 90^\circ - x \\ \text{supplement} = 180^\circ - x \end{gathered}
    A complement completes a right angle; a supplement completes a straight lineTwo small diagrams. In the left one a horizontal ray and a vertical ray leave the same vertex, and a third ray lies between them; a plain arc near the vertex marks the angle x from the horizontal ray up to that third ray, and a highlighted arc marks the remainder of the right angle as 90 degrees minus x. In the right one a straight line passes through a vertex with a single ray rising from it; a plain arc marks x on the right side and a highlighted arc marks the remainder of the straight angle as 180 degrees minus x.x90°−xcomplementaryx180°−xsupplementary
    Text description

    A right angle split into x and its complement, beside a straight angle split into x and its supplement.

    Use when A complement needs x<90x < 90^\circ, a supplement x<180x < 180^\circ, or the result is zero or negative. The angles need not touch.

    e.g. 6262^\circ: complement 2828^\circ, supplement 118118^\circ.

  • Angle sums: line and full turn

    linear pair=180around a point=360\begin{gathered} \text{linear pair} = 180^\circ \\ \text{around a point} = 360^\circ \end{gathered}

    Use when The angles must share the vertex and fill the line or turn with no gaps or overlaps; a linear pair is therefore supplementary.

    e.g. 110110^\circ, 135135^\circ, xx fill a turn: x=115x = 115^\circ.

  • Vertical angles are equal

    1=3,2=4\angle 1 = \angle 3, \qquad \angle 2 = \angle 4

    Use when Only the opposite pairs where two straight lines cross, sharing the vertex and no side; a neighbour is supplementary to it instead.

  • Parallel lines cut by a transversal

    corresponding: equalalternate interior: equalco-interior: sum 180\begin{gathered} \text{corresponding: equal} \\ \text{alternate interior: equal} \\ \text{co-interior: sum } 180^\circ \end{gathered}
    Corresponding angles are equal, and so are alternate interior anglesTwo horizontal lines drawn one above the other, each marked with a chevron to show they are parallel, crossed by a single slanted line running from upper left to lower right. At the upper crossing a highlighted arc labelled a sits below the line and right of the slanted cutter, and at the lower crossing a highlighted arc labelled a sits in that same corner. A plain arc labelled b sits below the upper line and left of the cutter, and a second plain arc labelled b sits above the lower line and right of the cutter, so the two b angles lie between the parallel lines on opposite sides of the cutter.aabb
    Text description

    Two parallel lines cut by a transversal, with the corresponding pair of angles marked a and the alternate interior pair marked b.

    Use when All three need the crossed lines PARALLEL. Corresponding: matching positions. Alternate interior: opposite sides, between the lines. Co-interior: same side, between them.

    e.g. An interior 7878^\circ gives alternate interior 7878^\circ and co-interior 102102^\circ.

  • Rectangle and square

    P=2(l+w),A=lwPsquare=4s,Asquare=s2\begin{gathered} P = 2(l + w), \quad A = lw \\ P_{\text{square}} = 4s, \quad A_{\text{square}} = s^2 \end{gathered}

    Use when Four right angles; the area counts ww rows of ll unit squares, and any other polygon's perimeter is the sum of its sides. Put lengths in ONE unit first: squaring a length squares the factor, so 1 m2=10,000 cm21 \text{ m}^2 = 10{,}000 \text{ cm}^2.

  • Area of a parallelogram

    A=b×hA = b \times h

    Use when hh is the perpendicular distance between base bb and the side opposite, never the slanted side, which is longer.

  • Area of a triangle

    A=12bhA = \tfrac{1}{2} \, b \, h

    Use when Any side may be base bb if hh is the perpendicular height to THAT base, and bhbh is the same whichever is chosen; on an obtuse triangle that height can fall outside the triangle.

  • Area of a trapezoid

    A=12(a+b)h=a+b2×hA = \tfrac{1}{2}(a + b)\,h = \frac{a + b}{2} \times h

    Use when aa and bb must be the PARALLEL sides and hh perpendicular between them; slanted sides never enter. Average the two, then multiply.

  • Circumference, and d=2rd = 2r

    d=2r,C=πd=2πrd = 2r, \qquad C = \pi d = 2\pi r

    Use when Halve a diameter whenever a formula wants rr. Circumference is a length, and it goes round a WHOLE circle: a part-circle boundary adds its straight edges.

  • Pi

    π=Cd3.14\pi = \frac{C}{d} \approx 3.14

    Use when The same for every circle, all circles being scaled copies. Computing with 3.143.14 or 227\tfrac{22}{7} makes any circle answer approximate: write \approx.

  • Area of a circle and a semicircle

    A=πr2Asemi=12πr2Psemi=πr+2r\begin{gathered} A = \pi r^2 \\ A_{\text{semi}} = \tfrac{1}{2}\pi r^2 \\ P_{\text{semi}} = \pi r + 2r \end{gathered}

    Use when The RADIUS, squared before multiplying by π\pi; halve a given diameter first, or the answer is four times too large. A semicircle's area halves; its boundary does not, the cut exposing the straight diameter 2r2r.

