Ratios, Rates, and Percents: Chapter Test
20 multiple-choice questions and 10 core practice problems, drawn from across the chapter and mixed together.
Multiple choice
20 questions, 100 points in total, 5 points each. Answer in any order and change your mind as often as you like. When you submit, your answers lock and every question shows its worked solution.
Core practice
10 problems from across the chapter. Work on paper, use hints when you need them, and check the answer or the full solution when you are ready.
Difficulty: Core (core-course level)
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Problem 1 Survey share
A survey finds that of the households on a street own a bicycle. Write this share as a decimal and as a fraction in lowest terms.
- Hint 1
The percent sign is an instruction to divide the number in front of it by one hundred.
- Hint 2
Read the decimal's last place to write it as a fraction, then divide out the greatest common factor.
Answer
; .
Full solution
The percent sign divides by one hundred, which moves the decimal point two places to the left.
The last digit of is in the thousandths place, so the decimal is one hundred seventy-five thousandths.
The greatest common factor of and is , since and , so divide top and bottom by it.
As a check,
Answer
; .
Key idea
The percent sign divides by one hundred, and the decimal's place value then gives the fraction.
- Hint 1
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Problem 2 Sound playback
At a fixed playback setting, seconds of a recording takes seconds to play. How many seconds of the original recording are heard during seconds of playback?
- Hint 1
Keep original recording time and playback time in matching positions.
- Hint 2
Multiply the pair you know along a diagonal, then divide by the number facing the unknown.
Answer
seconds.
Full solution
Let be the original recording time in seconds.
Comparing original time with playback time on both sides gives
The playback time is not a whole-number multiple of , so multiply the known diagonal.
This product equals times , so divide by the facing the unknown.
The original recording heard is seconds.
As a check, both ratios give the same number of original seconds per playback second.
Answer
seconds.
Key idea
Keep both ratios in the same order, then check the missing term by dividing within each ratio: the two quotients must match.
- Hint 1
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Problem 3 Choir size
A choir has members this term, which is more than last term. How many members did it have last term?
- Hint 1
This term's count is a known percent of last term's count.
- Hint 2
Undo the increase by dividing by its multiplier.
Answer
members.
Full solution
The increase was thirty percent of last term's count, so this term's count is of it.
Let be last term's number of members.
The multiplier is not zero, so divide by it.
The choir had members last term.
As a check, thirty percent of sixty members is eighteen members, and .
Taking thirty percent off instead would give , which is wrong because the increase was measured against the smaller count from last term.
Answer
members.
Key idea
The amount before a percent increase comes from dividing the later amount by the multiplier, because the increase was measured against the earlier amount.
- Hint 1
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Problem 4 Exhibit preparation
An exhibit contains pictures, all either prints or drawings. The ratio of prints to drawings is . The staff removes of the prints for cleaning. How many prints remain in the exhibit?
- Hint 1
Find the number of prints before cleaning from their share of the exhibit.
- Hint 2
The cleaning share is taken from the prints, not from all the pictures.
Answer
prints.
Full solution
The ratio has sixteen parts, so one part contains
pictures.
Prints take seven parts.
Forty percent of the one hundred forty prints are removed.
The remaining print count is
As a check, the prints that stay are sixty percent of the prints, and
Answer
prints.
Key idea
Find a category count from its ratio before taking a percent of that category.
- Hint 1
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Problem 5 Workshop schedule
A cutter uses cord only while cutting, always at the same steady rate, and it uses cm of cord in minutes of cutting. A workshop lasts minutes, and cutting occupies of that time. How much cord does the cutter use during the workshop?
- Hint 1
Ask how much of the workshop is spent cutting.
- Hint 2
Scale the cutting rate by the cutting time rather than the full workshop time.
Answer
cm.
Full solution
The cutter uses
cm per minute.
Cutting occupies
minutes.
The cord used during those thirty minutes is
cm.
Thirty minutes is five times the observed six-minute interval, so the result also matches five times sixty-six centimeters.
Answer
cm.
Key idea
Apply a unit rate to the part of the total time during which that rate is active.
- Hint 1
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Problem 6 Fixing a plank
A cm plank is cut into two pieces, and the ratio of the shorter piece's length to the longer piece's length is . The longer piece is fixed to a wall with screws for every cm of its length. How many screws does the longer piece need?
- Hint 1
Find the length of the longer piece before counting its screws.
- Hint 2
Keep screws and length in the same order in both comparisons.
Answer
screws.
