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Perimeter and Area

Learning goals

  • Add the side lengths for perimeter, and count unit squares for area
  • Derive the parallelogram area by sliding a right triangle across
  • Halve a parallelogram to get the triangle area 12bh\tfrac{1}{2}bh
  • Average the parallel sides of a trapezoid, then multiply by the height
  • Use the perpendicular height, never the slant side
  • Split a composite figure into pieces whose areas you know

Perimeter: the distance around

The perimeter of a shape is the total distance around its boundary. For any polygon (a shape with straight sides) there is nothing to memorize: walk around the edge and add up the side lengths. If a triangle has sides 55 cm, 66 cm, and 77 cm, its perimeter is

P=5+6+7=18 cm.P = 5 + 6 + 7 = 18 \text{ cm}.

Because perimeter is a sum of lengths, it is itself a length. So perimeter is measured in linear units like centimetres or metres, never in square units. That single fact keeps perimeter and area from ever being confused.

When a shape has equal or repeated sides, the sum collapses into a shortcut. A rectangle has two sides of length ll and two of width ww, so

P=l+w+l+w=2l+2w=2(l+w).P = l + w + l + w = 2l + 2w = 2(l + w).

A square is a rectangle whose four sides are all the same length ss, so the sum is just ss four times:

P=s+s+s+s=4s.P = s + s + s + s = 4s.

These are not new rules, only the side-adding rule written compactly for a shape whose sides repeat.

A rectangle 8 cm long and 5 cm wide. Its perimeter adds all four sides: 8 + 5 + 8 + 5 = 26 cm, the same as 2(8 + 5). A rectangle 8 cm wide and 5 cm tall. 8 cm 5 cm
A rectangle 8 cm long and 5 cm wide. Its perimeter adds all four sides: 8 + 5 + 8 + 5 = 26 cm, the same as 2(8 + 5).

Area: counting unit squares

Area measures how much flat space a shape covers. To measure it we need a fixed unit, and the natural choice is a unit square: a square one unit long on every side. A square one centimetre on each side has an area of one square centimetre, written 1 cm21 \text{ cm}^2. The area of any region is simply the number of unit squares it takes to tile the region with no gaps and no overlaps.

This is why area is always measured in square units. A length is measured by laying a ruler along a line; an area is measured by laying unit squares across a surface. A surface needs two directions to cover it, and that is exactly what the little raised 22 in cm2\text{cm}^2 records.

A rectangle 5 cm wide and 3 cm tall, tiled by unit squares. Counting them gives 15 squares, so the area is 15 cm². A rectangle 5 units wide and 3 units tall, divided into 15 unit squares. 1 cm²
A rectangle 5 cm wide and 3 cm tall, tiled by unit squares. Counting them gives 15 squares, so the area is 15 cm².

Area of a rectangle

Counting squares one at a time would be slow for a large shape, so we look for a pattern. Tile a rectangle that is 55 units wide and 33 units tall with unit squares, as in the figure above. The squares fall into a neat array: 33 rows, each holding 55 squares. The total is then a multiplication, not a long count:

3 rows×5 squares per row=15 squares.3 \text{ rows} \times 5 \text{ squares per row} = 15 \text{ squares}.

That is the whole idea behind the rectangle formula. The width tells you how many squares sit in each row, and the height tells you how many rows there are. So multiplying the two numbers counts every square exactly once.

Why the area of a rectangle is length times width#

Take a rectangle whose length is ll units and whose width is ww units, with ll and ww whole numbers. Lay unit squares inside it starting from one corner. Each horizontal row stretches the full length of the rectangle, so each row holds exactly ll squares. The rows stack up the full width of the rectangle, and since each row is one unit tall, there are exactly ww rows.

Every unit square belongs to exactly one row and one column, with no gaps and no overlaps. So the total count is the number of rows times the number of squares in each row:

A=l+l++lw rows=w×l=l×w.A = \underbrace{l + l + \cdots + l}_{w \text{ rows}} = w \times l = l \times w.