  • Volume of a prism or a cylinder

    V=B×hVbox=lwh,Vcube=s3Vcylinder=πr2h\begin{gathered} V = B \times h \\ V_{\text{box}} = lwh, \quad V_{\text{cube}} = s^3 \\ V_{\text{cylinder}} = \pi r^2 h \end{gathered}

    Use when BB is one base's area and hh the perpendicular distance to the identical opposite base, so the cross-section must never change; a cylinder takes the RADIUS. Cubic units; cones, pyramids, and spheres are not covered.

    e.g. Triangular end 77 by 44, length 66: B=14B = 14, so V=84 m3V = 84 \text{ m}^3.

  • Surface area from a net

    Sbox=2(lw+lh+wh)Scube=6s2Scylinder=2πr2+2πrh\begin{gathered} S_{\text{box}} = 2(lw + lh + wh) \\ S_{\text{cube}} = 6s^2 \\ S_{\text{cylinder}} = 2\pi r^2 + 2\pi r h \end{gathered}

    Use when Six box faces in three opposite pairs, so each term doubles; the cylinder's 2πr22\pi r^2 is its two caps and 2πrh2\pi r h its side unrolled to width 2πr2\pi r. An open box or tube drops the faces it lacks. SQUARE units, not cubic.

  • Quadrant sign patterns

    (+,+)II (,+)III (,)IV (+,)\begin{gathered} \text{I } (+,+) \qquad \text{II } (-,+) \\ \text{III } (-,-) \qquad \text{IV } (+,-) \end{gathered}
    The four quadrants, numbered counterclockwise, and the signs in eachA horizontal x-axis and a vertical y-axis crossing at a marked origin. Each of the four regions carries a roman numeral above a highlighted pair of signs: upper right I with plus and plus, upper left II with minus and plus, lower left III with minus and minus, lower right IV with plus and minus.I(+, +)II(−, +)III(−, −)IV(+, −)xy
    Text description

    Coordinate axes with the four quadrants numbered counterclockwise from the upper right, each labelled with the signs of its coordinates.

    Use when Counterclockwise from the upper right. A coordinate of 00 puts the point ON an axis and in NO quadrant, the origin included.

  • Horizontal and vertical distance

    horizontal x2x1vertical y2y1\begin{gathered} \text{horizontal } |x_2 - x_1| \\ \text{vertical } |y_2 - y_1| \end{gathered}

    Use when Only when the OTHER coordinate matches, putting the segment on a gridline; the absolute value keeps the length positive either way.

  • Reflecting a point across an axis

    over x-axis: (x,y)(x,y)over y-axis: (x,y)(x,y)\begin{gathered} \text{over } x\text{-axis: } (x, y) \to (x, -y) \\ \text{over } y\text{-axis: } (x, y) \to (-x, y) \end{gathered}
    Reflecting across the x-axis keeps x and flips the sign of yA vertical y-axis and a highlighted horizontal x-axis. A dot above the highlighted axis is labelled 3 comma 2. A dashed vertical segment runs from it straight down through the axis to a highlighted dot labelled 3 comma minus 2, and a slanted tick on each half of that segment shows the point and its image sit the same distance from the axis, at the same horizontal position.(3, 2)(3, −2)x-axisy
    Text description

    A point three right and two up, reflected across the x-axis to the point the same distance below with its y-sign flipped.

    Use when One sign flips: crossing the xx-axis flips the yy-sign, crossing the yy-axis flips the xx-sign. A point already on the axis crossed stays put.

Problem types, step by step

Find an unknown angle from a stated relationship

  1. Name the relationship: complementary (9090^\circ), linear pair (180180^\circ), vertical (equal), or filling a point (360360^\circ).
  2. Write it as an equation, with xx the unknown or the multiplier in an expression.
  3. Solve, then check the pieces total 9090^\circ, 180180^\circ, or 360360^\circ.

e.g. (3x+12)(3x + 12)^\circ with xx^\circ in a linear pair: 4x+12=1804x + 12 = 180, so x=42x = 42.

Find an angle using parallel lines and a transversal

  1. Confirm the crossed lines are marked parallel, or none of the rules applies.
  2. Classify the pair: matching positions (corresponding), opposite sides between the lines (alternate interior), same side between them (co-interior).
  3. Set them equal, or their sum to 180180^\circ for co-interior, and solve.

e.g. Corresponding (4x)(4x)^\circ and (x+60)(x + 60)^\circ: x=20x = 20, so each is 8080^\circ.

