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Square Roots

Learning goals

  • Undo squaring to find the side of a square from its area
  • Explain why the radical sign returns only the non-negative root
  • Read off the roots of perfect squares up to 144144
  • Pull a perfect-square factor out with ab=ab\sqrt{ab} = \sqrt{a}\sqrt{b} for non-negative aa and bb
  • Trap an imperfect root between neighboring perfect squares
  • Say why 2\sqrt{2} is irrational and best left exact

Squaring, and undoing it

Squaring a number means multiplying it by itself. The results, starting from 11, are the perfect squares:

12=1,22=4,32=9,42=16,52=25,62=36,1^2 = 1, \quad 2^2 = 4, \quad 3^2 = 9, \quad 4^2 = 16, \quad 5^2 = 25, \quad 6^2 = 36, \quad \ldots

A perfect square is any whole number you can reach by squaring a positive whole number, so 1,4,9,16,25,36,49,64,81,1001, 4, 9, 16, 25, 36, 49, 64, 81, 100 are the first ten of them. The square root of a number asks the reverse question. Given a number, what do you square to get it? The square root of 3636 is 66, because 62=366^2 = 36. The square root of 100100 is 1010, because 102=10010^2 = 100.

We write a square root with the radical sign x\sqrt{\phantom{x}}. The number tucked under it is called the radicand. So

25=5means52=25,\sqrt{25} = 5 \quad\text{means}\quad 5^2 = 25,

read aloud as “the square root of twenty-five is five.” Squaring and square-rooting are inverse operations: on numbers that are zero or more, each one undoes the other. Square 55 to get 2525, then take the square root of 2525 and you are back to 55. Starting from a negative number the round trip does not bring it back. Squaring 5-5 gives 2525, and the square root of 2525 is 55, not 5-5. In general the square root of x2x^2 is the size of xx, which means xx with any minus sign dropped.

Squaring and the square root are inverse operationsThe number 5 maps to 25 by squaring, and 25 maps back to 5 by taking the square root.525square (raise to the 2nd power)square root (find the side)
Squaring sends 5 to 25; the square root sends 25 back to 5. The two operations undo each other.

Because the radical undoes the square, the two cancel when you stack them. Start from 72\sqrt{7^2}: the radical hands back the number that was squared, so 72=7\sqrt{7^2} = 7. You never need the middle step of working out that 727^2 is 4949 and then rooting 4949 instead. Stacking them in the other order lands in the same place, since (49)2=72=49\left(\sqrt{49}\right)^2 = 7^2 = 49. So for any non-negative number aa,

a2=aand(a)2=a.\sqrt{a^2} = a \qquad\text{and}\qquad \left(\sqrt{a}\right)^2 = a.

Why the root is the non-negative one

There is a subtlety hiding in the question “what squares to 2525?” The obvious answer is 55. But 5-5 also works, because a negative times a negative is positive:

52=25and(5)2=(5)×(5)=25.5^2 = 25 \qquad\text{and}\qquad (-5)^2 = (-5)\times(-5) = 25.

So two different numbers, 55 and 5-5, both square to 2525. If the radical sign returned both, then 25\sqrt{25} would not name a single number, and you could not safely write it inside a calculation. To keep the square root a single, well-defined value, mathematicians make a choice: the radical sign always returns the non-negative root. This chosen value is called the principal square root.

Why a\sqrt{a} is defined as the non-negative root#

Start with 3636 and ask which numbers square to give it. One of them is 66, since 62=366^2 = 36, and its opposite works just as well:

(6)2=(6)×(6)=36.(-6)^2 = (-6)\times(-6) = 36.

So 3636 has two square roots, 66 and 6-6, one positive and one negative. That is a problem for notation: a symbol standing for 66 and 6-6 at the same time could not be used in an equation. You would never know which value was meant. The fix is to single out one of the pair by a fixed rule. So 36\sqrt{36} is defined to mean 66, the member that is not negative. The other root is still available, written separately as 36=6-\sqrt{36} = -6.

Nothing in that argument depended on the number being 3636. Take any positive number aa. If some number xx satisfies x2=ax^2 = a, then its opposite also works, because

(x)2=(x)×(x)=x2=a.(-x)^2 = (-x)\times(-x) = x^2 = a.

The solutions again come in a matched pair, so we define a\sqrt{a} to be the member that is zero or positive. With that rule the symbol names exactly one number every time, and the negative solution is written as a-\sqrt{a} when it is wanted.

The one number whose root needs no choice is 00 itself: since 02=00^2 = 0, we have 0=0\sqrt{0} = 0.

Check your understanding

What is the principal (non-negative) square root 81\sqrt{81}?

Answer choices

Roots of perfect squares

When the radicand is a perfect square, the root is a whole number, and you find it by recognizing which number was squared. It pays to know the first several perfect squares by sight, because then their roots come for free:

nn112233445566778899101011111212
n2n^2114499161625253636494964648181100100121121144144

Reading the table from the bottom row up gives you the square root directly. Since 144144 sits under 1212, you know 144=12\sqrt{144} = 12. Since 4949 sits under 77, you know 49=7\sqrt{49} = 7.