So the area is the length times the width. The argument was stated for whole-number sides, because then the squares tile evenly. But the same formula A=l×wA = l \times w holds for any side lengths. Take a side of 2.52.5 units, for instance. You handle that side by cutting the unit squares into matching strips. The count of area still comes out to length times width.

So for a rectangle,

A=l×w.A = l \times w.

A square is a rectangle whose length and width are the same value ss, so its area is

A=s×s=s2.A = s \times s = s^2.

This is exactly why s2s^2 is read ”ss squared”. Raising a length to the second power is the area of the square built on that length. The exponent notation you met earlier and the geometry of a square are the same idea seen from two sides.

Perimeter and area are easy to mix up because both are called “how big it is”. The surest way to keep them apart is to change a rectangle and watch what each one does. Set the width and the height below, and both numbers are reported for the shape you built.

Rectangle explorer

A rectangle 5 units wide and 3 units tall. Perimeter 16 units. Area 15 square units. A rectangle drawn on a grid of unit squares, inside a dashed boundary showing how large it can grow. Use the controls below the figure to change either dimension and watch the perimeter and the area separately. 5 3
Width Height

A rectangle 5 units wide and 3 units tall. Perimeter 16 units. Area 15 square units.

A rectangle on a grid of unit squares. Set its width and its height, and read its perimeter and its area.

Here is the experiment worth doing. Build the 44 by 44 square: its perimeter is 1616 and its area is 1616. Now build the rectangle 77 wide and 11 tall: its perimeter is still 1616, but its area has fallen to 77. Same distance around, less than half the surface inside. Perimeter measures the fence and area measures the field, and knowing one tells you very little about the other.

Check your understanding

A rectangle is 99 m long and 44 m wide. What is its area?

Answer choices

Area of a parallelogram

A parallelogram is a four-sided shape whose opposite sides are parallel. It looks like a rectangle that has been pushed over so it leans. You might guess that its area is the product of two of its sides, but that is the classic trap. The figure shows why: the slanted side is longer than the straight-up distance across the shape, so multiplying by it would overcount.

The quantity that actually matters is the height, meaning the perpendicular distance between the base and the side opposite it. That distance is measured straight across at a right angle, not along the slanted edge. With the base called bb and that perpendicular height called hh, the area turns out to be exactly b×hb \times h. We can see why by turning the parallelogram into a rectangle.

Cut the right triangle off the left end (dashed) and slide it to the right end. The leaning parallelogram becomes a rectangle of base b and height h, so its area is b times h. A parallelogram with base b along the bottom and a dashed perpendicular height h from the top edge down to the base. b h
Cut the right triangle off the left end (dashed) and slide it to the right end. The leaning parallelogram becomes a rectangle of base b and height h, so its area is b times h.

Why the area of a parallelogram is base times height#

Start with the parallelogram sitting on its base bb. Drop a vertical line from the top-left corner straight down to the base. This cuts a right triangle off the left end of the parallelogram, and that vertical line is exactly the perpendicular height hh.

Now slide that triangle to the right, moving it across until its slanted edge lines up with the slanted right side of the parallelogram. Because opposite sides of a parallelogram are equal and parallel, the triangle fits the right end perfectly, with no gap and no overlap. The shape you are left with is a rectangle: its bottom is still the base bb, and its height is still the perpendicular height hh.

Cutting a piece off and moving it somewhere else never changes how much area a shape has. So the parallelogram and the rectangle cover exactly the same amount of space. The rectangle’s area is base times height, so the parallelogram’s area is the same:

A=b×h.A = b \times h.

The slanted side never enters the calculation. Only the base and the straight-across height do, which is why the perpendicular height is the measurement that counts.

So for a parallelogram,

A=b×h(h is the perpendicular height).A = b \times h \qquad (h \text{ is the perpendicular height}).

A rectangle is just a parallelogram that happens to stand up straight. In that case the height equals the vertical side, and the formula collapses back to A=l×wA = l \times w.

Area of a triangle

A triangle is half of a parallelogram, and that single observation hands us its area. Take any triangle, make an identical copy, turn the copy upside down, and fit the two together along a matching side. The two triangles snap into a parallelogram with the same base bb and the same perpendicular height hh as the original triangle.