Find an area, or work back from one to a missing length

  1. Take the shape's formula: lwlw, bhbh, 12bh\tfrac{1}{2}bh, or 12(a+b)h\tfrac{1}{2}(a + b)h.
  2. Pick the base (or the two parallel sides) and the PERPENDICULAR height, discarding any slanted side given as a distractor.
  3. Substitute, every length in one unit, and report square units.
  4. Working back to a missing length, undo instead: multiply by 22 if the formula carries a 12\tfrac{1}{2}, then divide.

e.g. A triangle of area 54 cm254 \text{ cm}^2 on base 1212 cm: h=2(54)12=9h = \dfrac{2(54)}{12} = 9 cm.

Find the area of a composite figure

  1. Cut it into non-overlapping rectangles, triangles, and part-circles, or read it as one full shape with a piece removed.
  2. Recover an unlabelled side by subtracting the labelled ones running the same direction.
  3. Add the pieces, or subtract the removed piece, then split a second way as a check.

e.g. A 99 by 77 rectangle less a 44 by 33 corner: 6312=5163 - 12 = 51.

Find the circumference or the area of a circle

  1. Convert to the radius with r=d2r = \tfrac{d}{2} if a diameter was given.
  2. Around uses C=2πrC = 2\pi r; inside uses A=πr2A = \pi r^2, squaring rr BEFORE multiplying by π\pi.
  3. Halve for a semicircle, adding the diameter if its whole boundary is wanted, and report linear units for a length, square units for an area, with \approx.

e.g. d=20d = 20 cm: r=10r = 10, so C62.8C \approx 62.8 cm and A314 cm2A \approx 314 \text{ cm}^2.

Find the volume or the surface area of a solid

  1. Volume: find the base area BB (lwlw, 12bh\tfrac{1}{2}bh_{\triangle}, or πr2\pi r^2), multiply by the distance between the two bases, and report cubic units.
  2. Surface area of a box: compute lwlw, lhlh, and whwh, add, and double.
  3. Surface area of a cylinder: add the caps 2πr22\pi r^2 to the unrolled side 2πrh2\pi r h; an open box or tube drops the faces it lacks, and the answer is square units.

e.g. A closed cube of edge 55 cm: V=125 cm3V = 125 \text{ cm}^3 but S=6(25)=150 cm2S = 6(25) = 150 \text{ cm}^2.

Plot, read, and measure on the coordinate grid

  1. To plot, from the origin go across by the first number, then up or down by the second; negatives mean left and down.
  2. To read, drop to the xx-axis for the first coordinate and slide to the yy-axis for the second, then name the quadrant from the two signs.
  3. For an axis-aligned rectangle, subtract the xx-coordinates of a horizontal side for the length and the yy-coordinates of a vertical side for the width, then apply P=2(l+w)P = 2(l + w) and A=lwA = lw.

e.g. (3,5)(-3, 5) is 33 left, 55 up, Quadrant II; corners (2,1)(-2, 1), (5,1)(5, 1), (5,6)(5, 6) give P=24P = 24, A=35A = 35.

Exam traps

  • Trap Reporting a measurement in the wrong kind of unit, or converting 1 m21 \text{ m}^2 to 100 cm2100 \text{ cm}^2.

    Fix Count the factors of length the formula multiplies: one linear, two square, three cubic. Squaring a length squares the conversion factor, so it is 10,000 cm210{,}000 \text{ cm}^2.

  • Trap Putting the diameter where the radius belongs, so d=12d = 12 cm gives A3.14×122=452.16A \approx 3.14 \times 12^2 = 452.16.

    Fix Halve first: r=6r = 6 and A113.04 cm2A \approx 113.04 \text{ cm}^2. Squaring turns the factor of 22 into 44, so the slip is always four times too big.

  • Trap Answering a distance-around question with πr2\pi r^2, or a space-inside question with 2πr2\pi r.

    Fix Circumference carries rr once, area carries rr squared. At r=10r = 10: about 62.862.8 around, 314314 inside.

  • Trap Multiplying by the slanted side of a parallelogram, triangle, or trapezoid.

    Fix Only the perpendicular height counts: base 99, slant 66, height 55 gives 45 cm245 \text{ cm}^2, not 5454.

  • Trap Dropping the 12\tfrac{1}{2} from the triangle formula, or using a+ba + b instead of a+b2\tfrac{a+b}{2} for a trapezoid.

    Fix Either doubles the area: each shape is half of a parallelogram made from two copies of it.

  • Trap Calling a semicircle's boundary half the circumference.

    Fix The cut exposes a straight diameter, so P=πr+2rP = \pi r + 2r: at r=4r = 4, about 20.5620.56 cm, not 12.5612.56.

  • Trap Charging a closed can only its unrolled side, 2πrh2\pi r h.

    Fix Add both caps: S=2πr2+2πrhS = 2\pi r^2 + 2\pi r h. The side alone is a tube open at each end.

  • Trap Subtracting coordinates to get the distance between two diagonal points.

    Fix It works only when the points SHARE a coordinate; (1,2)(1, 2) and (4,6)(4, 6) are neither 33 nor 44 apart.

Chapter test Questions from across the chapter