In the figure below you set the two sides of a rectangle, and the readout counts the unit squares it holds.

Make the width and the height equal and you have built a square, so its area is one side multiplied by itself. Step that square up from 22 by 22 and you will generate the start of the table above (44, then 99, 1616, 2525, 3636). In each of those squares, the side length is the root of the area. Then break the equality on purpose: set the rectangle 99 wide and 33 tall, and its area of 2727 lands between two perfect squares. Those squares are 2525 and 3636, and that trapping is exactly how this lesson later estimates a root that is not a whole number.

Why the side of a square is the root of its area

A rectangle 3 units wide and 3 units tall. Area 9 square units. The sides are equal, so this is a square and its side 3 is the square root of 9. A rectangle drawn on a grid of unit squares, inside a dashed boundary showing how large it can grow. Use the controls below the figure to change either dimension and watch for the settings where the sides match and the area is a perfect square. 3 3
Width Height

A rectangle 3 units wide and 3 units tall. Area 9 square units. The sides are equal, so this is a square and its side 3 is the square root of 9.

A rectangle drawn on unit squares, with the count of those squares reported as its area. Whenever the two sides are equal the shape is a square, so its area is a perfect square and the side length is the root of that area.

Worked example 1 Evaluate 64\sqrt{64} and 121\sqrt{121}

For each one, find the whole number that squares to the radicand.

For 64\sqrt{64}, search the perfect squares for 6464. Since 8×8=648 \times 8 = 64,

64=8.\sqrt{64} = 8.

For 121\sqrt{121}, since 11×11=12111 \times 11 = 121,

121=11.\sqrt{121} = 11.

Squaring each answer lands back on its radicand: 82=648^2 = 64 and 112=12111^2 = 121, both correct.

The product of two perfect squares is itself a perfect square, and its root is the product of the roots. For instance 400=20\sqrt{400} = 20 because 400=4×100400 = 4 \times 100 and 4×100=2×10=20\sqrt{4} \times \sqrt{100} = 2 \times 10 = 20.

The product rule for square roots

Square roots of a product can be split apart. For non-negative numbers aa and bb,

a×b=a×b.\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}.

This is true because squaring the right-hand side returns a×ba \times b. So the right-hand side is the non-negative number whose square is a×ba \times b, which is exactly what a×b\sqrt{a \times b} means.

Why ab=ab\sqrt{ab} = \sqrt{a}\,\sqrt{b} for non-negative aa and bb#

Take the radicands 99 and 4949 first. Their roots are 33 and 77, so the product of the roots is 2121, and squaring that product puts both radicands back:

212=(3×7)×(3×7)=3×3×7×7=9×49=441.21^2 = (3\times7)\times(3\times7) = 3\times3\times7\times7 = 9\times49 = 441.

So 2121 is a number that is not negative and squares to 441441. The symbol 441\sqrt{441} means exactly that, the non-negative number whose square is 441441, and only one such number can fit. So 441=21\sqrt{441} = 21, and since 441=9×49441 = 9\times49 that says 9×49=9×49\sqrt{9\times49} = \sqrt{9}\times\sqrt{49}.

The only thing that argument used was the squaring, not the particular radicands. Let aa and bb be zero or positive, so that a\sqrt{a} and b\sqrt{b} both exist and are non-negative. Look at the product a×b\sqrt{a}\times\sqrt{b} and square it. Multiplication can be reordered freely, so

(a×b)2=a×a×b×b=(a)2×(b)2=a×b.\left(\sqrt{a}\times\sqrt{b}\right)^2 = \sqrt{a}\times\sqrt{a}\times\sqrt{b}\times\sqrt{b} = \left(\sqrt{a}\right)^2 \times \left(\sqrt{b}\right)^2 = a \times b.

So a×b\sqrt{a}\times\sqrt{b} is a number that squares to a×ba \times b. It is also non-negative, because a product of two non-negative numbers is non-negative. But the non-negative number whose square is a×ba \times b is precisely what the symbol a×b\sqrt{a \times b} stands for. Two non-negative numbers with the same square must be equal, so

a×b=a×b.\sqrt{a \times b} = \sqrt{a}\times\sqrt{b}.

Division splits the same way: ab=ab\sqrt{\tfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}, provided aa is zero or more and bb is greater than zero. The same squaring argument carries it, since (ab)2=ab\left(\dfrac{\sqrt{a}}{\sqrt{b}}\right)^2 = \dfrac{a}{b}. So a quotient of square roots combines or splits just like a product.

This rule lets you simplify a root by pulling out any perfect-square factor hiding inside the radicand. The trick is to split the radicand into a perfect square times whatever is left.

Worked example 2 Simplify 12\sqrt{12}

The number 1212 is not a perfect square, but it contains the perfect-square factor 44, since 12=4×312 = 4 \times 3. Split the radical with the product rule:

12=4×3=4×3.\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4}\times\sqrt{3}.