A triangle and an upside-down copy of it (dashed) fit together into a parallelogram of base b and height h. The triangle is exactly half of that parallelogram. A triangle with base b along the bottom and a dashed perpendicular height h from the apex down to the base. b h
A triangle and an upside-down copy of it (dashed) fit together into a parallelogram of base b and height h. The triangle is exactly half of that parallelogram.

Why the area of a triangle is half the base times the height#

Begin with a triangle of base bb and perpendicular height hh. Make a second triangle identical to it. Rotate the copy by half a turn (180180^\circ) and place it against the original so that the two share a full side. The pair fits together into a parallelogram. Each pair of opposite sides is made of one original side and its equal copy. Opposite sides are therefore equal and parallel, which is exactly what makes the shape a parallelogram.

This parallelogram has the same base bb and the same perpendicular height hh as the triangle, so its area is b×hb \times h. The parallelogram is made of two copies of the triangle, equal in area, so each triangle is exactly half of it:

A=12×b×h.A = \frac{1}{2} \times b \times h.

Any side of the triangle can be chosen as the base, as long as hh is the perpendicular height drawn to that base. The product b×hb \times h comes out the same whichever side you pick, so the area is well defined.

So for a triangle,

A=12bh(h is the perpendicular height to the base b).A = \frac{1}{2} \, b \, h \qquad (h \text{ is the perpendicular height to the base } b).

The perpendicular-height warning matters even more for triangles than for parallelograms. The reason is that a triangle’s height often falls inside the shape and is not one of the three sides at all. You must use the straight-across height to the base, never the slanted side leaning up to the top corner.

Check your understanding

A triangle has a base of 1010 cm and a perpendicular height of 66 cm. What is its area?

Answer choices

Area of a trapezoid

A trapezoid is a four-sided shape with at least one pair of parallel sides. Call those two parallel sides aa and bb, and call the perpendicular distance between them the height hh. When the two parallel sides have different lengths the trapezoid is wider at one than the other, so neither length alone gives the area. What works is the average of the two parallel sides, multiplied by the height. Taking “at least one pair” rather than “exactly one pair” lets a parallelogram count as a special trapezoid whose two parallel sides are equal. You will see in a moment that the trapezoid formula then collapses neatly onto both the parallelogram formula and the triangle formula.

A trapezoid with parallel sides a (top) and b (bottom) and perpendicular height h between them. Its area is the average of the two parallel sides times the height. A trapezoid with parallel sides a on top and b on the bottom, and a dashed perpendicular height h between them. b a h
A trapezoid with parallel sides a (top) and b (bottom) and perpendicular height h between them. Its area is the average of the two parallel sides times the height.

Why the area of a trapezoid is the average of the parallel sides times the height#

Take the trapezoid with parallel sides aa and bb and height hh. Make an identical copy, turn it upside down, and set it beside the original so the two slanted sides meet. Just as with the triangle, the two copies fit together into a parallelogram, with no gaps and no overlaps.

Look at the base of that parallelogram. Along the bottom you have the long side bb of one trapezoid. Next to that long side comes the short side aa of the flipped copy. That ordering holds because the flip puts a short side next to a long side all the way along. So the parallelogram’s base is a+ba + b. Its height is still hh, the same perpendicular distance as before, so the parallelogram’s area is

(a+b)×h.(a + b) \times h.

That parallelogram is two copies of the trapezoid, so one trapezoid is half of it:

A=12(a+b)h.A = \frac{1}{2}(a + b)\, h.

Reading the formula as a+b2×h\dfrac{a + b}{2} \times h shows what it means: take the average of the two parallel sides, a+b2\dfrac{a + b}{2}, and multiply by the height. The trapezoid covers the same space as a rectangle whose width is that average length.

So for a trapezoid,

A=12(a+b)h=a+b2×h.A = \frac{1}{2}(a + b)\, h = \frac{a + b}{2} \times h.

