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Proportions

Learning goals

  • State a proportion as two equal ratios
  • Test two ratios by reducing both to lowest terms
  • Cross-multiply, and show why the diagonal products must match
  • Find a missing amount by scaling or by cross-multiplying
  • Set both ratios up in the same order, units included

What a proportion is

A proportion is a statement that two ratios are equal. From the last two lessons you know that 3:63 : 6 is the same comparison as 1:21 : 2. That is because dividing both parts of 3:63 : 6 by 33 lands on 1:21 : 2. Writing that equality down is a proportion:

1:2=3:6.1 : 2 = 3 : 6.

Because a ratio can always be written as a fraction, the same proportion is usually written with two equal fractions. That fraction form is the one we will work in:

12=36.\frac{1}{2} = \frac{3}{6}.

Read it as ”11 is to 22 as 33 is to 66.” A proportion is true only when the two ratios really are equivalent. If they are not equivalent, the statement is simply false, the same way 4=54 = 5 is false.

Telling whether two ratios are in proportion

Since the two sides are just fractions, deciding whether a proportion is true is the same job as deciding whether two fractions are equal. You already have two ways to do that from the Fractions chapter, and both work here.

Start with 6:86 : 8 and 9:129 : 12. The ratio 6:86 : 8 reduces to 3:43 : 4 (divide both parts by 22), and 9:129 : 12 also reduces to 3:43 : 4 (divide both parts by 33). They share the same simplest form, so

68=912\frac{6}{8} = \frac{9}{12}

is a true proportion. That is the first test: simplify each ratio, then see whether the two land on the same lowest terms.

The second test scales one ratio to match the other. Multiplying both parts of 6:86 : 8 by 1.51.5 gives 6×1.5=96 \times 1.5 = 9 and 8×1.5=128 \times 1.5 = 12, which is the second ratio exactly. Whenever a single factor carries the whole of one ratio onto the other, the two are equivalent.

Worked example 1 Is 410=615\frac{4}{10} = \frac{6}{15} a true proportion?

Test it by simplifying each ratio to lowest terms.

The greatest common factor of 44 and 1010 is 22, so

410=4÷210÷2=25.\frac{4}{10} = \frac{4 \div 2}{10 \div 2} = \frac{2}{5}.

The greatest common factor of 66 and 1515 is 33, so

615=6÷315÷3=25.\frac{6}{15} = \frac{6 \div 3}{15 \div 3} = \frac{2}{5}.

Both ratios reduce to 25\frac{2}{5}, so they are equal. The proportion 410=615\frac{4}{10} = \frac{6}{15} is true.

Cross-multiplication, and why it works

Simplifying is easy when the numbers are friendly, but it gets fiddly when they are not. There is a test that works on any two ratios and needs only multiplication.

Simplifying already showed that 68=912\frac{6}{8} = \frac{9}{12} is true. Multiply along each diagonal instead, the top of one side times the bottom of the other:

6×12=72and8×9=72.6 \times 12 = 72 \qquad \text{and} \qquad 8 \times 9 = 72.

The two diagonal products are equal. They are called the cross-products. The picture shows where that name comes from. It draws the proportion 12=36\frac{1}{2} = \frac{3}{6}, with the two products running along its diagonals and crossing in the middle.

Cross-products of the proportion 1/2 = 3/6Two fractions one-half and three-sixths with an equals sign. Diagonal lines join 1 to 6 and 2 to 3, and both diagonal products equal 6.12=361 x 6 = 6 and 2 x 3 = 6
The cross-products of a proportion are the two diagonal products. The proportion is true exactly when they are equal, here 1 times 6 equals 2 times 3.

The match is not luck. Over the shared denominator 8×12=968 \times 12 = 96, the ratio 68\frac{6}{8} becomes 7296\frac{72}{96} and 912\frac{9}{12} becomes 7296\frac{72}{96}. Those two numerators are the diagonal products, and two equal ratios over one denominator must have equal numerators.

For any proportion, the same two diagonals give the same test:

ab=cda×d  and  b×c.\frac{a}{b} = \frac{c}{d} \qquad\longrightarrow\qquad a \times d \ \text{ and } \ b \times c.

The proportion is true exactly when these two cross-products are equal, a×d=b×ca \times d = b \times c. The test carries a condition you have to check: bb and dd must not be zero. Their product b×db \times d is then not zero either. That nonzero product is the common denominator each ratio gets rewritten over, which is where the rule comes from.