Full solution
The cut divides the plank into eleven ratio parts.
Each part measures
cm, so the longer piece measures
cm.
Let be the number of screws the longer piece needs.
Screws over length in cm is the same for the stated rule and for this piece.
The length is four times , so the screw count is four times .
As a check, reduces to .
Answer
screws.
Key idea
A length found by splitting a total can then be matched to a second quantity through a proportion.
- Hint 1
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Problem 7 Plumbing bill
A plumber charges 150 dollars for hours of work, at a steady hourly rate. A job takes hours. The bill then adds tax, with no other charges. What is the total bill?
- Hint 1
The charge for the job depends on how much one hour of work costs.
- Hint 2
Price the four hours of work first, then apply the multiplier for the tax.
Answer
261.60 dollars.
Full solution
In dollars per hour, the plumber's rate is
Four hours of work then cost, in dollars,
Tax adds nine percent of that charge, so the multiplier is .
The total bill is 261.60 dollars.
As a check, nine percent of 240 dollars is 21.60 dollars, and
Answer
261.60 dollars.
Key idea
Scale the unit rate to the whole job first, then apply the tax multiplier to that charge.
- Hint 1
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Problem 8 Marked rope
A rope is marked in two colors with no overlap: meters are blue and meters are red. The remaining meters are unmarked. Len says the marked parts make up about of the rope. Is Len right? Justify your answer.
- Hint 1
Decide which length Len has used as the whole.
- Hint 2
Compare the marked length with the whole length and write the result over one hundred.
Answer
No; the marked parts are of the rope.
Full solution
The marked length, in meters, is the blue and red parts together.
The whole rope, in meters, is the marked and unmarked lengths together.
The marked share of the whole rope is
which is , so Len is not right.
As a check, of meters is meters.
Len's figure comes from dividing by the unmarked length.
The unmarked meters is only one part of the rope, not the whole rope, so his figure compares one part with another part.
Answer
No; the marked parts are of the rope.
Key idea
A percent of a whole is found by dividing by that whole, not by another part.
- Hint 1
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Problem 9 Budget revision
A council sets aside of its budget for a project and for emergencies. It then increases the project's money by , taking the extra from the rest of the budget. The emergency money and the total budget stay fixed. A member says the two now use of the budget. Is the member right? What percent do they now use together?
- Hint 1
Ask what amount the is taken of, and compare it with the amount the other two percents are taken of.
- Hint 2
Update the project share before adding the unchanged emergency share.
Answer
No; together they use of the budget.
Full solution
The is taken of the project's money, not of the whole budget.
The project's money grows by a factor of , so its share of the fixed budget becomes
The emergency share stays at eight percent.
Both shares are now percents of the same total budget, so they add to
The member is wrong: that sum added a percent of the project's money to percents of the whole budget.
As a check, on a budget of 1000 dollars the project's 120 dollars grows to 150 dollars, and with the 80 dollars for emergencies that makes 230 dollars, which is of the budget.
Answer
No; together they use of the budget.
Key idea
Update a changing amount on its own base before combining its share with other shares of a fixed total.
- Hint 1
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Problem 10 Two orchards
Orchard B has more trees than Orchard A. In Orchard A, of the trees are in bloom, and in Orchard B, are. Ravi says that exactly of all the trees in the two orchards are in bloom, halfway between and . Is Ravi right? Explain.
- Hint 1
The two percents are taken of orchards of different sizes.
- Hint 2
Compare each orchard's percent with : which orchard is above that mark, which is below, and by how much of its own trees?
- Hint 3
Five percent of which orchard is the larger number of trees?
Answer
No; fewer than of all the trees are in bloom.
Full solution
Compared with of its trees, Orchard A has an extra amount equal to of its trees in bloom, and Orchard B is short by an amount equal to of its trees.
Thirty-five percent of all the trees is of every trees in Orchard A together with of every trees in Orchard B.
So the number in bloom is that amount, plus Orchard A's extra, minus Orchard B's shortfall.
Five percent of the larger Orchard B is a bigger amount than five percent of Orchard A, so the shortfall is bigger than the extra, and fewer than of all the trees are in bloom, whatever the two orchards' sizes are, as long as B is larger.
Ravi is not right.
For one example, with trees in Orchard A and in Orchard B, the trees in bloom number
and
which is of the trees, or .
Answer
No; fewer than of all the trees are in bloom.
Key idea
When two wholes of different sizes carry different percents, the percent of both together lies closer to the larger whole's percent, not halfway between them.
- Hint 1