This one formula quietly contains the others. If the two parallel sides are equal (a=ba = b), the trapezoid is a parallelogram and the formula gives 12(a+a)h=ah\tfrac{1}{2}(a + a)h = a h, matching the parallelogram rule. If the top side shrinks to nothing (a=0a = 0), the shape becomes a triangle and the formula gives 12(0+b)h=12bh\tfrac{1}{2}(0 + b)h = \tfrac{1}{2} b h, matching the triangle rule. Every area rule in this lesson is one idea seen at different settings.

Composite figures: cut into pieces you know

Many real shapes are not a single tidy rectangle or triangle, but you can almost always decompose them. Cut the figure into rectangles and triangles, find each piece’s area with the rules above, and then add the pieces together. Area is additive, so the area of the whole is the sum of the areas of the non-overlapping parts.

An L-shaped figure split by a dashed line into a tall left rectangle (6 by 9) and a short right rectangle (5 by 5). Add the two areas: 54 + 25 = 79 square metres. An L-shaped figure with labelled sides. A dashed line splits it into a taller left rectangle and a shorter right rectangle whose areas add to the whole. 11 m 9 m 6 m 4 m 5 m 5 m 6 × 9 5 × 5
An L-shaped figure split by a dashed line into a tall left rectangle (6 by 9) and a short right rectangle (5 by 5). Add the two areas: 54 + 25 = 79 square metres.

The L-shape above is split into a tall rectangle on the left and a short one on the right. The left piece is 6 m6 \text{ m} by 9 m9 \text{ m}, giving 54 m254 \text{ m}^2; the right piece is 5 m5 \text{ m} by 5 m5 \text{ m}, giving 25 m225 \text{ m}^2; together the figure covers 54+25=79 m254 + 25 = 79 \text{ m}^2. Splitting a different way, or subtracting the missing corner from a full rectangle, gives the same total, because the actual region covered has not changed.

A caution about units

Perimeter and area use different kinds of units, and mixing them up is the most common error in the whole topic. Perimeter is a length, so it is reported in linear units: cm, m, km. Area is a count of unit squares, so it is reported in square units: cm2\text{cm}^2, m2\text{m}^2, km2\text{km}^2. A number with no unit, or with the wrong unit, is not a complete answer.

Unit conversions deserve special care, because squaring a length squares the conversion factor too. There are 100100 centimetres in a metre, but a square metre is not 100100 square centimetres. A square metre is a square one metre on each side, which is 100 cm100 \text{ cm} by 100 cm100 \text{ cm}, so

1 m2=100×100=10,000 cm2.1 \text{ m}^2 = 100 \times 100 = 10{,}000 \text{ cm}^2.

Always convert lengths to the same unit before computing an area, and remember that the square unit grows by the conversion factor multiplied by itself.

Check your understanding

Which statement is correct?

Answer choices

Worked examples

Worked example 1 Perimeter and area of a rectangle

A rectangular garden is 1212 m long and 77 m wide. Find its perimeter and its area.

For the perimeter, add all four sides, using the rectangle shortcut P=2(l+w)P = 2(l + w):

P=2(12+7)=2×19=38 m.P = 2(12 + 7) = 2 \times 19 = 38 \text{ m}.

For the area, multiply length by width:

A=12×7=84 m2.A = 12 \times 7 = 84 \text{ m}^2.

So the garden needs 3838 m of fencing around the edge and covers 8484 square metres of ground. Notice the units: the perimeter is in metres, the area in square metres. That is because one is a length and the other a count of unit squares.

Worked example 2 Spotting the perpendicular height

A parallelogram has a base of 99 cm. Its slanted side is 66 cm, and the perpendicular height drawn straight down from the top edge to the base is 55 cm. Find its area.

The area of a parallelogram uses the perpendicular height, not the slanted side. The slanted side (66 cm) is given only to tempt you. Use the base and the perpendicular height:

A=b×h=9×5=45 cm2.A = b \times h = 9 \times 5 = 45 \text{ cm}^2.

Multiplying by the slanted 66 cm would give 54 cm254 \text{ cm}^2, which is wrong: it overcounts, because the slanted side is longer than the straight-across height. Always use the height measured at a right angle to the base.