Why equal ratios have equal cross-products#

Run the argument on numbers first. The proportion 79=1418\frac{7}{9} = \frac{14}{18} is true, since dividing both parts of 1418\frac{14}{18} by 22 gives 79\frac{7}{9}. Compare the two fractions by rewriting them over a common denominator, exactly as you did when adding fractions. A denominator that both 99 and 1818 divide into is their product, 9×18=1629 \times 18 = 162, so rewrite each fraction with that bottom:

79=7×189×18=126162,1418=14×918×9=126162.\frac{7}{9} = \frac{7 \times 18}{9 \times 18} = \frac{126}{162}, \qquad \frac{14}{18} = \frac{14 \times 9}{18 \times 9} = \frac{126}{162}.

The two numerators came out as 7×18=1267 \times 18 = 126 and 14×9=12614 \times 9 = 126, which are the cross-products of the proportion. They had to agree, because the fractions were equal to start with and now sit over one denominator.

Nothing there depended on the numbers chosen. Start with any true proportion ab=cd\frac{a}{b} = \frac{c}{d}, where bb and dd must not be zero. Their product b×db \times d is then not zero either, so it can serve as a denominator. To turn ab\frac{a}{b} into a fraction over b×db \times d, multiply its top and bottom by dd. To turn cd\frac{c}{d} into a fraction over b×db \times d, multiply its top and bottom by bb:

ab=a×db×d,cd=c×bd×b.\frac{a}{b} = \frac{a \times d}{b \times d}, \qquad \frac{c}{d} = \frac{c \times b}{d \times b}.

The order of the factors does not change the product, so d×bd \times b is the same as b×db \times d. Two fractions with the same denominator are equal exactly when their numerators are equal. Since the fractions were equal to begin with, the numerators must match:

a×d=c×b.a \times d = c \times b.

The argument also runs in reverse. If the cross-products are equal, the two rewritten fractions have equal numerators over the same denominator. That makes the two fractions equal, so the proportion is true.

Worked example 2 Use cross-products to test 37=1228\frac{3}{7} = \frac{12}{28}

Multiply along each diagonal and compare the two products.

The first cross-product is the top-left times the bottom-right:

3×28=84.3 \times 28 = 84.

The second cross-product is the bottom-left times the top-right:

7×12=84.7 \times 12 = 84.

The two cross-products are both 8484, so they are equal. That means 37=1228\frac{3}{7} = \frac{12}{28} is a true proportion. (You can double-check by simplifying: 1228\frac{12}{28} divides by 44 to give 37\frac{3}{7}.)

Check your understanding

Are the ratios 58\frac{5}{8} and 1524\frac{15}{24} in proportion?

Answer choices

Finding a missing amount

The real power of a proportion is that you can know three of the four numbers and find the fourth. That holds for the positive amounts this lesson works with, such as cups, miles and dollars. This is the everyday use: you know a recipe ratio and one ingredient amount, and you want the other. Set the two ratios equal, keeping the same kind of quantity in matching positions, then find the missing number with arithmetic you already have.

Both ratios must list their quantities in the same order. If the left ratio is cups of water over scoops of powder, the right ratio must also be cups of water over scoops of powder. Mixing the order (water over scoops on one side, scoops over water on the other) builds a false proportion and gives a wrong answer.

Method 1: scale the ratio

If one ratio’s known part is a whole-number multiple of the other’s, the fastest route is the equivalent-ratio scaling from the Ratios lesson. Find the scale factor from the pair you know, then apply that same factor to the other part.

Worked example 3 Scale to fill in the blank: 25=?20\frac{2}{5} = \frac{?}{20}

Look at the denominators, the pair you fully know: the bottom went from 55 to 2020. Find the scale factor by dividing:

20÷5=4.20 \div 5 = 4.

A proportion stays true when you scale both parts of a ratio by the same number. So multiply the top by that same factor of 44:

25=2×45×4=820.\frac{2}{5} = \frac{2 \times 4}{5 \times 4} = \frac{8}{20}.

The missing number is 88. This is the equivalent-fractions move from earlier chapters: 25\frac{2}{5} and 820\frac{8}{20} are the same ratio written in larger terms.

Method 2: cross-multiply, then divide

Scaling is neat, but it only stays simple when the known parts divide evenly. When they do not, cross-multiplication handles any proportion. The idea uses the rule you just proved: in a true proportion the cross-products are equal. So multiply the two numbers on the diagonal you fully know, which gives the value of the other cross-product. Then divide that value by the remaining known number to recover the missing one.

Take a missing numerator, and call the unknown amount nn. That nn is a variable standing for the amount you are finding, and here you solve for it by multiplying and dividing:

n6=104.\frac{n}{6} = \frac{10}{4}.

The cross-products of a true proportion are equal, so n×4n \times 4 must equal 6×106 \times 10. The right side is a product of two known numbers:

6×10=60.6 \times 10 = 60.

So nn multiplied by 44 gives 6060. The number that does that is found by dividing 6060 by 44, since division undoes multiplication:

n=60÷4=15.n = 60 \div 4 = 15.

The missing amount is 1515. Every proportion with one blank yields to the same two steps. Multiply the diagonal you know, then divide by the number diagonally opposite the blank.