Now 4=2\sqrt{4} = 2 is a whole number, while 3\sqrt{3} has no perfect-square factor to pull out, so it stays as it is:

12=23.\sqrt{12} = 2\sqrt{3}.

The form 232\sqrt{3} is considered simpler because the largest perfect square has been taken out from under the radical. Always pull out the largest perfect-square factor. Had you used 12=1×1212 = 1 \times 12 you would make no progress, since 11 is a perfect square but removing it changes nothing.

Check your understanding

Simplify 18\sqrt{18} by pulling out the largest perfect-square factor.

Answer choices

Estimating roots that are not whole numbers

Most radicands are not perfect squares, so their roots are not whole numbers. You can still pin a root down closely by trapping it between the two perfect squares it falls between. Take 10\sqrt{10}. The perfect squares on either side of 1010 are 99 and 1616:

9<10<16.9 < 10 < 16.

Taking the square root of all three keeps the order, because a bigger number has a bigger root:

9<10<16,that is3<10<4.\sqrt{9} < \sqrt{10} < \sqrt{16}, \qquad\text{that is}\qquad 3 < \sqrt{10} < 4.

You can say more: since 1010 is much closer to 99 than to 1616, its root sits close to 33, just a little above it. A trial check pins it down, because 3.22=10.243.2^2 = 10.24 is already slightly over 1010, so 10\sqrt{10} is a bit under 3.23.2, around 3.163.16.

Trapping the square root of 10 between 3 and 4A number line from 3 to 4. The left tick at 3 is the square root of 9, the right tick at 4 is the square root of 16, and the square root of 10 is marked just to the right of 3.3root of 94root of 16root of 10
The root of 10 lies between the roots of the neighboring perfect squares, 9 and 16, so between 3 and 4, and close to 3 because 10 is near 9.

The method is general: to estimate any square root, find the nearest perfect square below the radicand and the nearest one above it. The root lies between their two whole-number roots, and it leans toward whichever perfect square the radicand is closer to.

Worked example 3 Between which two whole numbers does 50\sqrt{50} lie?

Hunt for the perfect squares that bracket 5050. Counting up the squares, 49=7249 = 7^2 sits just below 5050, and 64=8264 = 8^2 is the next one above:

49<50<64.49 < 50 < 64.

Take the square root across the inequality, which preserves the order:

49<50<64,so7<50<8.\sqrt{49} < \sqrt{50} < \sqrt{64}, \qquad\text{so}\qquad 7 < \sqrt{50} < 8.

So 50\sqrt{50} lies between 77 and 88. Because 5050 is only just past 4949, the root is very close to 77 (in fact about 7.077.07).

Check your understanding

Between which two consecutive whole numbers does 30\sqrt{30} lie?

Answer choices

Why most square roots are irrational

When you estimate 10\sqrt{10} you can keep refining: 3.13.1, then 3.163.16, then 3.1623.162, and the decimal never settles and never falls into a repeating pattern. A square root of a whole number that is not a perfect square is an irrational number. Its decimal expansion runs on forever without ever repeating, so it can never be written exactly as a fraction or as a terminating decimal.

You met this idea when fractions and decimals were compared. A fraction always turns into a decimal that either stops or repeats, while an irrational number does neither. Numbers like 2=1.41421356\sqrt{2} = 1.41421356\ldots and 3=1.7320508\sqrt{3} = 1.7320508\ldots are the classic examples. The impossibility can be proved, as the Greeks first did for 2\sqrt{2} (the history below tells that story). This is why we usually leave such a root in its exact radical form, writing 2\sqrt{2} rather than a rounded decimal.

Common mistakes

Practice

Multiple Choice Questions (MCQ)

Progressively harder sets of questions. Each opens on its own page.

Free Response Questions (FRQ)

Longer questions in parts, to be worked out on paper. Progressive hints, the answer on its own so you can check yourself and try again, then the full worked solution, plus a rubric to mark your own work against.

Free response Work it out on paper 5 questions Start →
More practice (optional)

Extra sets, as hard as the Challenge set. Each one opens on its own page.

More resources (optional)

Other explanations of this lesson, if you want a second take.

A bit of history (Optional)

Draw a square one unit wide and rule in its diagonal. You can see that line and measure it, so it clearly has a length. Writing that length as a fraction turns out to be impossible. So does writing it as a decimal that ends.

The school of Pythagoras, a Greek teacher from twenty-five centuries ago, held that every length was a ratio of two whole numbers. One of them proved the diagonal is not. The trouble is not sloppy measuring. No fraction at all equals 2\sqrt{2}, and no finer ruler will change that.

The discovery is said to have shaken the school badly. Legend has the man who told it drowned at sea. The story is almost surely made up. The unease behind it was real, because an ordinary line had escaped their arithmetic.

That is why a root is left standing under the radical sign. The decimal 1.411.41 is a shade too small, so it is never quite the number you want. The exact length of that diagonal is 2\sqrt{2}, and the radical sign is how you write it without rounding.