Worked example 3 Area of a triangle

A triangle has a base of 1414 cm and a perpendicular height of 99 cm to that base. Find its area.

A triangle is half of a parallelogram with the same base and height, so its area is half the base times the height:

A=12×b×h=12×14×9.A = \frac{1}{2} \times b \times h = \frac{1}{2} \times 14 \times 9.

Multiply the base and height first, then take half:

A=12×126=63 cm2.A = \frac{1}{2} \times 126 = 63 \text{ cm}^2.

So the triangle covers 6363 square centimetres. Taking half of 1414 first (=7= 7) and then multiplying by 99 gives the same 6363, since multiplication can be grouped in either order.

Worked example 4 Area of a trapezoid

A trapezoid has parallel sides of 66 cm and 1010 cm, with a perpendicular height of 44 cm between them. Find its area.

Average the two parallel sides, then multiply by the height:

A=a+b2×h=6+102×4.A = \frac{a + b}{2} \times h = \frac{6 + 10}{2} \times 4.

The average of the parallel sides is

6+102=162=8 cm,\frac{6 + 10}{2} = \frac{16}{2} = 8 \text{ cm},

so the area is

A=8×4=32 cm2.A = 8 \times 4 = 32 \text{ cm}^2.

The trapezoid covers the same space as a rectangle 88 cm wide (the average width) and 44 cm tall.

Worked example 5 A composite figure

A room has the L-shape shown earlier. The outer rectangle is 1111 m wide and 99 m tall, with a 5 m5 \text{ m} by 4 m4 \text{ m} rectangle missing from the top-right corner. Find the floor area.

Split the L into two rectangles with a vertical cut. The left piece runs the full height and is 66 m wide (the 1111 m width less the 55 m notch):

Aleft=6×9=54 m2.A_{\text{left}} = 6 \times 9 = 54 \text{ m}^2.

The right piece is what remains on the right: 55 m wide and 55 m tall (the 99 m height less the 44 m notch):

Aright=5×5=25 m2.A_{\text{right}} = 5 \times 5 = 25 \text{ m}^2.

Add the non-overlapping pieces:

A=54+25=79 m2.A = 54 + 25 = 79 \text{ m}^2.

As a check, the full outer rectangle would be 11×9=99 m211 \times 9 = 99 \text{ m}^2, and the missing corner is 5×4=20 m25 \times 4 = 20 \text{ m}^2, so 9920=79 m299 - 20 = 79 \text{ m}^2. Cutting into pieces and subtracting the hole agree, as they must.

Check your understanding

A trapezoid has parallel sides of 55 m and 99 m and a perpendicular height of 66 m. What is its area?

Answer choices

Common mistakes

Practice

Multiple Choice Questions (MCQ)

Progressively harder sets of questions. Each opens on its own page.

Free Response Questions (FRQ)

Longer questions in parts, to be worked out on paper. Progressive hints, the answer on its own so you can check yourself and try again, then the full worked solution, plus a rubric to mark your own work against.

Free response Work it out on paper 5 questions Start →
More practice (optional)

Extra sets, as hard as the Challenge set. Each one opens on its own page.

More resources (optional)

Other explanations of this lesson, if you want a second take.

A bit of history (Optional)

How do you measure a field when nobody has written down a formula yet?

You measure it by work. In medieval England a farmer counted land in acres, and an acre was not a shape. It was the ground one man and a pair of oxen could plough in a single day.

That depends on the plough, so around the year 13001300 a royal statute settled the acre for good. It became a strip twenty-two yards wide and two hundred and twenty yards long. The long side had a name of its own, the furlong, meaning the length of a furrow.

Why so long and thin? Turning a heavy team of oxen was awkward, so a ploughman cut the longest furrows he could.

Consider what that shape costs. A square acre and a strip acre cover exactly the same ground. The strip needs almost twice as much fencing around its boundary. That is the experiment you ran on the rectangle in this lesson, turned around. Fixing the area still leaves the perimeter free to wander.