Worked example 4 A recipe: cross-multiply and divide

A punch recipe calls for juice and soda in the ratio 33 cups of juice to 44 cups of soda. You pour in 1818 cups of juice. How many cups of soda keep the same taste?

Set up the proportion with juice on top and soda on the bottom on both sides, so the matching quantities line up. Let ss stand for the unknown cups of soda:

3 cups of juice4 cups of soda=18 cups of juices cups of soda.\frac{3 \text{ cups of juice}}{4 \text{ cups of soda}} = \frac{18 \text{ cups of juice}}{s \text{ cups of soda}}.

The diagonal you fully know is 44 and 1818, so multiply them to get that cross-product:

4×18=72.4 \times 18 = 72.

The other cross-product is 3×s3 \times s, and in a true proportion the two are equal, so 3×s3 \times s is 7272. Divide by the number diagonally opposite the blank, which is 33:

s=72÷3=24.s = 72 \div 3 = 24.

You need 2424 cups of soda. Check it by simplifying the finished proportion: 1824\frac{18}{24} divides by 66 to give 34\frac{3}{4}, which matches the recipe ratio, so the amounts are in proportion.

Check your understanding

Find the missing number: 73=n12\frac{7}{3} = \frac{n}{12}.

Answer choices

Proportions in the real world

Most proportion problems arrive as a word problem, and the work is in the setup. The reliable habit is to write a sentence ratio first, with its units. Then build the second ratio in the same order and put the blank where the unknown belongs.

Worked example 5 A map scale

On a map, 22 centimeters represents 5050 real kilometers. Two towns are 77 centimeters apart on the map. How far apart are they in real life?

Write the scale as a ratio of map distance to real distance, and keep that same order on both sides. Let dd be the real distance in kilometers:

2 cm50 km=7 cmd km.\frac{2 \text{ cm}}{50 \text{ km}} = \frac{7 \text{ cm}}{d \text{ km}}.

Multiply the diagonal you know, 5050 and 77:

50×7=350.50 \times 7 = 350.

That equals the other cross-product, 2×d2 \times d, so 2×d2 \times d is 350350. Divide by the 22 next to the blank:

d=350÷2=175.d = 350 \div 2 = 175.

The towns are 175175 kilometers apart. Keeping map centimeters over real kilometers on both sides is what made the setup correct; flipping one side would have given a nonsense distance.

Worked example 6 Predict from a steady speed

A car travels at a steady speed and covers 150150 miles in 33 hours. At the same speed, how far does it go in 77 hours?

Steady speed means the ratio of miles to hours stays the same, so it is a proportion. Write miles over hours on both sides, with mm for the unknown miles:

150 mi3 hr=m mi7 hr.\frac{150 \text{ mi}}{3 \text{ hr}} = \frac{m \text{ mi}}{7 \text{ hr}}.

The known diagonal is 150150 and 77:

150×7=1050.150 \times 7 = 1050.

This equals the other cross-product 3×m3 \times m, so divide by the 33 diagonally opposite the blank:

m=1050÷3=350.m = 1050 \div 3 = 350.

The car covers 350350 miles in 77 hours. You could also find the unit rate first, 150÷3=50150 \div 3 = 50 miles per hour, then multiply by 77 to get the same 350350. A proportion is the unit-rate idea written as two equal ratios.

Check your understanding

If 44 notebooks cost 1010 dollars, how much do 1010 notebooks cost at the same price?

Answer choices

Common mistakes

Practice

Multiple Choice Questions (MCQ)

Progressively harder sets of questions. Each opens on its own page.

Free Response Questions (FRQ)

Longer questions in parts, to be worked out on paper. Progressive hints, the answer on its own so you can check yourself and try again, then the full worked solution, plus a rubric to mark your own work against.

Free response Work it out on paper 5 questions Start →
More practice (optional)

Extra sets, as hard as the Challenge set. Each one opens on its own page.

More resources (optional)

Other explanations of this lesson, if you want a second take.

A bit of history (Optional)

How do you measure a pyramid? You cannot climb it, and no rope will run up a slope of stone to the point.

The story goes that a Greek trader named Thales did it in Egypt, around 600 BCE. His tools were a stick and the sun. He pushed the stick upright into the sand and waited. When the stick’s own shadow grew as long as the stick, he had the pyramid’s shadow measured. At that hour the shadow of anything upright is its height, so the length on the ground was the answer.

Later tellings have him doing it at any hour of the day, which needs the full idea. The stick is to its shadow as the pyramid is to its shadow. Three of those four lengths can be paced out on the sand. The fourth is the one nobody could reach.

That is exactly this lesson, twenty-six centuries early. Write the two ratios in the same order, multiply the diagonal you know, and divide by the number facing the blank.